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QUIZ 2:Current Electricity(#freetestseries) - JEE MCQ


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15 Questions MCQ Test - QUIZ 2:Current Electricity(#freetestseries)

QUIZ 2:Current Electricity(#freetestseries) for JEE 2024 is part of JEE preparation. The QUIZ 2:Current Electricity(#freetestseries) questions and answers have been prepared according to the JEE exam syllabus.The QUIZ 2:Current Electricity(#freetestseries) MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for QUIZ 2:Current Electricity(#freetestseries) below.
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QUIZ 2:Current Electricity(#freetestseries) - Question 1

Current of 4.8 amperes is flowing through a conductor. The number of electrons per second will be [CPMT 1986]

QUIZ 2:Current Electricity(#freetestseries) - Question 2

When the current i is flowing through a conductor, the drift velocity is v. If 2i current is flowed through the same metal but having double the area of cross-section, then the drift velocity will be

Detailed Solution for QUIZ 2:Current Electricity(#freetestseries) - Question 2

I=AneVd

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QUIZ 2:Current Electricity(#freetestseries) - Question 3

 When current flows through a conductor, then the order of drift velocity of electrons will be [CPMT 1986]

Detailed Solution for QUIZ 2:Current Electricity(#freetestseries) - Question 3

 

   Order of drift velocity 

=10-4m/sec=10-2cm/sec

QUIZ 2:Current Electricity(#freetestseries) - Question 4

Every atom makes one free electron in copper. If 1.1 ampere current is flowing in the wire of copper having 1 mm diameter, then the drift velocity (approx.) will be (Density of copper =9×103kgm-3 and atomic weight = 63) [CPMT 1989]

QUIZ 2:Current Electricity(#freetestseries) - Question 5

Which one is not the correct statement [NCERT 1978]

Detailed Solution for QUIZ 2:Current Electricity(#freetestseries) - Question 5

    Because 1 H.P. = 746 J/s = 746 watt

QUIZ 2:Current Electricity(#freetestseries) - Question 6

 If a 0.1 % increase in length due to stretching, the percentage increase in its resistance will be [MNR 1990; MP PMT 1996; UPSEAT 1999; MP PMT 2000]

QUIZ 2:Current Electricity(#freetestseries) - Question 7

The resistivity of iron is1×10-7ohm−m. The resistance of a iron wire of particular length and thickness is 1 ohm. If the length and the diameter of wire both are doubled, then the resistivity in ohm−m will be [CPMT 1983; DPMT 1999]

Detailed Solution for QUIZ 2:Current Electricity(#freetestseries) - Question 7

Because it is an intensive property

QUIZ 2:Current Electricity(#freetestseries) - Question 8

The temperature coefficient of resistance for a wire is 0.00125/∘C. At 300K its resistance is 1 ohm. The temperature at which the resistance becomes 2 ohm is [IIT 1980; MP PET 2002; KCET 2003; MP PMT 2001; Orissa JEE 2002]

QUIZ 2:Current Electricity(#freetestseries) - Question 9

The battery E has an e.m.f.of 2volt If the galvanometer Greads zero, then the value of the resistance X in ohm is [NCERT 1990; AIEEE 2005] 

QUIZ 2:Current Electricity(#freetestseries) - Question 10

The magnitude and direction of the current in the circuit shown will be [CPMT 1986, 88] 

QUIZ 2:Current Electricity(#freetestseries) - Question 11

 A cell of e.m.f. 1.5V having a finite internal resistance is connected to a load resistance of 2Ω. For maximum power transfer the internal resistance of the cell should be [BIT 1988]

Detailed Solution for QUIZ 2:Current Electricity(#freetestseries) - Question 11

   For maximum power, external resistance = internal resistance.

QUIZ 2:Current Electricity(#freetestseries) - Question 12

By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]

QUIZ 2:Current Electricity(#freetestseries) - Question 13

The e.m.f. of a cell is E volts and internal resistance is r ohm. The resistance in external circuit is alsor ohm. The p.d. across the cell will be [CPMT 1985; NCERT 1973]

Detailed Solution for QUIZ 2:Current Electricity(#freetestseries) - Question 13

 

    Since both the resistors are same, therefore potential difference 

=V+V=E

 Þ 

V=E/2

QUIZ 2:Current Electricity(#freetestseries) - Question 14

 Two cells, e.m.f. of each is E and internal resistance r are connected in parallel between the resistance R. The maximum energy given to the resistor will be, only when [MNR 1988; MP PET 2000; UPSEAT 2001]

Detailed Solution for QUIZ 2:Current Electricity(#freetestseries) - Question 14

We know that when two equal resistors are connected in parallel the equivalent resistance becomes half.
Also maximum power is delivered when load resistance = equivalent internal resistance.
Hence A is correct.

QUIZ 2:Current Electricity(#freetestseries) - Question 15

Kirchhoff's first law i.e. Σi=0 at a junction is based on the law of conservation of [CBSE PMT 1997; AIIMS 2000; MP PMT 2002; RPMT 2001; DPMT 2005]

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