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This mock test of QUIZ 2:Photoelectric Effect(#freetestseries) for JEE helps you for every JEE entrance exam.
This contains 15 Multiple Choice Questions for JEE QUIZ 2:Photoelectric Effect(#freetestseries) (mcq) to study with solutions a complete question bank.
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QUESTION: 1

The idea of matter waves was given by

Solution:

QUESTION: 2

Wave is associated with matter

Solution:

QUESTION: 3

The de-Broglie wavelength associated with the particle of mass m moving with velocity v is [CBSE PMT 1992]

Solution:

QUESTION: 4

A photon, an electron and a uranium nucleus all have the same wavelength. The one with the most energy [MP PMT 1992]

Solution:

A is the correct answer.

p = h/λ

p = √2mK

E ∝ 1/m

Since photon has minimum mass so it has maximum KE

QUESTION: 5

When the kinetic energy of an electron is increased, the wavelength of the associated wave will

Solution:

QUESTION: 6

If the de-Broglie wavelengths for a proton and for a α−particle are equal, then the ratio of their velocities will be [NCERT 1972]

Solution:

QUESTION: 7

A particle which has zero rest mass and non-zero energy and momentum must travel with a speed [MP PMT 1992; DPMT 2001; Kerala PMT 2004]

Solution:

QUESTION: 8

Dual nature of radiation is shown combinedly by [MP PET 1991]

Solution:

{Photoelectric effect →Particle nature Diffraction→Wave nature}Dual nature

QUESTION: 9

For the Bohr's first orbit of circumference 2πr, the de-Broglie wavelength of revolving electron will be [MP PMT 1987]

Solution:

QUESTION: 10

An electron of mass m when accelerated through a potential difference V has de-Broglie wavelength λ. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be [CBSE PMT 1995; EAMCET 2001; J & K CET 2004]

Solution:

QUESTION: 11

What will be the ratio of de-Broglie wavelengths of proton and α−particle of same energy [RPET 1991, 96; DCE 2002; Kerala PET 2005]

Solution:

QUESTION: 12

What is the de-Broglie wavelength of the α−particle accelerated through a potential difference V [RPMT 1996]

Solution:

QUESTION: 13

The energy that should be added to an electron, to reduce its de-Broglie wavelengths from 10^{-10} m to 0.5×10^{-10}m, will be [KCET (Engg./Med.) 2000]

Solution:

λ = h/√2mE

λ' = λ/2

λ'= h/√2mE'

then [λ/2]/λ = (√E'/E)

E' = 4E

Additional energy= 4E - E = 3E.

QUESTION: 14

If particles are moving with same velocity, then maximum de-Broglie wavelength will be for [CBSE PMT 2002]

Solution:

QUESTION: 15

If an electron and a photon propagate in the form of waves having the same wavelength, it implies that they have the same [CBSE PMT 1995; DCE 2001; AIIMS 2003]

Solution:

- If an electron and a photon propagates in the form of waves having the same wavelength, it implies that they have same momentum. This is according to de-Broglie equation,
p∝1/λ

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