QUIZ 3:Current Electricity(#freetestseries)


15 Questions MCQ Test Physics chapterwise notes and mocks JEE | QUIZ 3:Current Electricity(#freetestseries)


Description
This mock test of QUIZ 3:Current Electricity(#freetestseries) for JEE helps you for every JEE entrance exam. This contains 15 Multiple Choice Questions for JEE QUIZ 3:Current Electricity(#freetestseries) (mcq) to study with solutions a complete question bank. The solved questions answers in this QUIZ 3:Current Electricity(#freetestseries) quiz give you a good mix of easy questions and tough questions. JEE students definitely take this QUIZ 3:Current Electricity(#freetestseries) exercise for a better result in the exam. You can find other QUIZ 3:Current Electricity(#freetestseries) extra questions, long questions & short questions for JEE on EduRev as well by searching above.
QUESTION: 1

 Kirchhoff's second law is based on the law of conservation of [RPET 2003; MH CET 2001]

Solution:
QUESTION: 2

 The figure below shows currents in a part of electric circuit. The current i is [CPMT 1981; RPET 1999] 

Solution:
QUESTION: 3

The terminal potential difference of a cell is greater than its e.m.f. when it is

Solution:
  •   In charging V > E.

QUESTION: 4

 In the circuit shown, potential difference between X and Y will be 

Solution:
  •  In open circuit of a cell V = E

QUESTION: 5

 In the previous question, potential difference across the 40Ω resistance will be

Solution:

      Zero (Circuit open means no current and hence no potential difference across resistance).

QUESTION: 6

 In the circuit shown, A and V are ideal ammeter and voltmeter respectively. Reading of the voltmeter will be 

Solution:
QUESTION: 7

When a resistance of 2 ohm is connected across the terminals of a cell, the current is 0.5 amperes. When the resistance is increased to 5 ohm, the current is 0.25 amperes. The internal resistance of the cell is [MP PMT 1996]

Solution:
QUESTION: 8

 The terminal potential difference of a cell when short-circuited is (E = E.M.F. of the cell)

Solution:

In short circuiting R = 0, so V = 0

QUESTION: 9

 A primary cell has an e.m.f. of 1.5 volts, when short-circuited it gives a current of 3 amperes. The internal resistance of the cell is [CPMT 1976, 83]

Solution:
QUESTION: 10

A 50V battery is connected across a 10 ohm resistor. The current is 4.5 amperes. The internal resistance of the battery is [CPMT 1985; BHU 1997; Pb. PMT 2001]

Solution:
QUESTION: 11

The potential difference in open circuit for a cell is 2.2 volts. When a 4 ohm resistor is connected between its two electrodes the potential difference becomes 2 volts. The internal resistance of the cell will be [MP PMT 1984; SCRA 1994; CBSE PMT 2002]

Solution:
QUESTION: 12

A new flashlight cell of e.m.f. 1.5 volts gives a current of 15 amps, when connected directly to an ammeter of resistance 0.04Ω. The internal resistance of cell is [MP PET 1994]

Solution:
QUESTION: 13

A cell whose e.m.f. is 2 V and internal resistance is 0.1Ω, is connected with a resistance of3.9Ω. The voltage across the cell terminal will be [CPMT 1990; MP PET 1993; CBSE PMT 1999; AFMC 1999; Pb. PMT 2000; AIIMS 2001]

Solution:
QUESTION: 14

The reading of a high resistance voltmeter when a cell is connected across it is 2.2 V. When the terminals of the cell are also connected to a resistance of 5Ω the voltmeter reading drops to 1.8 V. Find the internal resistance of the cell [KCET 2003; MP PMT 2003]

Solution:
QUESTION: 15

When cells are connected in parallel, then [MNR 1983]

Solution:

 In parallel, equivalent resistance is low

Similar Content

Related tests

  • Quiz