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In the given data if n = 230, l = 40, cf = 76, h = 10, f = 65, then its median is
Median=L +
=40 +
=40 + 6 = 46
In a data, if l = 40, h = 15, f_{1}=7, f_{0}=3, f_{2}=6, then the mode is
Mode=L+
Where L=lower limit of the modal class =40
f1= modal class frequency.=7
f2 = just after the modal class frequency.=6
f0 = just previous the modal class frequency=3
C = Class size=15
Mode=40+ * 15 = 40 + 12 = 52
The mode of 4, 5, 6, 8, 5, 4, 8, 5, 6, x, 8 is 8. The value of ‘x’ is
Mode is the most occurred value. In the data we have three 5 and three 8 , so if mode is only 8 then the value of x must be 8 ,so that only 8 is the most occurring value.
The wickets taken by a bowler in 10 cricket matches are 2, 6, 4, 5, 0, 3, 1, 3, 2, 3. The mode of the data is
Mode is the most frequently occurring observation. Since it's not a grouped data the frequency is the occurrence of only one observation , So the highest no. of frequency is 3 . So the modal age is 3.
In a data, if l = 60, h = 15, f_{1 }= 16, f_{0 }= 6, f_{2 }= 6, then the mode is
The mode of 4, 5, 6, 8, 5, 4, 6, 5, 6, x, 8 is 6. The value of ‘x’ is
For the following distribution the lower limit of the modal class is
Modal class as the name suggests is the interval which occurs most of the times which means the interval which has the highest frequency.By changing the distribution in grouped distribution 3040 has the maximum frequency that is 30
The times, in seconds, taken by 75 athletes to run a 500m race are tabulated as below:
The number of athletes who completed the race in less than 125 seconds is
A prime number is a natural number greater than 1 that is not a product of two smaller natural numbers. So 10 prime numbers are: 2,3,5,7,11,13,17,19,23,29
Since the number of terms are even ,
Median =
10/2=5th term=11
10/2 +1=6th term=13
Median =
The marks obtained by 9 students in Mathematics are 59, 46, 30, 23, 27, 44, 52, 40 and 29. The median of the data is
The marks obtained by 9 students in Mathematics are 59, 46, 30, 23, 27, 40, 52, 35 and 29. The median of the data is
The percentage of marks obtained by 100 students in an examination are as follows:
The median class is
In the given data if n = 44, l = 400, cf = 8, h = 100, f = 20, then its median is
The measure of central tendency that can be obtained graphically is
Central tendency is the central value for a probability distribution. Mean,media,mode and range are the measures of central tendeny. Amongst them, median can be determined graphically.
The wickets taken by a bowler in 10 cricket matches are 2, 6, 4, 5, 0, 3, 1, 3, 2, 3. The median of the data is
The marks obtained by 9 students in Mathematics are 59, 46, 30, 23, 27, 44, 52, 40 and 29. The median of the data is
Median is the middle value of the observations. So Median cannot be obtained when the observations are not in order. So first we have to arrange in ascending order.
59, 46, 30, 23, 27, 44, 52, 40 and 29
Gives 23,27,29,30,40,44,46,52,59
Since the no. of observations is odd
In the given data if n = 230, l = 40, cf = 76, h = 10, f = 65, then its median is
Construction of cumulative frequency table is useful to determine
The abscissa of the point of intersection of the less than type and of the more than type ogives of a grouped data gives its
An give, also known as a cumulative histogram, is a graph that is used to determine the number of data points that are equal to or below a certain value in a data set.It is a plot of cumulative values, rather than a plot of the values themselves. Median is determined by finding the (n/2)th value and then dropping it to the x axis.
To represent ‘the less than type’ graphically, we plot the ____________ on the x – axis.
To represent ‘the more than type’ graphically, we plot the ____________ on the x – axis.
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