RRB NTPC Previous Year Paper (Allahabad) - 2013 - RRB NTPC/ASM/CA/TA MCQ

22 boys are standing in front of Kunal in a Queue 12 boys are standing to the back of Rohit
Total boys = 30.
So, rank of Kunal in the queue is 22+1 = 23
Rank of Rohit in the queue is 30 - 12 = 18
Hence, the number of boys between Rohit and Kunal in the queue is 23 - 18 - 1 = 4

There is only one a between the 7th 'a' from the left and 7 th 'a' from the right.

a a b a b a a b a b a a a b b a b a b b a a a a

If A stands for ‘+’, B stands for ‘-’, C stands for ‘x’ and D for ‘÷' then

There are 7 years between the two except two of them are leap years.

In a normal year, there are 365 days. 365 when divided by 7 leaves a reminder of 1. So, 1 July of a year and 1 July of the previous year are one weekday apart. If it is a leap year, 1 July of a year and 1 July of a previous year are separated by 2 weekdays. So, If July 1, 1977 was a Friday, 1st july 1976 is a Thursday and 1st july 1975-tuesday 1st july 1974-monday 1st july 1973-sunday 1st july 1972-saturday 1st july 1971-thrusday 1st july 1970- wednesday

The given equation means P is the father of Q and Q is the sister of R. So, P maybe the father of R.

In 278 and 853, 8 and fast are common.

In 853 and 376, 3 and come are common

So, back is represented by 5 in 853.

The conclusion can be drawn from "none but stout men are players" since it implies that all players have to be stout.

Campaign is generally related to a military manoeuvre. Others are unrelated to military.

The opposite of Natural is artificial. The opposite of spontaneous is calculated.

301 is divisible by 7 (43 times)

497 is also divisible by 7 (71 times)

So, the required sum is

7 ( 43 + 44 + .... + 71)

= 7 x (sum of numbers upto 71 - sum of numbers upto 42) = 7 * [(71x 72/2)-(42 x 43/2)]

= 11571

5p + 4e = 13

9p + 5e = 19

solving for p, we get p = 1

e = 2

So, 6 pencils and 3 erasers cost

6 x 1 + 3 x 2 = 12

If a₁, a₂.........a₇ are different positive integers taking one value at a time from 1,2,........7. The number (a₁-1) (a₂-2)......(a₇ -7) will always be zero as one of the numbers will be equal to 1, 2, 3.... 7.

88935 can be written as 5929 x 15

5929 is the square of 77

So, the answer is 15

The area of the bigger rectangle is 18 x 13

The are of the smaller rectangle is 16 x 11

The required value is 18 x 13 - 16 x 11 = 58 sq.m

If the difference between the digits has to be 4, only 73 and 95 qualify. Of these 73 leaves a remainder of 3 and not 4 when divided by 7. So, the answer is 95.

Number of stations in 350 kilometers = 350/ 42 = 50/6 = 8 stations.

Time stopped at stations = 8 x 5 = 2/3 hrs

Time taken for travel = 350/72 + 2/3 = 5 hours 31 minutes 40 seconds