Retro JEE Advanced (Liquid Solutions) - JEE MCQ
8 Questions MCQ Test - Retro JEE Advanced (Liquid Solutions)
For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm pressure is 2°C. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is (take Kb = 0,76 K kg mol-1).
(2012)
The freezing point (in° C) of solution containing 0.1 g of K3[Fe(CN)6] (mol. wt. 329) in 100 g of water (Kf = 1.86 K kg mol-1) is
| 1 Crore+ students have signed up on EduRev. Have you? Download the App |
The Henry’s law constant for the solubility of N2 gas in water at 298 K is 1.O x 105 atm. The mole fraction of N2 in air is 0.8. The number of moles of N2 from air dissolved in 10 moles of water of 298 K and 5 atm pressure is
(2009)
Passage
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties.
Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles.
A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9.
Given, freezing point depression constant of water
(
) = l . 8 6 K kg mol-1
Freezing point depression constant of ethanol
(
) = 2.0 K kg mol-1
Boiling point elevation constant of water
{
) = 0.52 K kg mol-1
Boiling point elevation constant of ethanol
()=1.2 K kg mol-1
Standard freezing point of water =273 K
Standard freezing point of ethanol = 155.7 K
Standard boiling point of water = 373 K
Standard boiling point of ethanol = 351.5 K
Vapour pressure of pure water = 32.8 mm Hg
Vapour pressure of pure ethanol = 40 mm Hg
Molecular weight of water = 18 g mol-1
Molecular weight of ethanol = 46 g mol-1
In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.
Q.
The freezing point of the solution M is
Passage
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties.
Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles.
A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9.
Given, freezing point depression constant of water
(
) = l . 8 6 K kg mol-1
Freezing point depression constant of ethanol
(
) = 2.0 K kg mol-1
Boiling point elevation constant of water
{
) = 0.52 K kg mol-1
Boiling point elevation constant of ethanol
()=1.2 K kg mol-1
Standard freezing point of water =273 K
Standard freezing point of ethanol = 155.7 K
Standard boiling point of water = 373 K
Standard boiling point of ethanol = 351.5 K
Vapour pressure of pure water = 32.8 mm Hg
Vapour pressure of pure ethanol = 40 mm Hg
Molecular weight of water = 18 g mol-1
Molecular weight of ethanol = 46 g mol-1
In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.
Q.
The vapour pressure of the solution M is
Passage
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties.
Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles.
A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9.
Given, freezing point depression constant of water
(
) = l . 8 6 K kg mol-1
Freezing point depression constant of ethanol
(
) = 2.0 K kg mol-1
Boiling point elevation constant of water
{) = 0.52 K kg mol-1
Boiling point elevation constant of ethanol
()=1.2 K kg mol-1
Standard freezing point of water =273 K
Standard freezing point of ethanol = 155.7 K
Standard boiling point of water = 373 K
Standard boiling point of ethanol = 351.5 K
Vapour pressure of pure water = 32.8 mm Hg
Vapour pressure of pure ethanol = 40 mm Hg
Molecular weight of water = 18 g mol-1
Molecular weight of ethanol = 46 g mol-1
In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.
Q.
Water is added to the solution M such that the mole fraction of water in the solution becomes 0.9. The boiling point of this solution is
When 20 g of naphthoic acid (C11H8O2 is dissolved in 50 g of benzene {Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van’t Hoff factor (i) is
(2007)
The elevation in boiling point, when 13.44 g of freshly prepared CuCI2 are added to one kilogram of water, is (Some useful data, Kb = 0.52 kg K mol-1 molecular weight of CuCI2 =134.4 g).
Top Courses for JEE
Important Questions for Retro JEE Advanced (Liquid Solutions)
Retro JEE Advanced (Liquid Solutions) MCQs with Answers
Online Tests for Retro JEE Advanced (Liquid Solutions)
|
© EduRev
|
Education Revolution
|
Follow Us
|
