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SSC CGL Exam  >  SSC CGL Tests  >  SSC CGL Mathematics Previous Year Paper (Topic-wise)  >  SSC CGL Previous Year Questions: Trigonometry - 4 - SSC CGL MCQ

SSC CGL Previous Year Questions: Trigonometry - 4 - SSC CGL MCQ


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30 Questions MCQ Test SSC CGL Mathematics Previous Year Paper (Topic-wise) - SSC CGL Previous Year Questions: Trigonometry - 4

SSC CGL Previous Year Questions: Trigonometry - 4 for SSC CGL 2024 is part of SSC CGL Mathematics Previous Year Paper (Topic-wise) preparation. The SSC CGL Previous Year Questions: Trigonometry - 4 questions and answers have been prepared according to the SSC CGL exam syllabus.The SSC CGL Previous Year Questions: Trigonometry - 4 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SSC CGL Previous Year Questions: Trigonometry - 4 below.
Solutions of SSC CGL Previous Year Questions: Trigonometry - 4 questions in English are available as part of our SSC CGL Mathematics Previous Year Paper (Topic-wise) for SSC CGL & SSC CGL Previous Year Questions: Trigonometry - 4 solutions in Hindi for SSC CGL Mathematics Previous Year Paper (Topic-wise) course. Download more important topics, notes, lectures and mock test series for SSC CGL Exam by signing up for free. Attempt SSC CGL Previous Year Questions: Trigonometry - 4 | 40 questions in 40 minutes | Mock test for SSC CGL preparation | Free important questions MCQ to study SSC CGL Mathematics Previous Year Paper (Topic-wise) for SSC CGL Exam | Download free PDF with solutions
SSC CGL Previous Year Questions: Trigonometry - 4 - Question 1
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(3π/5) radians is equal to   (SSC CGL 1st Sit. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 1

∵ π radian = 180°

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 2
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Evaluate: 3 cos 80° cosec 10° + 2 cos 59° cosec 31°    (SSC CGL 1st Sit. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 2

3 cos 80°. cosec 10° + 2 cos 59°. cosec 31°
= 3 cos (90° – 10°). cosec 10° + 2 cos (90° – 31°). cosec 31°
= 3 sin 10°. cosec 10° + 2 sin 31°. cosec 31° = 3 + 2 = 5
[∵ cos (90° – θ) = sinθ; sinθ.cosecθ = 1]

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SSC CGL Previous Year Questions: Trigonometry - 4 - Question 3
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If the angles of elevation of a balloon from two consecutive kilometre–stones along a road are 30° and 60° respectively, then the height of the balloon above the ground will be    (SSC CGL 1st Sit. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 3


SSC CGL Previous Year Questions: Trigonometry - 4 - Question 4
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From 125 metre high towers, the angle of depression of a car is 45°. Then how far the car is from the tower?   (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 4

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 5
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If tan α + cot α = 2, then the value of tan 7α + cot7α is    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 5

tan α + cot α = 2

⇒ tan2 α – 2 tan α + 1 = 0
⇒ tan2 α – tan α – tan α + 1 = 0
⇒ tan α (tan α – 1) – 1 (tan α – 1) = 0 (tan α – 1) (tan α – 1) = 0
∴ tan α = 1

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 6
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If x = a cos θ – b sin θ, y = b cos θ + a sin θ, then find the value of x2 + y2.    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 6

x = a cos θ – b sin θ
y = b cos θ + a sin θ
x2 + y2 = (a cos θ – b sin θ)2 + (b cos θ + a sin θ)2 = a2 cos2 θ + b2 sin2 θ + a2 sin2 θ + b2 cos2 θ
= a2 + b2

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 7
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In a triangle, the angles are in the ratio 2 : 5 : 3. What is the value of the least angle in the radian?    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 7

Let angles are 2x, 5x and 3x.
2x + 5x + 3x = 180º (sum of interior angle of triangles is 180º)
10x = 18º
x = 18º
∴ Least angle in degree = 2x = 2 × 18 = 36º

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 8
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The value of    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 8

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 9
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The value of    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 9

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 10
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The value of     (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 10


[∵ cos (90º – θ) = sin θ and cot (90º – θ) = tan θ]

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 11
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If cos4θ – sin4θ = 2/3, then the value of 1 – 2 sin2θ is    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 11

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 12
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If cosθ + sinθ = √2 cos θ, then cosθ – sinθ is    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 12

cosθ + sinθ = √2 cos θ
On squaring both sides,
cos2θ + sin2θ + 2cos θ. sin θ = 2 cos2 θ
⇒ cos2θ – sin2θ = 2cosθ. cos θ
⇒ (cos θ + sin θ) (cos θ – sin θ) = 2 sin θ. cos θ
⇒ 2 cos θ (cosθ – sinθ) = 2sin θ. cos θ

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 13
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The value of     (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 13

Expression

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 14
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If tan α = n tan β, and sin α = m sin β, then cos2 α is    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 14



SSC CGL Previous Year Questions: Trigonometry - 4 - Question 15
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The tops of two poles of height 24 m and 36 m are connected by a wire. If the wire makes an angle of 60° with the horizontal, then the length of the wire is    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 15


BC = ED = 24 m
∴ AE = AD – ED = 36 m  – 24 m = 12 m
In ΔABE,

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 16
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The value of     (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 16

Expression

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 17
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If tan θ = 3/4 and θ is acute, then cosec θ   (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 17

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 18
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One of the four an gles of a rhombus is 60°. If the length of each side of the rhombus is, 8 cm, then the length of the longer diagonal is    (SSC CGL 2nd Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 18


∠BAD = 60°
∴ ∠BAO = 30°
∠ABO = 60°

∴ OA = 43
∴ AC = 83 metre

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 19
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If (1 + sinα) (1 + sinβ) (1 + sinγ) = (1 – sinα) (1 – sinβ) (1 – sinγ), then each side is equal to   (SSC CGL 2nd Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 19

(1 + sin α) (1 + sin β) (1 + sin γ) = (1 – sin α)  (1 – sin β) (1 – sin γ) = x
∴ x.x = (1 + sin α) (1– sin α) (1 + sin β)
(1 – sin β) (1 + sin γ) (1 – sin γ)
x2 = (1 – sin2 α) (1 – sin2 β) (1 – sin2 γ)
x2 = cos2 α. cos2β.cos2 γ
⇒ x = ± cos α. cos β . cos γ 

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 20
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The value of 152 (sin 30° + 2 cos2 45° + 3 sin 30° + 4 cos2 45° +...+17 sin 30° + 18 cos2 45°) is    (SSC CGL 2nd Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 20

152 (sin 30° + 2 cos2 45° + 3 sin 30° + 4 cos2 45° +...+17 sin 30° + 18 cos2 45°)
   equals space 152 open square brackets 1 half space plus space 2 open parentheses 1 half close parentheses space plus space 3 open parentheses 1 half close parentheses space plus space 4 open parentheses 1 half close parentheses space plus....18 open parentheses 1 half close parentheses close square brackets equals space 152 space cross times space 1 half left square bracket 1 space plus space 2 space plus space 3 space plus space 4 space plus space..... plus 18 right square bracket equals space 152 space cross times space 1 half space cross times space fraction numerator 18 space cross times space 19 over denominator 2 end fraction equals space 76 space cross times space 9 space cross times space 19 space equals space 12996 space equals space left parenthesis 114 right parenthesis squared
Thus, Required number is a perfect square of an integer.

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 21
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Maximum value of (2 sin θ + 3 cos θ) is    (SSC CGL 2nd Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 21

Maximum value of 2 sin θ + 3 cos θ
           equals space square root of left parenthesis 2 right parenthesis squared space plus space left parenthesis 3 right parenthesis squared end root equals space square root of 4 space plus space 9 end root space equals space square root of 13

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 22
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If sin ( A – B ) = 1/2 and cos (A + B) = 1/2 where A > B > 0 and A + B is an acute angle, then the value B is    (SSC CGL 2nd Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 22

sin (A – B) = 1/2 = sin 30° ⇒ A – B= 30°
cos (A + B) = 1/2 = cos 60° ⇒ A + B = 60°
∴ A + B + A – B = 30° + 60° = 90°
⇒ 2A = 90° ⇒ A = 45°
∴ A – B = 30°

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 23
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Evaluate : tan 1° tan 2° tan 3° ........... tan 89°.    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 23

tan 89° = tan (90° – 1°) = cot 1°
tan 88° = tan (90° – 2°) = cot 2°
∴ Expression = tan 1°, cot 1°, tan 2°,  cot2° ... tan 45° = 1
[∵ tan θ. cot θ = 1]

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 24
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If secθ + tanθ = 2 + √5,  then the value of sinθ + cosθ is?   (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 24


SSC CGL Previous Year Questions: Trigonometry - 4 - Question 25
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If sinθ + cosecθ = 2, then sin9θ + cosec9θ is equal to ______.    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 25

sinθ + cosecθ = 2

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 26
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The degree measure of 1 radian (taking π = (22 / 7)) is
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 26

π radian = 180°

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 27
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The value of (sin2 25° + sin2 65°) is:    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 27

sin2 25° + sin2 65°
= sin2 25° + sin2 (90° – 25°)
= sin2 25° + cos2 25° = 1

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 28
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The value of cos 1° cos 2° cos 3°............ cos 177° cos 178° cos 179° is:    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 28

cos 90° = 0
∴ cos 1°, cos 2° .... cos 179° = 0

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 29
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The angle of elevation of a tower from a distance 100 m from its foot is 30°. Height of the tower is:    (SSC CGL 1st Sit. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 29


AB = h metre
∠ACB = 30°;
BC = 100 metre

SSC CGL Previous Year Questions: Trigonometry - 4 - Question 30
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If 2(cos2θ - sin2θ) = 1, (θ is positive acute angle), then cotθ is equal to?   (SSC CHSL 2013)
Detailed Solution for SSC CGL Previous Year Questions: Trigonometry - 4 - Question 30

2 cos 2θ = 1
cos 2θ = 1/2
θ = 30°
cot 30° = √3

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