SSC MTS Mock Test - 3 - SSC MTS / SSC GD MCQ

Suppose, Initially petrol and kerosene be 3x and 2x litres respectively.
When 10 litres of mixture is taken out from the mixture.
Quantity of petrol left in the mixture = 
Quantity of kerosene left in the mixture = 
= (2x - 4) litres
Also, 10 litres of kerosene is added
Quantity of kerosene will be (2x−4+10)=(2x+6) litres
Now, 

Quantity of petrol = 3x = 3×6 = 18 litres
Quantity of kerosene = 2x = 2×6 = 12 litres
Total, quantity of mixtures = (18+12) = 30 litres

Given:
A person has planned to sell his old laptop for Rs. 4500, he would lose 10%.
Formula Used:
Selling price = Cost price - loss% of cost price 
Selling price of laptop = 4500
Loss percent = 10%
⇒ 4500 = cost price −10% of cost price
⇒ 4500 = 90% of cost price
Cost price = Rs. 5000
Now according to question he need 20% profit
So new selling price = cost price +20% of cost price
= 5000+20% of 5000
= 5000+1000
= Rs. 6000
∴ He will sell at Rs. 6000 to gain 20% on cost price.

Given:
Total number of sweets =405
As we know,
Total number of sweets = Total number of children × sweets received by each child
Let the number of children be n.
Sweets received by each child = n/5

Divide the numerator by denominator.

Given,

Hence, the correct option is (D).

Given:
Pipe 'P' can fill a tank in 5 hours.
Pipe 'Q' can fill the same tank in 15 hours.
Pipe 'R' can empty the same tank in 7.5 hours
The efficiency of a person is the inverse of the time taken
P's per hour efficiency = 1/5
Q's per hour efficiency = 1/15
R's per hour efficiency  negative because it is emptying the tank
Total efficiency of P, Q, R working together 
Since the time taken is the inverse of efficiency.
∴ Together they will take 7.5 hours to fill the tank
Hence, the correct option is (D)

20% discount means 20% of 500 = Rs.100 is first discount
Now price is 500−100 = Rs.400
10% discount means 10% of 400 = Rs.40
Now, Selling Price = 400 - 40 = Rs. 360.

Given:
The difference between S.I. and C.I. at 10% interest rate is Rs. 50
According to the question,
We know that,

Now, half of the sum,

∴ Half of the sum is Rs. 2500.

30 = 5 × 3 × 2
45 = 5 × 3 × 3 = 5 × 3²
60 = 5 × 3 × 2 × 2 = 5 × 3 × 2²
∴ LCM = 5 x 3² x 2² = 180

Given,
Total cost = Rs. 60000
The break-up of the cost of construction of a house (in degrees) for cement = 72
Amount spent on cement = (72/360) x 60000
= (4320000/360) = Rs12000

Given:
x² − 2xy = 84
x = y - 10
Calculations:
According to question,
x² − 2xy = 84 ------------(1)
And x = y - 10
now, put x = y - 10 in eq(1)
(y - 10)² - 2y(y - 10) = 84
⇒y² - 20y + 100 - 2y² + 20y = 84
⇒- y² = 84 - 100
⇒ y² = 16 
⇒ y = 4
Hence, The Required value is 4.

Given:
Loss = 12%
SP of an article = Rs. 242
Formula used:
SP = CP × (100 – Loss%)
SP = CP × (100 + gain%)
Calculation:
SP of an article = Rs. 242
Loss = 12%
SP = CP × (100 – Loss%)
⇒ 242 = CP × (100 – 12)%
⇒ 242 = CP × 88/100
⇒ CP = (242 × 100/88)
⇒ CP = Rs. 275
Now,
If gain = 15%
SP = CP × (100 + gain%)
⇒ SP = 275 × (100 + 15)%
⇒ SP = (275 × 115/100)
⇒ SP = Rs. (55 × 23)/4
⇒ Rs. 1265/4
⇒ Rs. 316.25
∴ The required SP is Rs. 316.25

Given:
A total of 1000 kg of vegetables were sold in a day
Calculation:
The percentage of tomatoes sold in a day is 40%
So according to the question:
Number of tomatoes = 40% of 1000 = 400.
∴ Option 1 is the correct answer.

Given:
Selling price of the article after two successive discounts = Rs. 560
First discount: 30%
Second discount: 20%
Formula used:
Selling price = Marked price - (Discount 1% × Marked price) - (Discount 2% × Marked price)
Calculation:
Let's solve the question:
Let the marked price of the article be "M".
Selling price after the first discount = M - (30/100)M = (70/100)M = 0.7M
Selling price after the second discount = 0.7M - (20/100)(0.7M) = (0.7M) - (0.14M) = 0.56M
Given that the selling price after the two discounts is Rs. 560, we can set up the equation:
0.56M = 560
To find the marked price (M), divide both sides of the equation by 0.56:
M = 560/0.56
M = 1000
Therefore, the marked price of the article is Rs. 1000.

Given:
Ajay can row his boat in still water at a speed of 6 km/hr. The speed of the stream is 4 km/hr.
Formula used:
Time = Distance/Speed
Calculation:
⇒ Speed of downstream = 6 + 4 = 10kmph
∴ Time is taken to a distance of 30 km downstream = 30/10 = 3 hours

Given:
A cuboid of length 36 m, breadth 18 m and height 9 m is melted and recast into a cube.
Concept used:
Volume of cuboid = L × H × B
Volume of cube = a³
Here,
L = Lenght
B = breadth
H = height
a = side of the cube
Calculation:
Let the side of the cubes to be formed be a
According to the question,
Volume of cuboid = volume of the cube
So,
36 × 18 × 9 = a³ 
⇒ 5832 = a³ 
⇒ a³ = 18³
⇒ a = 18
So, the diagonal of the cube is 18√3
∴ The length of the diagonal of the cube is 18√3.

Calculation:
[(√529) + (√5.29) + (√0.0529)]
⇒ (23 + 2.3 + 0.23) = 25.53
∴ answer is 25.53.

Calculation:
Income of P and Q  = 650 + 450 = 1100
Expenditure of S and T = 150 + 100 = 250
According to the question:
(1100 - 250)250 × 100 
850/250 × 100
85 × 4 = 340%
∴ Option 4 is the correct answer.

Given:
Sum becomes Rs. 15500
Rate of interest (r) = 30% per annum
Time period (t) = 7 years
Formula used:
Simple interest (S.I) = (Prt/100)
Where,
P = principal amount
r = rate of interest
t = time period
Calculation:
If the sum becomes Rs. 16000 Means,
[P + (S.I)] = sum
⇒ [P + (Prt /100)] = sum
⇒ [P + (P × 30 × 7)/ 100] = 15500
⇒ [P + (P × 210/100)] = 15500
⇒ [P + (21P/10)] = 15500
⇒ [31P/10] = 15500
⇒ P = 15500 × (10/31)
⇒ P = 5000
So, S.I = 15500 - 5000
⇒ Rs. 10500
∴ The total interest for the 7 years is Rs. 10500.

Given:
983² - 17² = ?
Formula used:
a² - b² = (a + b)(a - b)
Calculations:
(983)² - (17)² 
⇒ (983 + 17)(983 - 17)
⇒ 1000 × 966 = 966000
∴ 983² - 17² is 966000.

The pattern followed here is;

Hence, "222" is the correct answer.

The pattern followed is:

Hence, the correct answer is "MOF".

The logic followed in a column is that:
(1st number × 3rd number) - 1st number = second number
The pattern followed is,
1st column → 16 × 10 - 16 = 160 - 16 = 144
3rd column → 12 × 11 - 12 = 132 - 12 = 120
Similarly, we have:
2nd column → 31 × 15 - 31 = 465 - 31 = 434
Hence, 434 is the correct answer.

Seven Persons: M, N, O, P, Q, R and S
1. N sits third to the left of Q.
2. Only P is adjacent to S, who does not sit at extreme left end.
Case-1

Case-2

3. M sits immediate left of R.
4. O and Q are not adjacent to each other.

So, N sits immediate left of M.
Hence, N is the correct answer.

The logic followed in the given pair:
Peso : Chile → Peso is the currency of Chile.
Similarly,
Ringgit : Malaysia → Ringgit is the currency of Malaysia.
Here, 'Ringgit : Malaysia' is the correct pair.
Hence, the correct answer is "Malaysia ".

According to the English alphabets and their positional values:
According to the English alphabets and their positional values:

The pattern followed in the given codes is:
The alphabets are increased to 2 positional values and the code is arranged backwards.


Similarly,

Hence the correct answer is option (3).

The pattern followed in the given series is:
First and sixth alphabets are interchanged & third and fourth alphabets are interchanged.

Similarly,

Hence the correct answer is option (4).

The code of each word is shown below:

The code for of is na.
code for the is lu.
Code for way is fa.
Clearly, "of the way" is represented by "na lu fa".
Hence, ‘lu na fa’ is the correct answer.

According to the positional values of the letters in the English alphabetical series, the pattern followed here is,

1) F = 6; T = 20; 6² - 20 = 16
2) D = 4; M = 13; 4² - 13 = 3 ≠​​ 29
3) K = 11; Z = 26; 11² - 26 = 95
4) H = 8; S = 19; 8² - 19 = 45
Hence, '29DM' is the odd one out.

BODMAS Table

Given equation : 35 + 5 ÷ 4 × 2 – 15 =
after interchanging  × and ÷ we get, by Using BODMAS table
⇒ 35 + 5 × 4 ÷ 2 - 15
⇒ 35 + 5 × 2 - 15
⇒ 35 + 10 - 15
⇒ 45 - 15
⇒ 30
Hence, Option 3) is the correct answer.