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This mock test of Simple Harmonic Motion MCQ for IIT JAM helps you for every IIT JAM entrance exam.
This contains 10 Multiple Choice Questions for IIT JAM Simple Harmonic Motion MCQ (mcq) to study with solutions a complete question bank.
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QUESTION: 1

The equation of S.H.M of a particle is is a positive constant. The time period of motion is given by :

Solution:

Compare with equation of SHM

The correct answer is:

QUESTION: 2

If length of simple pendulum is increased by 6 % then percentage change in time period will be :

Solution:

The correct answer is:

QUESTION: 3

A particle is executing S.H.M. from mean position at 5 cm distance, acceleration is 20 cm/s^{2} then value of angular velocity will be :

Solution:

The correct answer is: 2 rad/s

QUESTION: 4

A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. If the lift accelerates upwards with an acceleration then the period of the pendulum will be :

Solution:

The correct answer is:

QUESTION: 5

The maximum velocity of harmonic oscillator is a, and its maximum acceleration is β Its time period will be :

Solution:

The correct answer is:

QUESTION: 6

One mass m is suspended from a spring. Time period of oscillation is T. Now if spring is divided into n piece and these are joined in parallel order then time period of oscillation if same mass is suspended.

Solution:

Keq = n^{2}k is correct but it is a 2 step process

First, K’ = k x n as the spring constant becomes ‘n’ times due to shortening of length

Second, Keq = n x K’ as they are connected in a parallel manner

=>Keq = n^{2}K

QUESTION: 7

Amplitude of harmonic oscillator is a when velocity of particle is half of maximum velocity, then position of particle will be :

Solution:

The correct answer is:

QUESTION: 8

A simple pendulum suspended from the ceiling of a stationary trolley has a length Its period of oscillation is What will be its period of oscillation if the trolley moves forward with an acceleration f ?

Solution:

The correct answer is:

QUESTION: 9

In S.H.M, the graph between kinetic energy 'K' and time 't' is:

Solution:

The correct answer is:

QUESTION: 10

Two object A and B of equal mass are suspended from two springs of spring constants K_{A} and K_{B} if the objects oscillate vertically in such a manner that their maximum kinetic energies are equal, then the ratio of their amplitude is :

Solution:

Kinetic energy of A = Kinetic energy of B.

So, ratio of amplitude

The correct answer is:

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