The equation of S.H.M of a particle is is a positive constant. The time period of motion is given by :
Compare with equation of SHM
The correct answer is:
If length of simple pendulum is increased by 6 % then percentage change in time period will be :
The correct answer is:
A particle is executing S.H.M. from mean position at 5 cm distance, acceleration is 20 cm/s^{2} then value of angular velocity will be :
The correct answer is: 2 rad/s
A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. If the lift accelerates upwards with an acceleration then the period of the pendulum will be :
The correct answer is:
The maximum velocity of harmonic oscillator is a, and its maximum acceleration is β Its time period will be :
The correct answer is:
One mass m is suspended from a spring. Time period of oscillation is T. Now if spring is divided into n piece and these are joined in parallel order then time period of oscillation if same mass is suspended.
Keq = n^{2}k is correct but it is a 2 step process
First, K’ = k x n as the spring constant becomes ‘n’ times due to shortening of length
Second, Keq = n x K’ as they are connected in a parallel manner
=>Keq = n^{2}K
Amplitude of harmonic oscillator is a when velocity of particle is half of maximum velocity, then position of particle will be :
The correct answer is:
A simple pendulum suspended from the ceiling of a stationary trolley has a length Its period of oscillation is What will be its period of oscillation if the trolley moves forward with an acceleration f ?
The correct answer is:
In S.H.M, the graph between kinetic energy 'K' and time 't' is:
The correct answer is:
Two object A and B of equal mass are suspended from two springs of spring constants K_{A} and K_{B} if the objects oscillate vertically in such a manner that their maximum kinetic energies are equal, then the ratio of their amplitude is :
Kinetic energy of A = Kinetic energy of B.
So, ratio of amplitude
The correct answer is:
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