All Courses
Get the App Signup / Login
Sign in Open App
JEE Exam  >  JEE Tests  >  Chemistry for JEE Main & Advanced  >  Solid State - 1 - JEE MCQ

Solid State - 1 - JEE MCQ


Test Description

30 Questions MCQ Test Chemistry for JEE Main & Advanced - Solid State - 1

Solid State - 1 for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Solid State - 1 questions and answers have been prepared according to the JEE exam syllabus.The Solid State - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Solid State - 1 below.
Solutions of Solid State - 1 questions in English are available as part of our Chemistry for JEE Main & Advanced for JEE & Solid State - 1 solutions in Hindi for Chemistry for JEE Main & Advanced course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Solid State - 1 | 30 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study Chemistry for JEE Main & Advanced for JEE Exam | Download free PDF with solutions
Solid State - 1 - Question 1
Save

What type of crystal defect is indicated in the diagram below ?

[AIEEE-2004]

Detailed Solution for Solid State - 1 - Question 1

Here the crystal defect is the paired vacancies caused by the ions missing from their lattice sites. 
 

Solid State - 1 - Question 2
Save

An ionic compound has a unit cell consisting of A ions at the corners of a cube and B ions on the centres of the faces of the cube. The empirical formula for this compound would be

 [AIEEE-2005]

Detailed Solution for Solid State - 1 - Question 2

Unit cell consists of A ions at the corners is 8. So we know that the 

contribution of corner is = 1/8th of corner = 1/8 x 8 = 1. 

Unit cell consists of B ions at the centre of the six faces 

Face = 1/2th of face 

= 1/2 x 6= 3 

So the empirical formula for this compound will be AB3 

1 Crore+ students have signed up on EduRev. Have you? Download the App
Solid State - 1 - Question 3
Save

Copper crystallizes in fcc with a unit cell length of 361 pm. What is the radius of copper atom?

Detailed Solution for Solid State - 1 - Question 3

Radius of the atom = a ÷ a√2

=361÷2√2

=127.56

Solid State - 1 - Question 4
Save

In a compound, atoms of element Y form ccp lattice and those of element X occupy 2/3rd of tetrahedral voids. The formula of the compound will be - 

[AIEEE 2008]
Detailed Solution for Solid State - 1 - Question 4

No. of Y atoms per unit cell in ccp lattice = 4

 No. of tetrahedral voids = 2 × 4 = 8

 No. of tetrahedral voids occupied by X = 2/3 × 8 = 16/3

 Therefore, Formula of the compound = X16/3Y4

= X16Y12

= X4 Y3

Solid State - 1 - Question 5
Save

Copper crystallises in fcc with a unit cell length of 361 pm. What is the radius of copper atom?
Detailed Solution for Solid State - 1 - Question 5

Solid State - 1 - Question 6
Save

If 'a' stands for the edge length of the cubic systems : simple cubic, body centred cubic and face centred cubic, then the ratio of radii of the spheres in these system will be respectively -
Detailed Solution for Solid State - 1 - Question 6


Solid State - 1 - Question 7
Save


Detailed Solution for Solid State - 1 - Question 7


Solid State - 1 - Question 8
Save


Detailed Solution for Solid State - 1 - Question 8


Solid State - 1 - Question 9
Save


Detailed Solution for Solid State - 1 - Question 9


Solid State - 1 - Question 10
Save

What is the diameter of the largest sphere that will fit in the void at the centre of the cube edge of a BCC crystal of edge length a ?
Detailed Solution for Solid State - 1 - Question 10


Solid State - 1 - Question 11
Save


Detailed Solution for Solid State - 1 - Question 11


Solid State - 1 - Question 12
Save

Detailed Solution for Solid State - 1 - Question 12

Solid State - 1 - Question 13
Save


Detailed Solution for Solid State - 1 - Question 13


Solid State - 1 - Question 14
Save


Detailed Solution for Solid State - 1 - Question 14


Solid State - 1 - Question 15
Save


Detailed Solution for Solid State - 1 - Question 15


Solid State - 1 - Question 16
Save

Detailed Solution for Solid State - 1 - Question 16


Solid State - 1 - Question 17
Save


Detailed Solution for Solid State - 1 - Question 17


Solid State - 1 - Question 18
Save

The packing fraction of the element that crystallizes in simple cubic arrangement is -
Detailed Solution for Solid State - 1 - Question 18


Solid State - 1 - Question 19
Save



Detailed Solution for Solid State - 1 - Question 19


Solid State - 1 - Question 20
Save


Detailed Solution for Solid State - 1 - Question 20


Solid State - 1 - Question 21
Save


Detailed Solution for Solid State - 1 - Question 21


Solid State - 1 - Question 22
Save

A solid compound contains X, Y and Z atoms in a cubic lattice with X atoms occupying the corners, Y atoms in the body centred positions and Z atoms at the centre of the faces of the unit cell. What is the empirical formula of the compound ?
Detailed Solution for Solid State - 1 - Question 22


Solid State - 1 - Question 23
Save

When heated above 916ºC, iron changes its bcc crystalline form to fcc without the change in the radius of atom. The ratio of density of the crystal before heating and after heating is [At . wt. Fe = 56]
Detailed Solution for Solid State - 1 - Question 23

Solid State - 1 - Question 24
Save

The anions (A) form hexagonal closest packing and the cations (C) occupy only 2/3 of octahedral holes. The simplest formula of the ionic compound is –
Detailed Solution for Solid State - 1 - Question 24


Solid State - 1 - Question 25
Save


Detailed Solution for Solid State - 1 - Question 25


Solid State - 1 - Question 26
Save


Detailed Solution for Solid State - 1 - Question 26


Solid State - 1 - Question 27
Save


Detailed Solution for Solid State - 1 - Question 27


Solid State - 1 - Question 28
Save


Detailed Solution for Solid State - 1 - Question 28


Solid State - 1 - Question 29
Save

A crystal is made of particles A and B. A forms FCC packing and B occupies all the octahedral voids. If all the particles along the plane as shown in figure are removed, then, the formula of the crystal would be :
Detailed Solution for Solid State - 1 - Question 29


Solid State - 1 - Question 30
Save


Detailed Solution for Solid State - 1 - Question 30


352 videos|596 docs|309 tests
Join Course
Information about Solid State - 1 Page
In this test you can find the Exam questions for Solid State - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Solid State - 1, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

352 videos|596 docs|309 tests
Join Course
Download as PDF

Top Courses for JEE

Important Questions for Solid State - 1

Find all the important questions for Solid State - 1 at EduRev.Get fully prepared for Solid State - 1 with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the Solid State - 1 syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of Solid State - 1 resources.

Solid State - 1 MCQs with Answers

Prepare for the Solid State - 1 within the JEE exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for Solid State - 1 Chemistry for JEE Main & Advanced

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace Solid State - 1 with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup