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A positive kaon (k+) has a rest mass of 494 MeV/c2 whereas a proton has a rest mass of 938 MeV/c2. If a koan has a total energy that is equal to the proton rest energy, speed of the kaon is most nearly :
The correct answer is: 0.85 c
A car of rest length 5 meters passes through a garage rest length 4 meters. Due to the relativistic Lorentz contraction, the car is only 3 meters long in the garage’s rest frame. There are doors on both ends of the garage, which open automatically when the front of the car reaches them and close automatically when the rear passes them. The opening or closing of each door requires a negligible amount of time.
The velocity of the car in the garage’s rest frame is
Length contraction: L = L0/γ
with γ = 1/(1 − v2/c2)½
Given for the car, L0 = 5 m and L = 3 m
γ = L0/L = 5/3 = 1/(1 − v2/c2)½
γ² = 25/9 = 1/(1 − v2/c2)
1 − v²/c² = 9/25
v²/c² = 1 − 9/25 = 16/25
v = 4/5 c = 0.8c
The mean life of a meson is 2 x 10-8 sec. Calculate the mean life of a meson moving with a velocity 0.8c.
∆t = t / √(1-v²/c²)
∆t = 2*10-8/√(1-(0.8)²)
∆t = 2*10-8 / 0.6
∆t = 3.3*10-8 s
Two observers O and O' observe 2 events, A and B. The observers have a constant relative speed of 0.8c. In the units such that the speed of light is 1, observer O obtained the following coordinates.
What is the length of the space time interval between these 2 events, as measured by O' ?
dS2 = dr2 + (cdt)2 = dx2 + dy2 + dz2 − (cdt)2
dS2 = dS'2
dx2 = (5 − 3)2 = 4
dy2 = (3 − 3)2 = 0
dz2 = (1 − 3)2 = 4
dt2 = (5 − 3)2 = 4
c = 1
dS'2 = 4 + 0 + 4 − 4 = 4
dS' = 2
The ultraviolet Lyman α line of hydrogen with wavelength 121.5 nm is emitted by an astronomical object. An observer on earth measures the wavelength of the light received from the object to be 607.5 nm. The observer can conclude that the object is moving with a radial velocity of :
Since the light received has a higher wavelength than the incident wavelength, one concludes that this is a red shift, that the object is moving away from the Earth.
where λ0 is the wavelength of the source.
The doppler effect equation gives
Solving this one gets β = 35/37
v = 2.8 × 108 m/s
away from the Earth.
The correct answer is: 2.8 × 108 m/s away from Earth
A particle leaving a cyclotron has a total relativistic energy of 10 GeV and a relativistic momentum of 8 GeV. What is the rest mass of this particle?
Total energy = 10 GeV
p = 8 GeV
In units in which c = 1 option (d)
The correct answer is: 6 GeV/c2
The matrix shown above transforms the components of a vector in one coordinate frame S to the components of the same vector in a second coordinate frame S'. This matrix represents a rotation of the reference frame S by :
The form of the matrix show that the rotation is about the z-axis
since the z component does not change
∴ rotation about the z axis
Now, the standard from of the rotation matrix about z axis is
The correct answer is: 60° counter clockwise about the z axis
A car of rest length 5m passes through a garage of rest length 4m. Due to the relativistic lorentz contraction, the car is only 3m long in length in the garage’s rest frame. There are doors on both ends of the garage, which open automatically when the front of the car reaches them and close automatically when the rear passes them. The opening or closing of the doors requires a negligible amount of time.
Which of the following is the best response to the question : “was the car ever inside the closed garage”
Correct Answer :- d
Explanation : The order of the door opening depends on which reference frame one is in
So, the car fits in the garage’s frame (the car is 3m and the garage is 4m). But in its own frame, the car is much longer to fit in the garage (car is 5m and the garage is only 2.4m)
Both the frames give different answers.
There is no unique answer, as the order of door openings and closings depends on the reference frame.
What is the length of a metre stick moving parallel to its length when its mass is 3/2 times of its rest mass.
The mass of the rod is 3/2 times its rest mass, that is
The length of meter stick moving parallel to its length, according to length contraction formula.
L0 = 1m
L = 1 × 0.667 = 0.67m
The correct answer is: 0.67 m
A space crew has a life support system that can last only for 1000 hours. What minimum speed would be required for safe travel of the crew between two space stations separated by a fixed distance of 1.08 x 1012 km ?
1000 x 3600 x v / √ 1- v2/ c2 = 1.08 x 1012 x 1000
= 105 x 36 x v / √ 1- v2/ c2 = 1080 x 1012
= v / √ 1- v2/ c2 = c
v = c / √2