In the tension test of a bar the fractured surface shows a truncated cone, the material may be:
In the engineering stress-strain curve for mild steel, the Ultimate Tensile Strength (UTS) refers to
The engineering stress-strain curve for mild steel is
Ultimate tensile strength represents the maximum stress that a material can withstand without Fracture.
_______ is the capacity of material to absorb energy when it is elastically deformed and then upon unloading, to have this energy recovered.
Resilience: It is energy absorbed by a member in elastic region. It denotes the capacity of material to absorb energy when it is elastically deformed and then upon unloading, to release this energy.
Toughness: It is energy absorbed by member just before its fracture.
The shear modulus of a material is half of its Young’s modulus. What is the value of its Poisson’s ratio?
A mild steel wire is 10 mm in diameter and 1 m long. If the wire is subjected to an axial tensile load 10 kN, find an extension of the road (Take E = 200 × 109 Pa) :
The ratio of strengths of solid to hollow shafts, both having outside diameter D and hollow having inside diameter D/2, in torsion, is
A simply supported beam is subjected to a uniformly distributed load. Which one of the following statements is true?
For section AB
For equilibrium, ∑M0 = 0
For M to be maximum or minimum ⇒ dM/dx = 0
Hence dM/dx = V = 0
A steel plate of side ‘a’ (2d) is enclosed in a closely fitting rigid support as shown. Assume friction between plate and support is zero. Determine the free expansion in x - direction of the plate due to heating by ΔT – (Poison ratio is μ & thermal co - eff. α)
σx = 0
σy = −αTE
εy = −αT
εx = −μεy = μαT = δa/a
ϵx = Free expansion due to temperature change + Expansion due to lateral strain
= a α Δ T + μ a α Δ T (due to y direction)
= a α Δ T (1 + μ)
For a cylindrical bar of 30 mm dia& 900 mm length, during a tension test, it is found that longitudinal strain is 4 times of lateral strain. The bulk modulus for the bar is (X) × 105 N/mm2 (if E = 3 × 105 N/mm2) The value if X is ___________
E = 2 × 105 N/mm2 & E = 3k (1 – 2μ).....(1)
From (1) we get K = E/3(1−2μ) [∴μ=0.25 given]
put μ=0.25 in equation 1,we get
A cantilever beam has the cross-section of an isosceles triangle and is loaded as shown in figure. If the moment of inertia of the cross-section Izz = 1/36m4, then the maximum bending stress is