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# Strength of Materials - 3

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## 20 Questions MCQ Test Mock Test Series for SSC JE Mechanical Engineering | Strength of Materials - 3

Strength of Materials - 3 for SSC 2022 is part of Mock Test Series for SSC JE Mechanical Engineering preparation. The Strength of Materials - 3 questions and answers have been prepared according to the SSC exam syllabus.The Strength of Materials - 3 MCQs are made for SSC 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Strength of Materials - 3 below.
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Strength of Materials - 3 - Question 1

### The resistance per unit area, offered by a body against deformation is known as:

Detailed Solution for Strength of Materials - 3 - Question 1
• The force of resistance per unit area, offered by a body against deformation is known as stress.
• The external force acting on the body is called the load or force.
• When a body is subjected to some external force, there is some change of dimension of the body. The ratio of change of dimension of the body to the original dimension is know as strain.
Strength of Materials - 3 - Question 2

### Which of the following load does not act on the considerable length of the beam?

Detailed Solution for Strength of Materials - 3 - Question 2

Point load is that load which acts over a small distance. Because of concentration over small distance this load can may be considered as acting on a point. Point load is denoted by P and symbol of point load is arrow heading downward (↓).

Uniformly distributed load is that whose magnitude remains uniform throughout the length.

Uniformly varying load is further divided into two types:

• Triangular Load: whose magnitude is zero at one end of span and increases constantly till the 2nd end of the span.
• Trapezoidal Load: which is acting on the span length in the form of trapezoid. Trapezoid is generally form with the combination of uniformly distributed load (UDL) and triangular load.
Strength of Materials - 3 - Question 3

### The shear stress on a beam section is maximum:-

Detailed Solution for Strength of Materials - 3 - Question 3

Shear stress on a beam section is:

(i) Zero at extreme fibres

(ii) Maximum at neutral axis Strength of Materials - 3 - Question 4

Maximum Shear strain Energy theory was postulated by:

Detailed Solution for Strength of Materials - 3 - Question 4

. Maximum Principal stress theory was postulated by Rankine. It is suitable for brittle materials.

2. Maximum Principal strain theory was postulated by St Venant. This theory is not accurate for brittle and ductile materials both.

3. Maximum Shear stress theory was postulated by Tresca. This theory is suitable for ductile materials. Its results are the safest.

4. Maximum shear strain energy theory was postulated by Von-mises. Its results in case of pure shear are the accurate for ductile materials.

Strength of Materials - 3 - Question 5

The maximum deflection due to a load W at the free end of a cantilever of length L and having flexural rigidity EI is

Detailed Solution for Strength of Materials - 3 - Question 5 The maximum deflection will occur at Strength of Materials - 3 - Question 6

If section modulus of a beam is increased, the bending stress in the beam will:

Detailed Solution for Strength of Materials - 3 - Question 6

Bending Moment Equation For the constant bending moment: σ ∝ 1/Z

So, bending stress is inversely proportional to the Section Modulus 'YH

Strength of Materials - 3 - Question 7

When the shear force diagram is a parabolic curve between two points, it indicates that there is a

Detailed Solution for Strength of Materials - 3 - Question 7

The general relationship between the shear force diagram, bending moment diagram and loading diagram will be:

2. Bending moment diagram is 1higher than shear force diagram.

3. For the uniformly varying load on the beam, the shear force diagram is parabolic in nature.

4. For the uniformly varying load on the beam, the bending moment diagram is also parabolic but is 1o higher than shear force diagram.

Strength of Materials - 3 - Question 8

Mohr’s circle can be used to determine the following stress on an inclined surface:

A. Principal stress

B. Normal stress

C. Tangential stress

D. Maximum shear stress

Detailed Solution for Strength of Materials - 3 - Question 8

Mohr circle is a graphical representation of plane stress which helps in determining the relationships between normal and shear stresses acting on any inclined plane at a point in a stressed body.

Mohr’s circle of stresses is a graphical method of finding normal, tangential and resultant stresses on an oblique plane.

Strength of Materials - 3 - Question 9

The ratio of moment of inertia of circular plate to that of square plate of equal depth is:

Detailed Solution for Strength of Materials - 3 - Question 9 Moment of inertia (I1) of circular plate of diameter “D” is given by:

. Moment of inertia (I2) of square plate of side equal to diameter “D” of circular plate is given by: Strength of Materials - 3 - Question 10

Which material has highest value of poison’s ratio?

Detailed Solution for Strength of Materials - 3 - Question 10

Elastic Rubber: 0.5

Wood: Because wood is orthotropic, 12 constants are required to describe elastic behaviour: 3 moduli of elasticity, 3 moduli of rigidity, and 6 Poisson’s ratios (vary from 0.02 to 0.47). These elastic constants vary within and among species and with moisture content and specific gravity.

Copper: 0.33

Steel: 0.27 - 0.30

Strength of Materials - 3 - Question 11

The major and minor principal stresses at a point are 3Mpa and -3Mpa respectively. The maximum shear stress at the point is

Detailed Solution for Strength of Materials - 3 - Question 11

Maximum shear stress (τ) is given by: Strength of Materials - 3 - Question 12

The equivalent length of a column of length L having one end fixed and the other end free is

Detailed Solution for Strength of Materials - 3 - Question 12

Effective length of columns under different end conditions are:

1. For both ends hinged: Le = L

2. One end fixed and another end free: Le = 2L

3. Both ends fixed = Le= 4. One end fixed and other is hinges: Le= Strength of Materials - 3 - Question 13

The radius of Mohr’s circle for two equal and unlike principal stresses of magnitude “p” is:

Detailed Solution for Strength of Materials - 3 - Question 13

Radius of Mohr’s circle is given by:

r=

At principal plane, σx = σ1, σy = σ2

τxy = 0

r= σ= p , σ2 = -p

r= r = p

Strength of Materials - 3 - Question 14

A rectangular beam is 24 cm wide and 50 cm deep, its section modulus is given by:

Detailed Solution for Strength of Materials - 3 - Question 14

Section modulus is defined as the ratio of moment of inertia of a beam about its C.G to the maximum distance of extreme x-section of the beam (Ymax). Strength of Materials - 3 - Question 15

The stress at a point in a bar is 200 MPa tensile. Determine the intensity of maximum shear stress in the material.

Detailed Solution for Strength of Materials - 3 - Question 15 Stress on x face, A(200, 0) and Stress on y face, B(0, 0) Maximum shear stress = Radius of Mohr circle

τmax= σ/2 = 100 MPa

Strength of Materials - 3 - Question 16

The correct relation between Modulus of elasticity (E), Shear Modulus (G) and Bulk modulus (K) is:

Detailed Solution for Strength of Materials - 3 - Question 16

Relation between Modulus of elasticity (E), Shear Modulus (G) and Bulk modulus (K) is given by: Now, rewriting the equation as follows:

3KE + GE = 9KG

3KE – 9KG = - GE

K(3E – 9G) = - GE Strength of Materials - 3 - Question 17

The total area under the stress-strain curve of a mild steel specimen tested up to failure under tension is a measure of its:

Detailed Solution for Strength of Materials - 3 - Question 17

Strength is defined as the ability of the material to resist, without rupture, external forces causing various types of stresses. Breaking strength is the ability of a material to withstand a pulling or tensile force.

Toughness is defined as the ability of the material to absorb energy before fracture takes place. In other words, toughness is the energy for failure by fracture. Toughness is measured by a quantity called modulus of toughness. Modulus of toughness is the total area under a stress-strain curve in tension test, which also represents the work done to fracture the specimen.

Hardness is defined as the resistance of a material to penetration or permanent deformation. It usually indicates resistance to abrasion, scratching, cutting or shaping.

Stiffness or rigidity is defined as the ability of the material to resist deformation under the action of external load. Modulus of elasticity is the measure of stiffness.

Strength of Materials - 3 - Question 18

What is the limit to Poisson's ratio?

Detailed Solution for Strength of Materials - 3 - Question 18

Limit of poisons ratio varies between -1 to 0.5.

μ = 0.5 for rubber.

Strength of Materials - 3 - Question 19

Slenderness ratio of a long column is

Detailed Solution for Strength of Materials - 3 - Question 19

Slenderness ratio ( λ ) of long column is defined as the ratio of Effective length of column to its least radius of gyration. Strength of Materials - 3 - Question 20

The neutral axis of a beam is subjected to _________ stress.

Detailed Solution for Strength of Materials - 3 - Question 20

The neutral axis is an axis in the cross-section of a beam (a member resisting bending) or shaft along which there are no longitudinal stresses or strains. If the section is symmetric, isotropic and is not curved before a bend occurs, then the neutral axis is at the geometric centroid. All fibers on one side of the neutral axis are in a state of tension, while those on the opposite side are in compression.

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## Mock Test Series for SSC JE Mechanical Engineering

3 videos|1 docs|55 tests