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Is it possible to use a capacitor of suitable capacitance instead of a choke coil?
We can use a capacitor of suitable capacitance as a choke coil because the average power consumed per cycle in an ideal capacitor is zero. Therefore, like a choke coil, a condenser can reduce AC without power dissipation.
An a.c. voltage source E= 200 √2 sin 100t is connected across a circuit containing an a.c ammeter and a capacitor of capacitance 1μF. The reading of the ammeter is:
equation of alternating voltage , E = 200√2sin(100t)
compare this equation with E_{0}sin(ωt)
so, E_{0}=200√2 volts
ω= 100 rad/s
now, E_{rms}=E_{0}/√2
= 200√2/√2 = 200 volts .
given, capacitance of capacitor, C = 10^{6} F
so, reactance of capacitor, X_{C}=1/ω_{C}
=1/(10^{6}x100)
=10^{4}
so, the reading of Ammeter, I=E_{rms/}X_{C}
= 200/10^{4} A = 20 × 10^{3} A = 20mA
hence, option (b) is correct.
What is the unit of Capacitive Reactance X_{c}?
The opposition offered by a capacitor for the flow of A.C is called capacitive reactance.
Xc = 1/wC
it's SI unit is ohm
The average power dissipation in pure capacitive circuit is:
As we know,
Average power in ac circuit is given by P=V_{rms}i_{rms}cosϕ
For pure capacitive circuit ϕ=90^{o} so P=0
What is the natural frequency of an LC oscillator?
What is the average power consumed/cycle in ideal capacitor.
P_{av}=(V_{0}i_{0}/2) cosθ
In ideal capacitor θ= π2
Cosθ=Cosθ(π/2)=0
Therefore
P_{av}=0
Capacitive reactance of the capacitor depends upon
Capacitive reactance (symbol XC) is a measure of a capacitor’s opposition to AC (alternating current). Like resistance it is measured in ohms, but reactance is more complex than resistance because its value depends on the frequency (f) of the signal passing through the capacitor. Reactance is also inversely proportional to the value of capacitance (C), i.e. the value of XC at any frequency will be less in larger capacitors than in smaller ones. All capacitors have infinitely high values of reactance at 0Hz, but in large capacitors, the reactance falls to a low level at much lower frequencies than in smaller capacitors. Hence, larger capacitors are preferred in low frequency applications.
he impedance of a 10 microfarad capacitor for 50 Hz ac is:
Impedance(X_{C})=1/ω_{C}
=1/ 2πf λC
=1/2πx50x10x10^{6}
=10^{6}/1000π
X_{C}=10^{3}/π=(1000/π) Ω
Voltage lags current by 90° in a pure capacitive circuit. In a pure capacitive circuit, the instantaneous power may be positive or negative. As with the simple inductor circuit, the 90degree phase shift between voltage and current results in a power wave that alternates equally between positive and negative.
What is the capacitive reactance of 6 x 10^{6} F capacitor for frequency of 10^{6} Hz?
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