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The perimeter of a triangle with two sides of length 15 cm and 12.5 cm is 40 cm. Its third side is
Find the area of an isosceles triangle, whose unequal side is 12 cm and the perimeter of triangle, is 60 cm.
Let the length of equal sides be x.$
Two sides are equal
Then,
x + x + 12 = 60
2x = 48
x = 24 cm
s = (a+b+c)/2
= (12+24+24)/2
60/2
= 30
Area = [s(sa)(sb)(sc)]^{1/2}
= [30(3012)(3024)(3024)]^{1/2}
= [30(18)(6)(6)]^{1/2}
= 36(15)^{1/2}
The lengths of a triangle are 6 cm, 8 cm and 10 cm. Then the length of perpendicular from the opposite vertex to the side whose length is 8cm is:
Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on land and produce different crops to suffice the needs of their family. She divided the land in two equal parts. If the perimeter of the land is 400 m and one of the diagonals is 160 m, the area of each part is
A square sheet whose perimeter is 32 cm is painted at the rate of Rs. 5 per m^{2}. The cost of painting is:
The area of an equilateral triangle of side 14 cm is
An isosceles triangle has perimeter 40 cm and each of the equal sides is 15 cm. The area of the triangle is
The base of a right angled triangle with area 300 cm^{2} and height 30 cm is
The area of a scalene triangle with sides 32 cm, 34 cm and 34 cm is
The sides of a scalene triangle are in the ratio 3:5:7. If the perimeter of the triangle is 60 cm, then its area is :
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