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Test: Area Of Parallelograms


10 Questions MCQ Test Mathematics (Maths) Class 9 | Test: Area Of Parallelograms


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This mock test of Test: Area Of Parallelograms for Class 9 helps you for every Class 9 entrance exam. This contains 10 Multiple Choice Questions for Class 9 Test: Area Of Parallelograms (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Area Of Parallelograms quiz give you a good mix of easy questions and tough questions. Class 9 students definitely take this Test: Area Of Parallelograms exercise for a better result in the exam. You can find other Test: Area Of Parallelograms extra questions, long questions & short questions for Class 9 on EduRev as well by searching above.
QUESTION: 1

Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is:

Solution:
QUESTION: 2

Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is:

Solution:

We know that,

Area of a parallelogram = base ⨯ height

Now, if both parallelograms are on the same base and between the same parallels, then their heights will be equal. Hence, their areas will also be equal.

∴ Option D is correct

QUESTION: 3

In parallelogram ABCD, AL ⊥ CD and CM ⊥ AD. If AL=20cm, CD = 12 cm, CM=8cm, then perimeter of the parallelogram is

Solution:
QUESTION: 4

PQRS is a trapezium in which PQ = 7 cm, PS = QR = 5 cm, RS = x cm and distance between PQ and RS is 4 cm. The area of trapezium is

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Solution:
QUESTION: 5

A triangle and a rhombus are on the same base and between the same parallels. Then the ratio of area of triangle to that rhombus is:
Solution:

If a triangle and a rhombus are on the same base and between the same parallels then the ratio of the areas of the triangle and rhombus is 1 : 2

The base of triangle and rhombus are equal. The rhombus have equal sides, and  one side is the base of triangle.

The are of triangle must be half of the are of rhombus.

QUESTION: 6

ABCD is a parallelogram of area 100 cm2. AE is drawn perpendicular to BC and AF is drawn perpendicular to DC. If AE = 8 cm and AF is equal to 6.25 cm, then AB is

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Solution:
QUESTION: 7

Parallelogram ABCD and rectangle ABEF are on the same base AB. If AB = 14 cm, BC = 12 cm, then the possible value for the perimeter of ABEF is
Solution:

IIgm ABCD and rectangle ABEF are between the same parallels AB and CF.
AB = EF (For rectangle) and AB = CD (For parallelogram)
? CD = EF ? AB + CD = AB + EF ... (1)
Of all the line segments that can be drawn to a given line from a point not lying on it, the perpendicular line segment is the shortest.
? AF < AD
similarly we write , BE < BC ? AF + BE < AD + BC ... (2)
From equations (1) and (2), we get
AB + EF + AF + BE < AD + BC + AB + CD
Perimeter of rectangle ABEF < Perimeter of parallelogram ABCD

Now,  Perimeter of parallelogram ABCD = AB + BC + CD + DA = 14 + 12 + 14 + 12 = 52

Thus, Perimeter of rectangle ABEF < 52 cm

QUESTION: 8

ABCD is a parallelogram, Area(DAB) =
Solution: ABCD is a parallelogram
In a Triangle ABC and ADC
AB=CD(opposite lines of a parallelogram)
BC=AD(opposite lines of a parallelogram)
AC=AC(common)
Triangle ABC and ADC ( SSS Cong. rule)
ar(ABC) =ar(ADC)=1/2 ar (ABCD)
hence proved
QUESTION: 9

In the following figure, if ED = 10 cm, BG = 8 cm and BE = CD = 9 cm, then find the area of triangle CDF.

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Solution:

If a triangle and a parallelogram are on the same base and between the same parallels, then the area of the triangle is equal to half the area of the parallelogram.

Here, the area of the parallelogram = base x height = 10 x 8 = 80 sq cm;

Therefore, the area of the triangle = 1/2 x area of parallelogram

= 1/2 x 80 = 40 sq cm

QUESTION: 10

Find the area of quadrilateral ABCD, if AB || CD and AB = CD is as shown in figure :

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Solution:

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