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What is the area of rectangle if Length = 2m, Breadth = 5m
The area of rectangle is given by length × breadth. So the area is 2 × 5 = 10m2.
The third side of the triangle if the perimeter of a triangle is 20m and two of its sides are 5m and 4m, is
Perimeter of a triangle =1stside+2ndside+3rd side So, 20=5+4+3rdside 3rdside=20−9=11m.
Calculate no. of shaded boxes. It comes out to be 21. And each box has area of 1m2. So the area of shaded region becomes21m2.
The difference between the length and the breadth of a rectangle is 8 cm and the perimeter is 64 cm. Which of the following can be the length and breadth of this rectangle?
Length of rectangle = x cm Breadth of rectangle = (x - 8) cm Perimeter of rectangle = 2(x + x - 8) = 2(2x - 8) Given 2(2x - 8) = 64 ⇒ 2x = 40 ⇒ x = 20 L = 20, B = 20 - 8 = 12
The area of a square is 100 sq. cm. If the sides this square are increased by 10% then what will be the area of new square?
Given area of square = 100 side×side=100=10×10 ⇒Side = 10 cm Increased in side of square = 10% of 10 = 1 ∴ New side = 10 + 1 = 11 ∴ Area of new square =(11)2=121sq.cm.
The area of a square is equal to the area of a rectangle of I = 8 cm and b = 2 cm. What is the side of the square?
Area of rectangle = l×b
l = 8cm,. b= 2 cm
Area of rectangle= ( 8×2)cm
= 16cm^2
Area of rectangle= Area of square
therefore area of the square is 16cm^2
Area of square= (a)^2
√16 = a
Side of the square 4cm
A cuboid measures 24m × 12m × 10m. how many cubes of side 3m can fit in the box?
Given : length = 24 m , breadth= 12 m , height = 10 m
edge of a cube = 3 m
to find how many cubes of side 3 m can fit in the cuboid, let us first find the volume of the cuboid:
volume of the cuboid = l × b × h ⇒ 24×12×10 = 2880 m³
now, volume of cube :
vol of cube = a³ (where 'a' is the side ) ⇒ 3³ = 27 m³
no. of cubes that can fit in the cuboid = volume of the cuboid ÷ volume of the cube
⇒ 2880 ÷ 27 = 106.66 ⇒ 106 cubes
Calculate the area of rectangle given below if each square has an area of 4m2.
There are 2×5=10 squares and each square has an area of 4m2 So, the area of rectangle =2×5×4=40m2.
Area of rectangle is 32m2. If the length is 8m then breadth = ________
Given, area = length × breadth⇒ breadth = area÷length So, the breadth = 32/8 = 4m.
If a figure has sides 4m, 2m, 4m and 2m then which type of figure is this?
There are four sides .So it cannot be circle or triangle. Now, it has 2 pairs of equal sides. So it is a rectangle as the square has all its four sides equal.
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