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This mock test of Test: Areas Of Parallelograms And Triangles- 2 for Class 9 helps you for every Class 9 entrance exam.
This contains 25 Multiple Choice Questions for Class 9 Test: Areas Of Parallelograms And Triangles- 2 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

D,E,F are mid points of the sides BC, CA & AB respectively of ΔABC, then area of BDEF is equal to

Solution:

QUESTION: 2

ABCD is a quadrilateral P,Q,R and S are the mid-points of AB, BC, CD and DA respectively, then PQRS is a

Solution:

QUESTION: 3

The median of a triangle divides it into two

Solution:

QUESTION: 4

The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 16 cm and 12 cm is

Solution:
The fig. formed by joining mid points is parellelogram and area of this parellelogram = 1/2 of the area of rhombs Area of rhombus= 1 /2x12x16 =96;;;;;; or Area of parellelogram= 1/2x96 = 48cm^2

QUESTION: 5

The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm is

Solution:

QUESTION: 6

ABCD is quadrilateral whose diagonal AC divides it into two parts, equal in area, then ABCD

Solution:

Here, ABCD need not be any of rectangle, rhombus and parallelogram because if ABCD is a square, then its diagonal AC also divides it into two parts which are equal in area.

QUESTION: 7

Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is

Solution:

QUESTION: 8

If a triangle and a parallelogram are on the same base and between the same parallels, then the ratio of the area of the triangle to the area of the parallelogram is

Solution:

QUESTION: 9

ABCD is a parallelogram. If AB = 12 cm, AE 7.5 cm, CF = 15 cm, then AD is equal to

Solution:

QUESTION: 10

A, B, C, D are mid-points of sides of parallelogram PQRS. If ar(PQRS)=36cm^{2}, then ar (ABCD) is

Solution:

QUESTION: 11

In the given figure if ar(ΔABCD) = 29cm^{2} and AB = 5.8 cm, then the height of ΔABEF is

Solution:

QUESTION: 12

AP||BQ||CR. If ar(ΔAQC)=17cm^{2}, then ar(ΔPBR) is

Solution:

QUESTION: 13

ABCD is a square. P and Q are mid-point of AB and DC respectively. If AB = 8 cm, then ar(ΔBPD) is

Solution:

QUESTION: 14

PQRS is a parallelogram. If X and Y are mid-points of PQ and SR and diagonal SQ is joined, then ar(ΔXQRY): ar(ΔQSR) is equal to

Solution:

QUESTION: 15

ABCD is a trapezium with parallel sides AB = a cm and DC = b cm. E and F are the mid-points of the non-parallel sides. The ratio of ar (ABFE) to ar (EFCD) is

Solution:

QUESTION: 16

In quadrilateral PQRS, M is the mid-point of PR. If ar (SMQR) is 18cm^{2}, then ar (PQMS) is

Solution:

QUESTION: 17

In the given figure ABCD is a parallelogram and its area is 64cm^{2}. If P is any point in the interior of ΔABCD, then ar(ΔAPD)+ar(ΔPBC) is equal to

Solution:

QUESTION: 18

D and E are mid-points of BC and AD respectively. If ar(ΔABC) = 10cm^{2}, then ar(ΔEBC) is

Solution:

QUESTION: 19

If E and F are mid-points of sides AB and CD respectively and ar(ΔABCD) = 36cm^{2},then ar(APD): ar(DEF)

Solution:

QUESTION: 20

In the given figure, if BC║AE,CD║BE, and ar(ΔBED) = 6cm^{2}, then ar(ΔABC) is

Solution:

QUESTION: 21

PQRS is a parallelogram. A and B are any points on PQ and RQ respectively. If ar(ΔSBR) = 16cm^{2 }and ar(ΔPBQ) = 8cm^{2}, then the area of ΔRAS is

Solution:

QUESTION: 22

ABCD is a parallelogram. P is any point on CD. If ar(ΔDPA) = 15cm^{2} and ar(ΔAPC)=20cm^{2}, thenar(ΔAPB)is

Solution:

QUESTION: 23

M and N are the mid-points of sides DC and AB respectively, of a rectangle ABCD. If ar(rectangle ABCD) = 48cm^{2}, then ar(ΔEMC) is

Solution:

QUESTION: 24

ABCD is a trapezium in which AB║DC.AB║DC. A line through A parallel to BC meets diagonal BD at P. If ar(ΔBPC) = 5cm^{2}, then ar(ΔABD) is

Solution:

QUESTION: 25

PQRS and ADEQ are rectangles. RE║AP. If ar(ACPQ) = 25cm^{2 }and ar(ABEP) = 10cm^{2},then ar (PQRS) is

Solution:

### Areas of Parallelograms & Triangles

Doc | 6 Pages

### Areas of Parallelograms and Triangles

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