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Test: Arun Sharma Based Level 1: Percentages


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15 Questions MCQ Test Quantitative Aptitude (Quant) | Test: Arun Sharma Based Level 1: Percentages

Test: Arun Sharma Based Level 1: Percentages for CAT 2023 is part of Quantitative Aptitude (Quant) preparation. The Test: Arun Sharma Based Level 1: Percentages questions and answers have been prepared according to the CAT exam syllabus.The Test: Arun Sharma Based Level 1: Percentages MCQs are made for CAT 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Arun Sharma Based Level 1: Percentages below.
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Test: Arun Sharma Based Level 1: Percentages - Question 1

What fraction is equal to 57.12% (approximately)?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 1

Test: Arun Sharma Based Level 1: Percentages - Question 2

a% of a + b% of b = 2% of ab, then what percentage of a is b?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 2

Test: Arun Sharma Based Level 1: Percentages - Question 3

Subtracting 48% of N from N is equivalent to multiplying N by

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 3

N - 0.48 N = 0.52 N

Test: Arun Sharma Based Level 1: Percentages - Question 4

The length of rectangle is increased by 30% and the breadth is decreased by 25%. What is the percentage change in the area of the rectangle due to this?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 4

Let Length = 100, Breadth =100 Hence, Area = 10000

Now, Length =130, Breadth = 75 Hence, Area = 130 x 75 = 9750 

Test: Arun Sharma Based Level 1: Percentages - Question 5

The numbers are respectively 30% and 40% of a third number. What percentage is the first number of the second number?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 5

Let 3rd No = 100

1st No. = 30 and 2nd No. = 40 Hence, 1st is 75% of 2nd No.

Test: Arun Sharma Based Level 1: Percentages - Question 6

A man spends 25% of his money on food. After spending 50% of the remaining, he is left with Rs 375. How much money was with that man initially?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 6

Assume that he had initially Rs 100.

After spending on food, money left = Rs 75

After spending 50% of Rs 75, he had Rs 37.5

 

Test: Arun Sharma Based Level 1: Percentages - Question 7

After spending 20% on clothes, 10% on books, 9% on purchasing gift for girl friend and 7% on others, Chandra has a balance of Rs 2,700. How much money was there with him initially?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 7

Let initial Amount = Rs. 100

Money left = 100 – (20 + 10 + 9 + 7)

= Rs. (100 – 46)

= Rs. 54

This 54r = 2700

r = 50

100r = 5000

Test: Arun Sharma Based Level 1: Percentages - Question 8

In an exam of two papers maths and chemistry, 60% of the students pass in maths and 70% pass in chemistry. What is minimum percentage of students who could have failed in both the subjects?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 8

Since, we have to find the minimum percentage, it can be possible that no one has failed in both the subjects.

Test: Arun Sharma Based Level 1: Percentages - Question 9

An amount is lent at y% p.a. simple interest for two years. Instead, had it been lent at 2y% p.a. simple interest for y more years, then the interest would have been five times the earlier interest. Find the value of y.

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 9


Test: Arun Sharma Based Level 1: Percentages - Question 10

Find the least number of integral years in which a sum of money invested at 20% compound interest per annum will become more than double itself.

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 10

Test: Arun Sharma Based Level 1: Percentages - Question 11

In the country of Tattoland, a new term tercentage has been introduced in the place of percentage. While percentage is per 100, tercentage is per 125. What will be the tercentage marks obtained by a student in Tattoland if his percentage of marks is 60?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 11

The numerator has been increased by 25%. Hence, denominator will also increase by 25%.
Value in tercentage = 60 x 1.25 = 75 tercentage

Test: Arun Sharma Based Level 1: Percentages - Question 12

In a maternity centre, 5% of all the childbirth cases result in twins. What is the approximate percentage of twins out of total children born?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 12

 Let there be x number of birth cases.
Thus, the number of birth cases of twins = (5*x)/100 = x/20
So the total number of children born are = x + (x/20)(since in cases of twins there is an additional child) = 21x/20
Total number of twin born = (x/20)* 2 = x/10
percentage of twins in the total population born = ((x/10)/(21x/20)) * 100 = 9.5 %

Test: Arun Sharma Based Level 1: Percentages - Question 13

A, B and C donate 8%, 7% and 9%, of their salaries, respectively to a charitable trust. The salaries of A and B are same and the difference between their donations is 259. The total donation of A and B is 1185 more than that of C. The total donation of A and C is what percentage of the total salaries of A, B and C?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 13

Let salaries of A and B be Rs. x and salary of C be Rs. y, then

8x/100 – 7x/100 = 259

⇒ x/100 = 259

⇒ x = 25900

Salaries of A and B is Rs. 25900.

Donation of A and B = 25900 × (8 + 7)/100 = 25900 × 15/100 = 3885

Donation of C = 3885 – 1185 = 2700

y × (9/100) = 2700

⇒ y = 30,000

Sum of salaries of A, B and C = 25900 + 25900 + 30000 = 81800

Donation of A = 259 × (8/100) = 2072

Total donation of A and C = 2072 + 2700 = 4772

Percentage of total donation of total salaries of A, B and C = (4772/81800) × 100 = 5.8%

Short Trick:

Let salaries of A, B be 100%

⇒ 8% – 7% = 259

⇒ 1% = 259

⇒ 8% = 2072

⇒ 15% = 3885

⇒ 100% = 25900

Donation of C = 3885 – 1185 = 2700

⇒ 9% = 2700

⇒ 100% = 30,000

Total donation of A and C = 2072 + 2700 = 4772

Total salaries of A, B and C = 25900 + 25900 + 30000 = 81800

∴ Required percentage = 4772/81800 × 100 = 5.8%

Test: Arun Sharma Based Level 1: Percentages - Question 14

In solution of sugar and water the ratio of sugar and water by weight is 1:4. This solution is heated and in the process it loses 50% weight. What is the ratio of weight of sugar and water in the final mixture?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 14

Weight of solution = (1+4) = 5 units weight of sugar = 1 unit weight of water after heating =1.5 units Required ration =1 : 1.5 = 2 : 3

Test: Arun Sharma Based Level 1: Percentages - Question 15

Dataman Infosys Systems is a Lucknow-based software company which is growing tremendously. It doubled its turnover in 1998 from Rs 50 crores in 1997. Then it tripled its turnover in 1999 and grew by 50% in 2000. What is the turnover at the end of 2000?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 15

Turnover in 1998 = Rs 100 cr Turnover in 1999 = Rs 300 cr Turnover in 2000 = Rs 450 cr

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