Test: BITSAT Mock Test- 7

Test: BITSAT Mock Test- 7 - Question 1

Same current is flowing in two alternating circuits. The first circuit contains only inductance and the other contains only a capacitor. If the frequency of the e.m.f. of A.C. is increased, the effect on the value of the current will be

A.
Increases in the first circuit and decreases in the other
B.
Increases in both the circuits
C.
Decreases in the both the circuits
D.
Decreases in the first circuit and increases in the other

Test: BITSAT Mock Test- 7 - Question 2

Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. the spectral lines emitted by hydrogen atoms according to Bohr's theory will be

A.
One
B.
Two
C.
Three
D.
Four

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 2

Test: BITSAT Mock Test- 7 - Question 3

Heavy water has molecular weight

A.
20
B.
18
C.
19
D.
36

Test: BITSAT Mock Test- 7 - Question 4

Two coils are placed close to eachother. The mutual inductance of the pair of coils depends upon

A.
The rates at which currents are changing in the two coils
B.
Relative position and orientation of the two coils
C.
The materials of the wires of the coils
D.
The currents in the coils

Test: BITSAT Mock Test- 7 - Question 5

An infinite number of identical capacitors, each of capacitance 1 μ F, are connected as in the figure. The equivalent capacitance between 'A' and 'B' is

A.
1/2 μ F
B.
1 μ F
C.
2 μ F
D.
∞

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 5

Test: BITSAT Mock Test- 7 - Question 6

Consider the following statements concerning electrons :(I) Electrons are universal constitutents of matter (II) J.J. Thomson received the very first Nobel Prize in Physics for discovering the electron (III) The mass of the electron is about 1/2000 of that of a neutron (IV) According to Bohr the linear momentum of the electron is quantised in the hydrogen atom. Which of the above statements are NOT correct ?

A.
I,II and IV
B.
II and IV
C.
III and IV
D.
II and III

Test: BITSAT Mock Test- 7 - Question 7

A cell of emf E has a resistance R connected across it, and a voltmeter measures the potential difference across the terminals of the cell is V. The internal resistance of the cell is

A.
RV (E-V)
B.
R(E-V)/V
C.
ER(V+E)/E-V
D.
V(E-V)R/E

Test: BITSAT Mock Test- 7 - Question 8

If work function of metal is 3 eV then threshold wavelength will be

A.
4125 +
B.
4000 +
C.
4500 +
D.
5000 +

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 8 Work function = hvoTherefore vo = WO/h = 3 x 1.602 x 10^-19 / 6.626 x 10^-34= 0.724 x 10^15/secThreshold Wavelength: λo =c/vo = 3x10^8 / 0.724 x 10^15 = 4.143 x 10^7 m

Test: BITSAT Mock Test- 7 - Question 9

Specific resistance of a wire depends upon

A.
Length
B.
Crossectional area
C.
Mass
D.
None

Test: BITSAT Mock Test- 7 - Question 10

If 4 * 10²⁰ eV of energy is required to move a charge of 0•25 coluomb between two points, the p.d between them is

A.
256 V
B.
512 V
C.
123V
D.
215 V

Test: BITSAT Mock Test- 7 - Question 11

On a rough horizontal surface, a body of mass 2 kg is given a velocity of 10 m/s. If the coefficient of friction is 0.2 and g=10 m/s², the body will stop after covering a distance of

A.
10 m
B.
25 m
C.
50 m
D.
250 m

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 11

Test: BITSAT Mock Test- 7 - Question 12

If acceleration due to gravity on the surface of a planet is two times that on surface of earth and its radius is double that of earth. Then escape velocity from the surface of that planet in comparison to earth will be

A.
2 Ve
B.
3 Ve
C.
4 Ve
D.
None of these

Test: BITSAT Mock Test- 7 - Question 13

If 10% of the current passes through a moving coil galvanometer of resistance 99 ohm, then the shunt resistance will be

A.
9.9 Ω
B.
11 Ω
C.
10 Ω
D.
9 Ω

Test: BITSAT Mock Test- 7 - Question 14

The absolute temperature of a gas is determined by

A.
The average momentum of the molecules
B.
The velocity of sound in the gas
C.
The number of molecules in the gas
D.
The mean square velocity of the molecules

Test: BITSAT Mock Test- 7 - Question 15

Curie temperature is the temperature above which

A.
Ferromagnetic material becomes diamagnetic material .
B.
Ferromagnetic material becomes paramagnetic material .
C.
Paramagnetic material becomes diamagnetic material.
D.
Paramagnetic material becomes ferromagnetic material .

Test: BITSAT Mock Test- 7 - Question 16

The temperature of a body falls from 50^oC to 40^oC in 10 minutes. If the temperature of the surroundings is 20^oC Then temperature of the body after another 10 minutes will be

A.
36.6^oC
B.
33.3^oC
C.
35^oC
D.
30^oC

Test: BITSAT Mock Test- 7 - Question 17

A river water is flowing at 0.5 m-s⁻¹. The shearing stress between horizontal layers at a distance of 10 cm of the river water is (Viscosity of water = 0.01 poise)

A.
1*10⁻³ N−m⁻²
B.
5*10⁻³ N−m⁻²
C.
2.5*10⁻³ N−m⁻²
D.
7.5*10⁻³ N−m⁻²

Test: BITSAT Mock Test- 7 - Question 18

If an air-bubble of radius 0.4 mm at a depth h in water having surface tension of 72*10⁻³ N-m⁻¹ and density 1000 kg-m⁻³ is in equilibrium then, the value of h is (Take g=10 m-s⁻²)

A.
14.4 cm
B.
7.2 cm
C.
3.6 cm
D.
1.8 cm

Test: BITSAT Mock Test- 7 - Question 19

Which of the following affets the elasticity of a substance?

A.
hammering and annealing
B.
change in temperature
C.
impurity in substance
D.
all of these

Test: BITSAT Mock Test- 7 - Question 20

A rocket is fired upward from the earth's surface such that it creates an acceleration of 19.6 m/sec². If after 5 sec its engine is switched off, the maximum height of the rocket from earth's surface would be

A.
245 m
B.
490 m
C.
980 m
D.
735 m

Test: BITSAT Mock Test- 7 - Question 21

A stone projected with a velocity u at an angle θ with the horizontal reaches maximum height H₁. When it is projected with velocity u at an angle (π/2 -θ) with the horizontal, it reaches maximum height H₂. The relation between the horizontal range R of the projectile, H₁ and H₂ is

A.
R = 4√H₁H₂
B.
R = 4(H₁ - H₂)
C.
R = 4(H₁ + H₂)
D.
R = H₁²/H₂²

Test: BITSAT Mock Test- 7 - Question 22

An impulse applied to a moving object with the force at an angle of 120 ^o with respect to the velocity vector. The angle between impulse vector and change in momentum vector is

A.
0 ^o
B.
2 ^o
C.
3 ^o
D.
10 ^o

Test: BITSAT Mock Test- 7 - Question 23

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is

A.
90^o
B.
60^o
C.
45^o
D.
30^o

Test: BITSAT Mock Test- 7 - Question 24

The focal lengths of the objective and eye lenses of a telescope are 200 cm and 5 cm respectively. The maximum power of the telescope will be

A.
40
B.
48
C.
60
D.
100

Test: BITSAT Mock Test- 7 - Question 25

The length of a simple pendulum is increased by 1%. Its time period will

A.
Increase by 2%
B.
Increase by 1%
C.
Increase by 0.5%
D.
Decrease by 0.5%

Test: BITSAT Mock Test- 7 - Question 26

A simple pendulum executing simple harmonic motion is falling freely along with the support. Then

A.
Its periodic time increases
B.
It does not oscillate at all
C.
Its periodic time decreases
D.
None of these

Test: BITSAT Mock Test- 7 - Question 27

A body A of mass M while falling vertically downwards under gravity breaks into two parts, a part B of mass M/3 and body C of mass 2M/3. The centre of mass of the bodies B and C taken together

A.
does not shift
B.
shifts towards body B
C.
shifts towards body C
D.
depends upon height of breaking

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 27 No horizontal external force is acting
∴ a_cm = 0
since v_cm = 0
∴ Δx_cm = 0

Test: BITSAT Mock Test- 7 - Question 28

The moment of inertia of a thin uniform circular disc about one of the diameters is I. Its moment of inertia about an axis perpendicular to the circular surface and passing through the centre is

A.
√ 2 I
B.
2 I
C.
I ∕ √ 2
D.
I ∕ 2

Test: BITSAT Mock Test- 7 - Question 29

Moment of inertia of a uniform horizontal solid cylinder of mass M about an axis passing through its edge and perpendicular to the axis of the cylinder when its length is 6 times its radius 'R' is

A.
39 MR²/4
B.
39 MR/4
C.
49 MR/4
D.
49 MR²/4

Test: BITSAT Mock Test- 7 - Question 30

A point object O is placed at 15 cm in front of a glass rod having spherical end of radius of curvature 30 cm. The image would be formed at

A.
30 cm left
B.
Infinity
C.
1 cm to the right
D.
18 cm to the left

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 30

Here, μ₁ = 1, μ₂ = 1.5, u = - 15 cm,
R = + 30 cm, v = ?
Refraction from rearer to denser medium,

Test: BITSAT Mock Test- 7 - Question 31

A fuse wire with radius 1 mm blows at 1.5 amp. The radius of the fuse wire of the same material to blow at 3A will be

A.
4¹/³ mm
B.
3¹/4 mm
C.
21/2 mm
D.
31/2 mm

Test: BITSAT Mock Test- 7 - Question 32

The internal energy of the gas increases when

A.
In adiabatic expansion
B.
In adiabatic compression
C.
In isothermal expansion
D.
In isothermal compression

Test: BITSAT Mock Test- 7 - Question 33

In which of the following systems of unit, Weber is the unit of magnetic flux.

A.
CGS
B.
MKS
C.
SI
D.
None of these

Test: BITSAT Mock Test- 7 - Question 34

A reversible engine converts one-sixth of the heat into work. When temperature of sink is reduced by 62^oC, the efficiency of the engine is doubled. The temperature of source and sink are

A.
80^oC and 28^oC
B.
90^oC and 32^oC
C.
95^oC and 35^oC
D.
99^oC and 37^oC

Test: BITSAT Mock Test- 7 - Question 35

When a source is linear, the wavefront is

A.
Plane
B.
Spherical
C.
Cylindrical
D.
None of these

Test: BITSAT Mock Test- 7 - Question 36

If the two slits in Young's experiment have width ratio 1:4, the ratio of intensity at maxima and minima in the interference pattern in

A.
3 : 1
B.
1 : 3
C.
9 : 1
D.
1 : 9

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 36

Test: BITSAT Mock Test- 7 - Question 37

A standing wave having 3 nodes and 2 antinodes is formed between two atoms having a distance 1.21 Å between them. The wavelength of the standing wave is

A.
1.21 Å
B.
2.42 Å
C.
6.05 Å
D.
3.63 Å

Test: BITSAT Mock Test- 7 - Question 38

In a sinusoidal wave, the time required for a particular point to move from maximum displacement is 0.5 s. The frequency of wave is

A.
0.1 Hz
B.
0.25 Hz
C.
0.5 Hz
D.
1.5 Hz

Test: BITSAT Mock Test- 7 - Question 39

A stationary particle explodes into two particles of masses m₁ and m₂, which move in opposite directions, with velocities ν₁ and ν₂. The ratio of their kinetic energies (E₁/E₂) is

A.
m₂/m₁
B.
m₁/m₂
C.
1
D.
m₁ν₁/m₂ν₂

Test: BITSAT Mock Test- 7 - Question 40

A ball of mass 'm' moving with velocity 'V' collides with an identical ball at rest. After collision the first ball comes to rest. The speed of the other ball is

A.
V
B.
V/2
C.
2 V
D.
0

Test: BITSAT Mock Test- 7 - Question 41

Which of the following compounds does not react with metallic sodium?

A.
CH₃CH(OH)CH₃
B.
CH₃ $―$ O $―$ CH₃
C.
CH₃COOH
D.
C₂H₅OH

Test: BITSAT Mock Test- 7 - Question 42

The organic compound which will answer the Fehling solution test is

A.
Ethanol
B.
Acetone
C.
Maltose
D.
Benzaldehyde

Test: BITSAT Mock Test- 7 - Question 43

If r is the radius of first orbit, the radius of nth orbit of the H atom will be

A.
r n²
B.
r n
C.
r/n
D.
r²n²

Test: BITSAT Mock Test- 7 - Question 44

The no. of unpaired electrons in an element with electronic configuration 1s²,2s²,3p² is

A.
1
B.
2
C.
3
D.
5

Test: BITSAT Mock Test- 7 - Question 45

Heterolytic fission of a covalent bond in organic molecules gives

A.
Free radicals
B.
Cations and anions
C.
Only cations
D.
Only anions

Test: BITSAT Mock Test- 7 - Question 46

Point out the incorrect statement about resonance?

A.
Resonance structures should have equal energy
B.
In resonance structures, the constituent atoms must be in the same position
C.
In resonance structures, there should not be same number of electron pairs
D.
Resonance structures should differ only in the location of electrons around the constituent atoms.

Test: BITSAT Mock Test- 7 - Question 47

Which of the following does not have sp²-hybridised carbon?

A.
acetone
B.
acetamide
C.
acetonitrile
D.
acetic acid

Test: BITSAT Mock Test- 7 - Question 48

Which of the following is an electrophile?

A.
H₂O
B.
NH₃
C.
AlCl₃
D.
C₂H₅NH₂

Test: BITSAT Mock Test- 7 - Question 49

The aldehyde which is formed during photosynthesis in plants is

A.
Methanal
B.
Acetaldehyde
C.
Propanal
D.
Phenyl methanol

Test: BITSAT Mock Test- 7 - Question 50

Molish's test is answered by

A.
all carbohydrates
B.
sucrose
C.
fructose
D.
glucose

Test: BITSAT Mock Test- 7 - Question 51

In a reaction involving ring substitution of C₆H₅Y, the major product is meta isomer. The group Y can be

A.
-NH₂
B.
-COOH
C.
-CH₃
D.
-Cl

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 51 Electron withdrawing groups favour meta substitution
- COOH group is metadirecting group

Test: BITSAT Mock Test- 7 - Question 52

For an exothermic reaction, the value of

A.
∆E is negative
B.
∆H is positive
C.
∆H is negative
D.
∆H is equal to zero

Test: BITSAT Mock Test- 7 - Question 53

Which one of the following molecules is paramagnetic?

A.
CO₂
B.
SO₂
C.
NO
D.
H₂O

Test: BITSAT Mock Test- 7 - Question 54

when a catalyst is added to a reversible reaction in equilibrium state, the value of equilibrium constant

A.
increases
B.
decreases
C.
becomes zero
D.
does not change

Test: BITSAT Mock Test- 7 - Question 55

1 dm³ of 2 M CH₃COOH is mixed with 1 dm³ of 3 M ethanol to form ester. The decrease in the initial rate if each solution is diluted with an equal volume of water would be

A.
2 times
B.
4 times
C.
0.25 times
D.
0.5 times

Test: BITSAT Mock Test- 7 - Question 56

Which of the following has highest first ionization potential?

A.
Carbon
B.
Oxgyen
C.
Nitrogen
D.
Boron

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 56

Nitrogen has highest first ionization potential. This is because N contains exactly half-filled p-orbitals which is extra stable. hence its first ionisation potential is high.
Electronic configuration of N:

Test: BITSAT Mock Test- 7 - Question 57

The densities of graphite and diamond at 298 K are 2.25 and 3.31 g-cm^-3 respectively. If the standard free energy difference (ΔG^o)is equal to 1895 J-mol^-1, then pressure at which graphite will be transformed into diamond at 298 K is

A.
7.92 x 10⁸ Pa
B.
9.92 x 10⁸ Pa
C.
9.92 x 10¹⁰ Pa
D.
9.92 x 10¹⁸ Pa

Test: BITSAT Mock Test- 7 - Question 58

The chloramphenicol is an example of

A.
antibiotic
B.
antipyretic
C.
antiseptic
D.
sulpha drug

Test: BITSAT Mock Test- 7 - Question 59

Which of the following is an inner orbital complex as well as diamagnetic in behaviour?

A.
[Zn(NH₃)₆]²⁺
B.
[Cr(NH₃)₆]³⁺
C.
[Co(NH₃)₆]³⁺
D.
[Ni(NH₃)₆]²⁺

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 59 Co³⁺ has 3d⁶ configuration and in the formation of the complex it assumes d²sp³ hybrid state and is, therefore, inner orbital complex

Test: BITSAT Mock Test- 7 - Question 60

The aqueous solution containing which of the following ions will be colourless?

A.
Sc³⁺
B.
Fe²⁺
C.
Ti³⁺
D.
Mn²⁺

Test: BITSAT Mock Test- 7 - Question 61

Which of the following is a synthetic element?

A.
C
B.
U
C.
Np
D.
Ra

Test: BITSAT Mock Test- 7 - Question 62

The standard reduction potentials of 4 elements are given below.Which of the following will be the most suitable reducing agent?
I = -3.04 V, II = -1.90 V, III =0 V,IV = 1.90 V

A.
I
B.
II
C.
III
D.
IV

Test: BITSAT Mock Test- 7 - Question 63

Of the five isomeric hexanes,the isomer which can give two monochlorinated compounds is

A.
2-methylpentane
B.
2,2-dimethylbutane
C.
2,3-dimethylbutane
D.
n-hexane

Test: BITSAT Mock Test- 7 - Question 64

A war gas Lewisite is formed by reaction of arsenic chloride with

A.
CH₄
B.
C₆H₆
C.
C₂H₂
D.
C₂H₄

Test: BITSAT Mock Test- 7 - Question 65

The chemical formula of lead sulphate is

A.
Pb₂SO₄
B.
Pb(SO₄)₂
C.
PbSO₄
D.
Pb₂(SO₄)₃

Test: BITSAT Mock Test- 7 - Question 66

Silver nitrate solution is gradully added to an aqueous solution containing 0.01 M each of chloride ,bromide and iodide ions .The correct sequence in which the halides will be precipitated is

A.
Br⁻,Cl⁻,I⁻
B.
I⁻,Cl⁻,Br⁻
C.
I⁻,Br⁻,Cl⁻
D.
Br⁻,I⁻,Cl⁻

Test: BITSAT Mock Test- 7 - Question 67

Which of the following is an isomer of propanal?

A.
acetone
B.
propane
C.
propanol
D.
propionic acid

Test: BITSAT Mock Test- 7 - Question 68

Ethyl bromide can be obtained by the action of HBr on

A.
propene
B.
acetylene
C.
ethanol
D.
ethane

Test: BITSAT Mock Test- 7 - Question 69

The chemical used for cooling in refrigeration is

A.
CO₂
B.
NH₄OH
C.
NH₄Cl
D.
Liquid NH₃

Test: BITSAT Mock Test- 7 - Question 70

Oxygen will directly react with each of the following elements except

A.
P
B.
Cl
C.
Na
D.
S

Test: BITSAT Mock Test- 7 - Question 71

Liquid ammonia is used for refrigeration because

A.
it has a high dipole moment
B.
it has a high heat of vaporisation
C.
it is basic
D.
it is a stable compound

Test: BITSAT Mock Test- 7 - Question 72

Oxygen molecule is

A.
Diamagnetic with no unpaired electrons
B.
Diamagnetic with two unpaired electrons
C.
Paramagnetic with two unpaired electrons
D.
Paramagnetic with no unpaired electrons

Test: BITSAT Mock Test- 7 - Question 73

B(OH)₃ is

A.
Monobasic acid
B.
Dibasic acid
C.
Tribasic acid
D.
Basic

Test: BITSAT Mock Test- 7 - Question 74

Which is a protein?

A.
Nylon
B.
Rayon
C.
Natural silk
D.
Terylene

Test: BITSAT Mock Test- 7 - Question 75

Which of the following oxides is paramagnetic?

A.
Na₂O
B.
Na₂O₂
C.
K₂O
D.
KO₂

Test: BITSAT Mock Test- 7 - Question 76

What are the metal ions present in carnalite?

A.
Mg, K
B.
Al, Na
C.
Na, Mg
D.
Zn, Mg

Test: BITSAT Mock Test- 7 - Question 77

The vapour pressure of two liquids P ans Q are 80 and 60 torr, respectively. The total vapour pressure of solution obtained by mixing 3 moles of P and 2 moles of Q would be

A.
20 torr
B.
68 torr
C.
72 torr
D.
140 torr

Test: BITSAT Mock Test- 7 - Question 78

Select one correct statement. In the gas equation, PV = nRT

A.
n is the number of molecules of a gas
B.
n moles of the gas have a volume V
C.
V denotes volume of one mole of the gas
D.
P is the pressure of the gas when only one mole of gas is present

Test: BITSAT Mock Test- 7 - Question 79

Atomic weight of bromine is 80,0.1 mole of ethylene absorbs following gram of bromine

A.
8
B.
16
C.
4
D.
3

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 79

Test: BITSAT Mock Test- 7 - Question 80

Which of the following collodial solution used in photography?

A.
colloidal silver
B.
colloidal gold
C.
colloidal sulphur
D.
colloidal silver bromide

Test: BITSAT Mock Test- 7 - Question 81

The area bounded by the x-axis and the curve y = 4x - x² - 3, is

A.
4/3
B.
3/4
C.
7
D.
3/2

Test: BITSAT Mock Test- 7 - Question 82

The term independent of x in the expansion of [(x^1/3/2)+(x^-1/5)]⁸ is

A.
11
B.
10
C.
8
D.
7

Test: BITSAT Mock Test- 7 - Question 83

The coordinates of a point from which tangents drawn to three circles x²+y²=1, x²+y²+8x+15=0, x²+y²+10y+24=0 are equal in length, are

A.
(-2,1)
B.
(1,-2)
C.
(2,3)
D.
(-2,-(5/2))

Test: BITSAT Mock Test- 7 - Question 84

The number of common tangents to the circles x² + y² = 4 and x² + y² - 8x + 12 = 0 is

A.
1
B.
2
C.
3
D.
4

Test: BITSAT Mock Test- 7 - Question 85

The value of arg [(1-i√3)/(1+i√3)] is

A.
60^o
B.
120^o
C.
210^o
D.
240^o

Test: BITSAT Mock Test- 7 - Question 86

The number of points at which the function f(x)=|x-0.5|+|x-1|+tanx is not differentiable in (0,2) is

A.
1
B.
2
C.
3
D.
4

Test: BITSAT Mock Test- 7 - Question 87

The differential equation of the family of curves y²=4a (x+a) is

A.
y²=4 dy/dx (x+dy/dx)
B.
y²(dy/dx)²+2xy dy/dx-y²=0
C.
2y dy/dx =4a
D.
y² dy/dx+4y=0

Test: BITSAT Mock Test- 7 - Question 88

The general solution of the differential equation dy/dx=y/x is

A.
y=k/x,k constant
B.
y=k log x
C.
y=kx
D.
log y=kx

Test: BITSAT Mock Test- 7 - Question 89

y = Ae^x + Be^2x + Ce^{3 x}

satisfies the diferential equation

A.
y ‴ − 6 y ″ + 11 y ′ − 6 y = 0
B.
y ‴ + 6 y ″ + 11 y ′ + 6 y = 0
C.
y ‴ + 6 y ″ − 11 y ′ + 6 y = 0
D.
y ‴ − 6 y ″ − 11 y ′ + 6 y = 0

Test: BITSAT Mock Test- 7 - Question 90

A.
B.
C.
D.

Test: BITSAT Mock Test- 7 - Question 91

2/1! + 4/3! + 6/5! + .........∞ is equal to

A.
e
B.
e⁻¹
C.
e-1
D.
e+1

Test: BITSAT Mock Test- 7 - Question 92

The area of the region bounded by the curves y = |x-1| and y = 3-|x| is

A.
3 sq. units
B.
4 sq. units
C.
6 sq. units
D.
2 sq. units

Test: BITSAT Mock Test- 7 - Question 93

If f(x) = 0, when x is rational
x, when x is irrational,
g(x) = x, when x is rational
0, when x is irrational
then f - g is

A.
One-One onto
B.
One-One not onto
C.
Not one-one but onto
D.
Not one-one not onto

Test: BITSAT Mock Test- 7 - Question 94

A house subtends a right angle on the window of its opposite house and the angle of elevation of the window from the foot of the former houses is 60^o. If the distance between houses is 6 metres, then the height of the former house is

A.
6√3m
B.
8√3m
C.
4√3m
D.
24m

Test: BITSAT Mock Test- 7 - Question 95

The product of the perpendicular, drawn from any point on a hyperbola to its asymptotes is

A.
ab/√a + √b
B.
ab/a² + b²
C.
a²b²/a² + b²
D.
a² + b²/a²b²

Test: BITSAT Mock Test- 7 - Question 96

If sin⁻¹x+sin⁻¹y=(2π/3), then cos⁻¹x+cos⁻¹y=

A.
2π/3
B.
π/3
C.
π/6
D.
π

Test: BITSAT Mock Test- 7 - Question 97

The slope of the tangent at (x, y) to a curve passing through (2, 1) is (x² + y²)/2xy, then the equation of the curve is

A.
2 (x² - y²) = 3 x
B.
2 (x² - y²) = 6 y
C.
x (x² - y²) = 6
D.
x (x² + y²) = 10

Test: BITSAT Mock Test- 7 - Question 98

A.
4006/3006
B.
4003/3007
C.
4006/3008
D.
4006/3009

Test: BITSAT Mock Test- 7 - Question 99

If A is a square matrix, then A - A is

A.
unit matrix
B.
null matrix
C.
A
D.
a skew symmetric matrix

Test: BITSAT Mock Test- 7 - Question 100

If each element of a 3 * 3 matrix is multiplie by 3, then the determinant of the newly formed matrix is

A.
3 det A
B.
9 det A
C.
27 det A
D.
(det A)³

Test: BITSAT Mock Test- 7 - Question 101

If x + y = 12, then the minimum value of x² + y² is

A.
72
B.
144
C.
48
D.
36

Test: BITSAT Mock Test- 7 - Question 102

Which of the following is correct

A.
5 + 3i > 6 + 4i
B.
5 + 3i = 6 + 4i
C.
5 + 3i < 6 + 4i
D.
none of these

Test: BITSAT Mock Test- 7 - Question 103

The angle between pair of lines represented by x²+2xy-y²=0 is

A.
π/3
B.
π/6
C.
π/2
D.
0

Test: BITSAT Mock Test- 7 - Question 104

If in a Binomial Distribution n = 4, P(X = 0) = 16/81, then P(X = 4)

A.
1/8
B.
1/27
C.
1/81
D.
1/16

Test: BITSAT Mock Test- 7 - Question 105

Two finite sets have m and n elements, the total number of subsets of the first set is 56 more than the total number of subsets of the second. The value of m and n are respectively

A.
7, 6
B.
6, 3
C.
5, 1
D.
8, 7

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 105

Let A denote the first set and B denote the second set
We have, n(A) = 2^m and n(B) = 2ⁿ
As per the question, we have
n(A) = 56 + n(B)
⇒ n(A) - n(B) = 56
⇒ 2^m - 2ⁿ = 56
⇒ 2ⁿ (2^{m - n} - 1)
⇒ 2ⁿ (2^{m - n} - 1) = 8 * 7
⇒ 2ⁿ = 8 = 2³ or (2^{m - n} - 1) = 7
⇒ n = 3 or 2^{m - n} = 8 = 2³ = 2^{6 - 3}
⇒ n = 3 or m - n = 3
⇒ n = 3 or m = 6
Hence, the required values of m and n are 6 and 3 respectively

Test: BITSAT Mock Test- 7 - Question 106

The equation of the normal to the curve x² = 4y at (1, 2) is

A.
$2 x + y + 4 = 0$
B.
$2 x + y - 4 = 0$
C.
$2 x - y + 4 = 0$
D.
$2 x - y - 4 = 0$

Test: BITSAT Mock Test- 7 - Question 107

The parabola (y + 1)² = a x − 2 passes through the point 1, − 2 . The equation of its directrix is

A.
4 x + 1 = 0
B.
4 x − 1 = 0
C.
4 x + 9 = 0
D.
4 x − 9 = 0

Test: BITSAT Mock Test- 7 - Question 108

P,Q,R and S have to deliver lecture, then in how many ways can the lectures be arranged?

A.
4
B.
12
C.
256
D.
24

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 108 Total no. of ways delivering lectures = ⁴P₄ = 4! = 24

Test: BITSAT Mock Test- 7 - Question 109

A speaks truth in 75% cases and B speaks truth in 80% cases. The probability that they contradict each other in a statement is

A.
7/20
B.
13/20
C.
3/5
D.
2/5

Test: BITSAT Mock Test- 7 - Question 110

In Δ A B C , if the line joining the circumcentre 'O' and the incentre I is parallel to BC ,then cosB + cosC =

A.
3/2
B.
1
C.
3/4
D.
2

Test: BITSAT Mock Test- 7 - Question 111

If the roots of the equation 1/ x + p + 1/ x + q = 1/r are equal in magnitude but opposite in sign, then (p + q) equals

A.
2r
B.
r
C.
- 2r
D.
none of htese

Test: BITSAT Mock Test- 7 - Question 112

A.
1
B.
2
C.
3
D.
4

Test: BITSAT Mock Test- 7 - Question 113

The sum of first 24 terms of an A.P. a₁, a₂, a₃, .... ; if it is known that a₁ + a₅ + a₁₀ + a₁₅ + a₂₀ + a₂₄ = 225, is equal to

A.
90
B.
180
C.
900
D.
1800

Test: BITSAT Mock Test- 7 - Question 114

If x, y, z are positive real numbers, then (x³/z) < (x³ + y³ + z³)/(x + y + z) < (z³/x) if

A.
x < y < z
B.
x > y > z
C.
x < y > z
D.
x > y < z

Test: BITSAT Mock Test- 7 - Question 115

The 6th term of a G.P. is 32 and its 8th term is 128 ; then the common ratio of the G.P. is

A.
-1
B.
2
C.
4
D.
-4

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 115

Test: BITSAT Mock Test- 7 - Question 116

The foot of perpendicular from (2,4) on the line x+y=1 is

A.
[(1/2),(3/2)]
B.
[-(1/2),(3/2)]
C.
[(1/2),(-3/2)]
D.
[-(1/2),(-3/2)]

Test: BITSAT Mock Test- 7 - Question 117

If f (x) = log ((1 + x)/(1 - x)), then f (x) is

A.
even
B.
f (x₁) f(x₂) = f (x₁ + x₂)
C.
f(x₁)/f(x₂) = f (x₁ - x₂)
D.
odd

Test: BITSAT Mock Test- 7 - Question 118

The two curves x = y², xy = a³ cut arthogonally at a point, then a² =

A.
1/3
B.
1/2
C.
2
D.
3

Test: BITSAT Mock Test- 7 - Question 119

The distance between the parallel planes x + 2y - 3z = 2 and 2x + 4y - 6z + 7 = 0 is

A.
2/√14
B.
11/√56
C.
7/√56
D.
none of these

Test: BITSAT Mock Test- 7 - Question 120

The shortest distance between the lines (x - 1)/2 = (y - 2)/3 = (z - 3)/4 and (x - 2)/3 = (y - 4)/4 = (z - 5)/5 is

A.
1/6
B.
1/√6
C.
1/√3
D.
1/3

Test: BITSAT Mock Test- 7 - Question 121

The period of sinθ-√3 cosθ is

A.
π/4
B.
π/2
C.
π
D.
2π

Test: BITSAT Mock Test- 7 - Question 122

If vectors (i+j+k),(5i+3j-3k) and (2i+5j+9k) are the position vectors of vertices of any triangle then its perimeter is

A.
15+√157
B.
15-√157
C.
√15-√157
D.
√15+√157

Test: BITSAT Mock Test- 7 - Question 123

Find the Antonym of the word occurring in the sentence in capital letter as per the context.
The criminal was known to the police by VARIOUS names.

A.
Separate
B.
Distinct
C.
Identical
D.
Similar

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 123 'Various' means several and different

Test: BITSAT Mock Test- 7 - Question 124

The sine of the angle between the vectors 3i+2j-k and 12i+5j-5k is

A.
[(√115)/(√14)(√194)]
B.
[(51)/(√14)(√144)]
C.
[(√64)/(√14)(√194)]
D.
none of these

Test: BITSAT Mock Test- 7 - Question 125

The value of cos 12^o+cos 84^o+cos 156^o+cos 132^o is

A.
1/2
B.
1
C.
-1/2
D.
1/8

Test: BITSAT Mock Test- 7 - Question 126

All the values of x satisfying sin 2 x + sin 4 x = 2 sin 3 x are

A.
B.
2 n π
C.
n π
D.

Test: BITSAT Mock Test- 7 - Question 127

Find the Antonym of RISIBLE

A.
absurd
B.
entertaining
C.
serious
D.
grotesque

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 127 Meaning of the word ‘Risible is fit to be laughed at. Hence ‘Serious’ is the most suitable antonym of the given word. However, grotesque means comically or repulsively ugly or distorted.

Test: BITSAT Mock Test- 7 - Question 128

Choose the one which can be substituted for the given words/sentences
The raison d' etre of a controversy is

A.
the enthusiasm with which it is kept alive
B.
the finesse with which participants handle it
C.
the reason or justification of its existence
D.
the unending hostility the parties concerned have towards each other.

Test: BITSAT Mock Test- 7 - Question 129

Fill in the blank with appropriate word.
Freedom and equality are the.....rights of every human being.

A.
inalienable
B.
inscrutable
C.
incalculable
D.
institutional

Test: BITSAT Mock Test- 7 - Question 130

Choose the one which can be substituted for the given words/sentences
Study of birds

A.
Orology
B.
Optology
C.
Ophthalmology
D.
Ornithology

Test: BITSAT Mock Test- 7 - Question 131

Fill in the blank with appropriate word.
This is a.........translation of the speech.

A.
verbatim
B.
verbal
C.
literal
D.
literary

Test: BITSAT Mock Test- 7 - Question 132

Spot the error.

A.
This is an instance
B.
of the blind
C.
leading the blinds
D.
No error

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 132 correct form is leading the blind instead of leading the blinds

Test: BITSAT Mock Test- 7 - Question 133

Spot the error.

A.
To lead a well balanced life
B.
you shall have to cultivate other interests
C.
besides your proffessional
D.
No error

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 133 The correct statement would be 'besides your profession'

Test: BITSAT Mock Test- 7 - Question 134

Find the Synonym of the word occurring in the sentence in capital letter as per the context.
Valiant Vicky used to BOAST of his bravery to his beloved wife.

A.
cry
B.
abuse
C.
hate
D.
brag

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 134 Meaning of BOAST
To speak of (one's own achievements, possessions, etc) arrogantly adding things that may be false
Brag is also similar in meaning it is also speaking boastfully
Sentence is about the boastful nature of Vicky about is bravery

Test: BITSAT Mock Test- 7 - Question 135

Spot the error.

A.
Oil has and
B.
still is
C.
in great demand
D.
No error

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 135 The correct statement is 'oil has been'

Test: BITSAT Mock Test- 7 - Question 136

Find the Synonym of the word occurring in the sentence in capital letter as per the context.
His ALLEGIANCE to the party was suspected from the very beginning.

A.
Servility
B.
Obedience
C.
Loyalty
D.
Passivity

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 136 'Allegiance' means continued support for somebody

Test: BITSAT Mock Test- 7 - Question 137

Complete the analogous pair.
Men : Messers :: ? : Women

A.
Madams
B.
Mesdames
C.
Madames
D.
Mrs.

Test: BITSAT Mock Test- 7 - Question 138

Choose the word that does NOT match with the two given words.
Querulous : Peevish

A.
A child telling tales
B.
A person redressing at a consumer court
C.
An elite grumbling about a shabby reception
D.
A man unhappy with the state\'s policies

Test: BITSAT Mock Test- 7 - Question 139

Group the following figures into three classes on the basis of identical properties.

A.
7,8,9; 2,4,3; 1,5,6
B.
1,3,2; 4,5,7; 6,8,9
C.
1,6,8; 3,4,7; 2,5,9
D.
1,6,9; 3,4,7; 2,5,8

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 139

1,6,9, are all triangles.
3,4,7, are all four-sided figures.
2,5,8 are all five-sided figures.

Test: BITSAT Mock Test- 7 - Question 140

In each question, three sequences of letters/numerals are given which correspond to each other. Find out the letters/numerals that come in vacant places.
C _ B _ D _ A _ B B D D
2 _ _ 4 _ 3 4 _ ? ? ? ?
_ a _ c b a _ d _ _ _ _

A.
2, 2, 1, 1
B.
2, 2, 3, 3
C.
3, 3, 4, 4
D.
3, 3, 1, 1

Test: BITSAT Mock Test- 7 - Question 141

Find out the term in the number series which is wrong.
5, 27, 61, 122, 213, 340, 509

A.
27
B.
61
C.
122
D.
509

Detailed Solution for Test: BITSAT Mock Test- 7 - Question 141 The terms of the series are (2³ - 3), (3³ - 3), (4³ - 3), (5³ - 3), (6³ - 3), (7³ - 3), (8³ -3).
So, 27 is wrong and must be replaced (3³ - 3) i.e. 24

Test: BITSAT Mock Test- 7 - Question 142

Find the missing character.

150 Questions MCQ Test BITSAT Mock Tests Series & Past Year Papers | Test: BITSAT Mock Test- 7

Same current is flowing in two alternating circuits. The first circuit contains only inductance and the other contains only a capacitor. If the frequency of the e.m.f. of A.C. is increased, the effect on the value of the current will be

Increases in the first circuit and decreases in the other

Increases in both the circuits

Decreases in the both the circuits

Decreases in the first circuit and increases in the other

Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. the spectral lines emitted by hydrogen atoms according to Bohr's theory will be

Heavy water has molecular weight

20

18

19

36

The rates at which currents are changing in the two coils

Relative position and orientation of the two coils

The materials of the wires of the coils

The currents in the coils

I,II and IV

II and IV

III and IV

II and III

RV (E-V)

R(E-V)/V

ER(V+E)/E-V

V(E-V)R/E

4125 +

4000 +

4500 +

5000 +

Length

Crossectional area

Mass

None

2 Ve

3 Ve

4 Ve

None of these

9.9 Ω

11 Ω

10 Ω

9 Ω

The average momentum of the molecules

The velocity of sound in the gas

The number of molecules in the gas

The mean square velocity of the molecules

Ferromagnetic material becomes diamagnetic material .

Ferromagnetic material becomes paramagnetic material .

Paramagnetic material becomes diamagnetic material.

Paramagnetic material becomes ferromagnetic material .

hammering and annealing

change in temperature

impurity in substance

all of these

245 m

490 m

980 m

735 m

40

48

60

100

Increase by 2%

Increase by 1%

Increase by 0.5%

Decrease by 0.5%

Its periodic time increases

It does not oscillate at all

Its periodic time decreases

None of these

does not shift

shifts towards body B

shifts towards body C

depends upon height of breaking

39 MR2/4

39 MR/4

49 MR/4

49 MR2/4

In adiabatic expansion

In adiabatic compression

In isothermal expansion

39 MR²/4

49 MR²/4

CH₃ $―$ O $―$ CH₃

-NH₂

-CH₃