Test: BJT in Amplifier Design

# Test: BJT in Amplifier Design

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## 10 Questions MCQ Test Analog Electronics | Test: BJT in Amplifier Design

Test: BJT in Amplifier Design for Electronics and Communication Engineering (ECE) 2022 is part of Analog Electronics preparation. The Test: BJT in Amplifier Design questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Test: BJT in Amplifier Design MCQs are made for Electronics and Communication Engineering (ECE) 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: BJT in Amplifier Design below.
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Test: BJT in Amplifier Design - Question 1

### Find the maximum allowed output negative swing without the transistor entering saturation, and

Test: BJT in Amplifier Design - Question 2

### The corresponding maximum input signal permitted is

Detailed Solution for Test: BJT in Amplifier Design - Question 2

If we assume linear operation right to saturation we can use the gain Av to calculate the maximum input signal. Thus for an output swing ∆ Vo = 0.8 we have
∆ Vi = ∆ Vo / Av = -0.7 / -360 = 1.94 mV.

Test: BJT in Amplifier Design - Question 3

### (Q.3- Q.5) For the amplifier circuit in Fig. 6.33(a) with Vcc = +10 V, Rc = 1 kΩ and the DC collector bias current equal to Ic Q. Find the voltage gain.

Detailed Solution for Test: BJT in Amplifier Design - Question 3

Test: BJT in Amplifier Design - Question 4

The maximum possible positive output signal swing as determined by the need to keep the transistor in the active region.

Detailed Solution for Test: BJT in Amplifier Design - Question 4

Assuming the output voltage Vo = 0.3v is the lowest Vce to stay out of saturation.
Vo = 0.3 = 10 – IcRc
= 10 – IcRc + ∆Vo
∆ Vo = -10 + 0.3 + Ic*1.

Test: BJT in Amplifier Design - Question 5

The maximum possible negative output signal swing as determined by the need to keep the transistor in the active region.

Detailed Solution for Test: BJT in Amplifier Design - Question 5

Maximum output voltage before the Transistor is cutoff.
Vce + ∆Vo = Vcc
∆Vo = Vcc – Vce
= 10 – 10 + 10 Ic
= 10 Ic.

Test: BJT in Amplifier Design - Question 6

The transistor in the circuit below is biased at a dc collector current of 0.5 mA. What is the voltage gain?

Detailed Solution for Test: BJT in Amplifier Design - Question 6

Test: BJT in Amplifier Design - Question 7

For a BJt Vt is 5 V, Rc = 1000 ohm and bias current Ic is 12 mA. The value of the voltage gain is __________

Detailed Solution for Test: BJT in Amplifier Design - Question 7

Voltage gain is (Ic X Rc ) / Vt.

Test: BJT in Amplifier Design - Question 8

(Q.8–Q.10) (Q.3- Q.5) For the BJT amplifier circuit with Vcc = +10 V, Rc = 1 kΩ and the DC collector bias current equal to 5 mA,

Q. The value of the voltage gain is _______________

Detailed Solution for Test: BJT in Amplifier Design - Question 8

The voltage is 400 X Ic where Ic is 5 mA.

Test: BJT in Amplifier Design - Question 9

The maximum possible positive output signal swing as determined by the need to keep the transistor in the active region.

Detailed Solution for Test: BJT in Amplifier Design - Question 9

The maximum voltage swing is given by -10 + 0.3 + (Ic X Rc). Putting Ic as 5 mA, we get -4.7 mV.

Test: BJT in Amplifier Design - Question 10

The maximum possible negative output signal swing as determined by the need to keep the transistor in the active region.

Detailed Solution for Test: BJT in Amplifier Design - Question 10

It is given by -10 + 10 + (Ic X Rc). Putting Ic as 5 mA we get 5V.

## Analog Electronics

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## Analog Electronics

11 videos|57 docs|108 tests