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If 120 C of charge passes through an electric conductor in 60 sec, the current in the conductor is:
A solid copper sphere, 10 cm in diameter is deprived of 10^{20} electrons by a charging scheme. The charge on the sphere is:
A lightning bolt carrying 15,000 A lasts for 100 μs. If the lightning strikes an airplane flying at 2 km, the charge deposited on the plane is:
ΔQ = i x Δ t = 15000 x 100μ = 1.5 C
In the circuit given, a charge of 600 C is delivered to the 100 V source in a 1 minute. The value of v_{1} must be:
In the circuit of the fig the value of the voltage source E is:
Going from 10 V to 0 V:
Consider the circuit graph shown in fig. Each branch of circuit graph represent a circuit element. The value of voltage v_{1} is:
What quantity of charge must be delivered by a battery with a Potential Difference of 110 V to do 660J of Work?
► V = W / Q
► Q = W / V = 660 / 110 = 6 C
Twelve 6 Ω resistor are used as edge to form a cube.The resistance between two diagonally opposite corner of the cube is
The current i will be distributed in the cube branches symmetrically
If we go from +ve side of 1 kΩ through 7 V, 6 V and 5 V
We get, v_{1} = 7 + 6  5 = 8 V
From above figure
V – 4 – 5 = 0
or
V = 9 V
Hence alternative (D) is the correct choice.
In a AC circuit, resistive and total impedance are 10 and 20 ohms respectively. What is the phase angle difference between the voltage and current?
The quantity of a charge that will be transferred by a current flow of 10 A over 1 hour period is _________ ?
We know that,
I=Q / t or Q = I x t = 10 x 1 hours
{since unit of current is Cs^{1}, therefore time should be in seconds}
∴ Q = 10 x 60 x 60
= 36000 C
= 3.6 x 10^{4 }C
A capacitor is charged by a constant current of 2 mA and results in a voltage increase of 12 V in a 10 sec interval. The value of capacitance is:
12 * C = 2 m x 10
C = 1.67 mF
Hence, Capacitance is equal to 1.67 mF.
The energy required to charge a 10 μF capacitor to 100 V is:
The current in a 100 μF capacitor is shown in fig. If capacitor is initially uncharged, then the waveform for the voltage across it is:
This 0.2 V increases linearly from 0 to 0.2 V. Then current is zero. So capacitor hold this voltage.
The voltage across a 100 μF capacitor is shown in fig. The waveform for the current in the capacitor is:
= 600 mA
For 1 ms < t < 2 ms,
The waveform for the current in a 200 μF capacitor is shown in fig. The waveform for the capacitor voltage is:
= 3125 t^{2}
At t = 4 ms, v_{c} = 0.05 V
It will be parabolic path at t = 0
taxis will be tangent.
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