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For the circuit shown below, the value of current through R_{L} is
The given circuit can be reduced by combining resistors and current sources as shown below.
Let the node voltage be V volts.
Applying nodal analysis, we have
or,
or,
or, 5 +
or,
or,
So,
In nodal analysis, if there are N nodes in the circuit, then how many equations will be written to solve the network ?
In the node voltage technique of solving networks, choice of a reference node does not
1. affect the operation of the circuit.
2. change the voltage across any element.
3. affect the pd between any pair of nodes.
4. affect the voltages of various nodes.
Q. Which of the above statements is/are true?
R_{A} and R_{B} are the input resistances of circuits as shown below. The circuits extend infinitely in the direction shown. Which one of the following statements is TRUE?
In the circuit shown below, the value of l_{x} is
Applying nodal analysis at the given node, we have
or, 3I_{x} = V  3 ...(i)
Also, 10 = 2I_{x} + V
or, V = 10  2I_{x} ...(ii)
Putting V from equation (ii) into equation (i),
3I_{x }= 10  2I_{x}  3
or, 5I_{x }= 7
or,
The value of V_{1} in the circuit shown in the given figure is
Let the node voltage be V' volts.
Applying nodal analysis at the given node, we have
or, 2V' = 0
or, V' = 0 volts
Now, V' =  3 + 1_{1}
or, 0 =  3 + V_{1}
or, V_{1} = 3 volts
Consider the electrical network shown below.
What is the value of R so that current through the resistor R is zero?
The given circuit can be redrawn as shown below (By combining current sources).
Now, I = 0 (Given)
i.e.
or, R = 2Ω
Assertion (A): In the method of solution of the network using nodal analysis, the assumption is made that the node potential is always higher than the other voltages appearing in the equation.
Reason (R): Nodal analysis is used to find the branch currents.
Node potential is always higher than the other voltages appearing in the equations otherwise a negative value for current would result.
The nodal equations of the circuit shown below are respectively given by
We have,
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