In the given fig, P and Q are points on the sides AB and AC respectively of Δ ABC such that AP = 3.5 cm, PB = 7 cm, AQ = 3 cm and QC = 6 cm. If PQ = 4.5 cm, find BC.
Therefore, by converse of Basic Proportionality Theorem, we have QP || CB
Hence, ∆AQP ~ ∆ACB [Using AA similar condition]
If a triangle and a parallelogram are on the same base and between same parallels, then what is the ratio of the area of the triangle to the area of parallelogram?
ΔABC ~ ΔPQR, ∠B = 50° and ∠C = 70° then ∠P is equal to
Similar triangles have corresponding angles equal. So Angle Q=Angle B = 50° and Angle R = Angle C = 70° . So by angle sum property, Angle P+Angle Q +Angle R = 180°
Angle P=180° - 50° - 70° = 60°
Two congruent triangles are actually similar triangles with the ratio of corresponding sides as.
Which geometric figures are always similar?
It can be found that circles map one onto another.So they are similar figures. A regular polygon is a polygon which has the same sides and equal measures of angles. So they are also similar.