Test: Biomolecules Level - 4
30 Questions MCQ Test Organic Chemistry | Test: Biomolecules Level - 4
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Which of the following compounds will form an osazone derivative?
When sugars are reacted with excess of phenylhydrazine osazone formation takes place.
Osazone will form in that sugar only where keto hydroxy group is present.
Thus CH3CH2COCH2OH will form an osazone derivative; as it has keto hydroxy group.
on epimerization with base gives Epimers are carbohydrates which vary in one position for the placement of the -OH group. The best examples are for D-glucose and D-galactose. Both monosaccharides are D-sugars, meaning that the -OH group on carbon-5 of these hexoses is located on the right in Fischer Projection.
When sugars react with an excess of phenylhydrazine, a class of compounds known as osazone is formed.
Glucose and fructose differ in the arrangement of atoms around the C−1 and C−2 carbon. When both of them react with three molecules of phenylhydrazine, the formation of osazone crystals makes the difference between the carbon atoms in their chain and hence they form the same osazone.
The correct statement(s) about the following sugars X and Y is/are:
Consider the following reaction. 
Among the following, the compound(s) whose osazone derivative(s) will have the same melting point as that of X is/are:
Which of the following are non-covalent interactions important is maintaining the secondary, tertiary and quaternary aspects of amino acids:
Which pair(s) of amino acids cannot have hydrophobic interactions:
Which of the following regarding steroids is/are correct:
Which of the following statement regarding to properties of starch is/are correct:
Which of the following pair regarding to biological importance of carbohydrates is/are correctly matched:
Which of the following regarding to the examples of Keto sugar is/are correct:
Which of the following pairs is/are correctly matched:
D-Glucose exist in x different forms. The value of x(stereoisomer) is:
How many of the following carbohydrate would not undergo mutarotaion in aqueous solutions:
The number of reducing sugars among the following is…………….. [IIT JAM 2017]
How many isophene unit are present in the following compound:
How many of the following will give same product on reaction with PhNHNH2 (excess):
For 
Glutamic acid value of pKa, pKa2, pKa3 are 2.00, 4.65 and 9.98 respectively. At which pH Glutomic acid will not be obtained during electroproresis at any one of the electrodes.
How many statements about peptides are correct.
(a) A dipeptide has two peptide linkage between amino acids.
(b) If only one amino group and one carboxylic acid group are available for the reaction, then only one dipeptide can form.
(c) By convention N-terminus is kept left and (–terminus) at siglate in the structure of a pepetide.
(d) A polypeptide with more than hundred amino acid residures (mal . mass > 10,000) is called a protein.
The number of hydrogen bond present in Guanine-Cytosine base pair is:
How many of the following are reducing sugar:
Sucrose, Lactose, Maltose, Glucose, Galactose, Fructose, Glycogen, Ribose.
The aldehyde group of aldoses is very susceptible to oxidation, whereas ketoses are less so, but can easily be oxidized if, like fructose, they contain an α-hydroxyl and can tautomerize to an aldose. Most monosaccharides are reducing sugars. This includes all of the common ones galactose, glucose, fructose, ribose, xylose, and mannose. Some disaccharides, such as lactose and maltose are reducing sugars since they have at least one anomeric carbon free, allowing that part of the sugar to linearize and yield an aldose.
How many different tripeptides can be obtained from alanine, glycine and phenylalanine, each tripeptide containing all the three amino acids?
3 x 2 x 1 = 6 tripedes are possible if each is used only once : AGF,AFG,GAF,GFA,FAG,FGA
Find the value of x + y for
Tyr-Ile-Gln-Arg-Leu-Gly-Phe-Lys-Asn-Trp-Pne-Gly-Ala-Lys-Gln-Gln-NH2
Where
X = Number of fragments obtained by the cleavage of Trypsin.
Y = Number of fragments obtained by the cleavage of chemotrpsin.
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