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Test: CAT Logical Reasoning & Data Interpretation- 2 - CAT


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20 Questions MCQ Test CAT Mock Test Series - Test: CAT Logical Reasoning & Data Interpretation- 2

Test: CAT Logical Reasoning & Data Interpretation- 2 for CAT 2023 is part of CAT Mock Test Series preparation. The Test: CAT Logical Reasoning & Data Interpretation- 2 questions and answers have been prepared according to the CAT exam syllabus.The Test: CAT Logical Reasoning & Data Interpretation- 2 MCQs are made for CAT 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: CAT Logical Reasoning & Data Interpretation- 2 below.
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*Answer can only contain numeric values
Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 1
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Directions: Read the given information carefully and answer the question that follows.

Mr. Brown, a shopkeeper, purchased eight bundles of magazines (bundle 1 to bundle 8). Each bundle contained a different number of magazines and he purchased each bundle at a different cost. He sold the magazines from these eight bundles over a period of six weeks, from week 1 to week 6, such that he first sold all the magazines from bundle 1, after which he sold all the magazines from the next bundle, i.e. bundle 2 and so on, until bundle 8. All the magazines that he sold in any week were sold at the same price, which however, was different for each of the six weeks. Further, for each magazine that he sold, CP of that magazine was calculated as the cost of the bundle which that magazine is from, divided by the number of magazines in that bundle.
The table below provides the number of magazines in each bundle and the price (in $) at which he purchased each bundle and the second table provides the number of magazines that he sold on each of the six weeks and the price (in $) per magazine on each week.

Q. Key in the number of the week in which Mr. Brown made the third highest percent of profit.


Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 1



Total CP of magazines of week 1 = 54 × 7.5 + 88 × 8 = 1,109
Total CP of magazines of week 2 = 34 × 8 + 88 × 6.75 + 2 × 6.5 = 879
Total CP of magazines of week 3 = 72 × 6.5 + 36 × 7.75 = 747
Total CP of magazines of week 4 = 84 × 7.75 + 30 × 6 = 831
Total CP of magazines of week 5 = 66 × 6 + 42 × 6.52 = 669
Total CP of magazines of week 6 = 22 × 6.52 + 82 × 8.50 = 840

In week 3, Mr. Brown made the third highest percent of profit.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 2
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Directions: Study the given information and answer the following question.

In a quiz competition, two academies - Alex Academy and Zed Academy - with five groups each competed against each other such that each group of an academy competed against all the five groups of the other academy exactly once. In any round, the winner was given three points, and the loser was awarded no points. In case of a draw, the two groups were awarded one point each.

The table below provides partial information about the wins, draws and losses of each group:


Moreover, it is also known that:
(A) Each group won at least one round.
(B) G1 lost the round against K5, while G4 lost against K1.

Q. Which of the following groups drew the maximum number of rounds?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 2

Since G1 has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G2 could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G2 must have won 1 round and drew 2 rounds. Since G3 has two losses, it must have won the remaining 3 rounds for 9 points. G4 must have won 4 rounds and lost 1 round, and G5 must have won 1 round and lost 4 rounds.

In Zed Academy. K1 could have 2 wins or 1 win and 3 draws. K2 could have 2 wins and 1 draw or 1 win and 4 draws. K3 must have 2 wins and 2 draws. K4 and K5 each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K3 already has 2 draws, the only possibility is K2 having 2 wins and 1 draw.

Therefore, K1, K4 and K5 each has 2 wins and 3 losses.

The table below presents this information:


Since G1 and G2 drew 3 rounds and K2 and K3 also drew three rounds, G2 must have drawn against both K2 and K3 while G1 must have drawn against K3. Since G4 lost against K1, it must have won all the remaining rounds. Since G1 lost against K5, it must have won against K1, K2 and K4.

K2 lost to G1 and G4. Hence, it must have won against G3 and G5. K3 lost to G4. Hence, it must have won against G3 and G5. Since G3 lost two rounds, it must have won the rounds against K1, K4 and K5. K4 must have won against G2 and G5. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).


K3 drew the most number of rounds.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 3
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Directions: Study the given information and answer the following question.

In a quiz competition, two academies - Alex Academy and Zed Academy - with five groups each competed against each other such that each group of an academy competed against all the five groups of the other academy exactly once. In any round, the winner was given three points, and the loser was awarded no points. In case of a draw, the two groups were awarded one point each.

The table below provides partial information about the wins, draws and losses of each group:


Moreover, it is also known that:
(A) Each group won at least one round.
(B) G1 lost the round against K5, while G4 lost against K1.

Q. K2 lost a round against which of the following groups

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 3

Since G1 has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G2 could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G2 must have won 1 round and drew 2 rounds. Since G3 has two losses, it must have won the remaining 3 rounds for 9 points. G4 must have won 4 rounds and lost 1 round, and G5 must have won 1 round and lost 4 rounds.

In Zed Academy. K1 could have 2 wins or 1 win and 3 draws. K2 could have 2 wins and 1 draw or 1 win and 4 draws. K3 must have 2 wins and 2 draws. K4 and K5 each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K3 already has 2 draws, the only possibility is K2 having 2 wins and 1 draw.

Therefore, K1, K4 and K5 each has 2 wins and 3 losses.

The table below presents this information:


Since G1 and G2 drew 3 rounds and K2 and K3 also drew three rounds, G2 must have drawn against both K2 and K3 while G1 must have drawn against K3. Since G4 lost against K1, it must have won all the remaining rounds. Since G1 lost against K5, it must have won against K1, K2 and K4.

K2 lost to G1 and G4. Hence, it must have won against G3 and G5. K3 lost to G4. Hence, it must have won against G3 and G5. Since G3 lost two rounds, it must have won the rounds against K1, K4 and K5. K4 must have won against G2 and G5. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

K2 lost the rounds against G1 and G4.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 4
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Directions: Study the given information and answer the following question.

In a quiz competition, two academies - Alex Academy and Zed Academy - with five groups each competed against each other such that each group of an academy competed against all the five groups of the other academy exactly once. In any round, the winner was given three points, and the loser was awarded no points. In case of a draw, the two groups were awarded one point each.

The table below provides partial information about the wins, draws and losses of each group:


Moreover, it is also known that:
(A) Each group won at least one round.
(B) G1 lost the round against K5, while G4 lost against K1.

Q. The group that scored the least number of points won against which of the following groups?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 4

Since G1 has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G2 could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G2 must have won 1 round and drew 2 rounds. Since G3 has two losses, it must have won the remaining 3 rounds for 9 points. G4 must have won 4 rounds and lost 1 round, and G5 must have won 1 round and lost 4 rounds.

In Zed Academy. K1 could have 2 wins or 1 win and 3 draws. K2 could have 2 wins and 1 draw or 1 win and 4 draws. K3 must have 2 wins and 2 draws. K4 and K5 each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K3 already has 2 draws, the only possibility is K2 having 2 wins and 1 draw.

Therefore, K1, K4 and K5 each has 2 wins and 3 losses.

The table below presents this information:


Since G1 and G2 drew 3 rounds and K2 and K3 also drew three rounds, G2 must have drawn against both K2 and K3 while G1 must have drawn against K3. Since G4 lost against K1, it must have won all the remaining rounds. Since G1 lost against K5, it must have won against K1, K2 and K4.

K2 lost to G1 and G4. Hence, it must have won against G3 and G5. K3 lost to G4. Hence, it must have won against G3 and G5. Since G3 lost two rounds, it must have won the rounds against K1, K4 and K5. K4 must have won against G2 and G5. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

The group that scored the least number of points is G5. G5 could have won against either K1 or K5.

*Answer can only contain numeric values
Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 5
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Directions: Study the given information and answer the following question.

In a quiz competition, two academies - Alex Academy and Zed Academy - with five groups each competed against each other such that each group of an academy competed against all the five groups of the other academy exactly once. In any round, the winner was given three points, and the loser was awarded no points. In case of a draw, the two groups were awarded one point each.

The table below provides partial information about the wins, draws and losses of each group:


Moreover, it is also known that:
(A) Each group won at least one round.
(B) G1 lost the round against K5, while G4 lost against K1.

Q. The total number of rounds that K4 lost was _________.

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 5

Since G1 has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G2 could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G2 must have won 1 round and drew 2 rounds. Since G3 has two losses, it must have won the remaining 3 rounds for 9 points. G4 must have won 4 rounds and lost 1 round, and G5 must have won 1 round and lost 4 rounds.

In Zed Academy. K1 could have 2 wins or 1 win and 3 draws. K2 could have 2 wins and 1 draw or 1 win and 4 draws. K3 must have 2 wins and 2 draws. K4 and K5 each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K3 already has 2 draws, the only possibility is K2 having 2 wins and 1 draw.

Therefore, K1, K4 and K5 each has 2 wins and 3 losses.

The table below presents this information:


Since G1 and G2 drew 3 rounds and K2 and K3 also drew three rounds, G2 must have drawn against both K2 and K3 while G1 must have drawn against K3. Since G4 lost against K1, it must have won all the remaining rounds. Since G1 lost against K5, it must have won against K1, K2 and K4.

K2 lost to G1 and G4. Hence, it must have won against G3 and G5. K3 lost to G4. Hence, it must have won against G3 and G5. Since G3 lost two rounds, it must have won the rounds against K1, K4 and K5. K4 must have won against G2 and G5. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

K4 lost three rounds.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 6
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Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:
1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.
2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.
3) Bonnie was a part of the Fierce Werewolves.
4) At any point of time, exactly one player, of either team, took possession of the ball.

Q. Which among the following is a part of Fierce Werewolves?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 6

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
The following table represents the team.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 7
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Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:
1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.
2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.
3) Bonnie was a part of the Fierce Werewolves.
4) At any point of time, exactly one player, of either team, took possession of the ball.

Q. Who scored the highest number of goals in Deadly Sharks?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 7

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
The following table represents the team.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 8
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Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:
1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.
2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.
3) Bonnie was a part of the Fierce Werewolves.
4) At any point of time, exactly one player, of either team, took possession of the ball.

Q. Which of the following pairs of players belongs to the same team?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 8

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
The following table represents the team.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 9
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Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:
1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.
2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.
3) Bonnie was a part of the Fierce Werewolves.
4) At any point of time, exactly one player, of either team, took possession of the ball.

Q. If the title 'Player of the Game' was awarded to the player from the winning team who scored at least two goals and possessed the ball for the highest duration, who was awarded the Player of the Game?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 9

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
The following table represents the team.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 10
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Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:
1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.
2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.
3) Bonnie was a part of the Fierce Werewolves.
4) At any point of time, exactly one player, of either team, took possession of the ball.

Q. The second least possession time of a player in the winning team is more or less than the same for a player in the losing team by _______ minutes.
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 10

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
The following table represents the team.

The second least possession time, i.e. 3 minutes, is that of Charlie in "Fierce Werewolves", the winning team.
The second least possession time is that of Rjay, i.e. 10 minutes, in "Deadly Sharks", the losing team.
Thus, the possession time of Charlie in the winning team is less by 7 minutes.

*Answer can only contain numeric values
Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 11
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Directions: Study the following information and answer the question given below.

Ten participants - Oliver, Archie, Ethan, Max, Joshua, Logan, Oscar, Finlay, David and Louie participated in three different rounds of a quiz competition - Round 1, Round 2 and Round 3. Each participant belongs to one of the four colleges among ABC College, XYZ College, LMN College and PQR College. The first table below presents the number of questions answered by each of the ten participants in each round and the second table provides, for each college, the number of questions answered by all the participants (from among the given ten participants) that belong to that college in each round.

Q. How many of the ten participants are from LMN College? Key in the correct answer.

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 11

Three participants are from LMN College.

The participants from XYZ College have given 8 correct answers in Round 3. Oscar and Archie could have given 8 correct answers, but their number of correct answers in the other rounds will not add up. Logan and one among Max, Finlay and David also will have 8 correct answers in Round 3. Among these participants. Logan and David will satisfy the number of questions answered by the participants from XYZ College. For no other combination of participants this is possible. Hence, Logan and David are from XYZ College.

The participants from ABC College have given 8 correct answers in Round 1. If either of Max and Finlay is from ABC College, then Oscar must also be from ABC College (for the total number of correct answers in Round 1 to become 8). However, for any of these cases, the number of correct answers in the other rounds will not satisfy. Another possibility is Joshua with Oliver or David. Joshua and Oliver can be from ABC College, but Joshua and David cannot be from ABC College. The other possibilities are also not possible. Hence, Joshua and Oliver are from ABC College.

Oscar cannot be from PQR College (since he has given 8 correct answers and no combination of participants with this participant will give the required number of correct answers). Hence, Oscar has to be from LMN College. The number of correct answers remaining for LMN College (removing Oscar) will be 9, 11 and 2 in the three rounds. To have 2 correct answers in Round 3, Archie and Ethan will satisfy. The other possibility is Max and Finlay which will not satisfy for correct answers in other rounds. Hence, Archie and Ethan are from LMN College and the rest are from PQR College.

The following table gives the college that each participant is from:

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 12
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Directions: Study the following information and answer the question given below.

Ten participants - Oliver, Archie, Ethan, Max, Joshua, Logan, Oscar, Finlay, David and Louie participated in three different rounds of a quiz competition - Round 1, Round 2 and Round 3. Each participant belongs to one of the four colleges among ABC College, XYZ College, LMN College and PQR College. The first table below presents the number of questions answered by each of the ten participants in each round and the second table provides, for each college, the number of questions answered by all the participants (from among the given ten participants) that belong to that college in each round.

Q. To which college does the participant who got the highest number of correct answers across the three rounds combined belong?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 12

Three participants are from LMN College.

The participants from XYZ College have given 8 correct answers in Round 3. Oscar and Archie could have given 8 correct answers, but their number of correct answers in the other rounds will not add up. Logan and one among Max, Finlay and David also will have 8 correct answers in Round 3. Among these participants. Logan and David will satisfy the number of questions answered by the participants from XYZ College. For no other combination of participants this is possible. Hence, Logan and David are from XYZ College.

The participants from ABC College have given 8 correct answers in Round 1. If either of Max and Finlay is from ABC College, then Oscar must also be from ABC College (for the total number of correct answers in Round 1 to become 8). However, for any of these cases, the number of correct answers in the other rounds will not satisfy. Another possibility is Joshua with Oliver or David. Joshua and Oliver can be from ABC College, but Joshua and David cannot be from ABC College. The other possibilities are also not possible. Hence, Joshua and Oliver are from ABC College.

Oscar cannot be from PQR College (since he has given 8 correct answers and no combination of participants with this participant will give the required number of correct answers). Hence, Oscar has to be from LMN College. The number of correct answers remaining for LMN College (removing Oscar) will be 9, 11 and 2 in the three rounds. To have 2 correct answers in Round 3, Archie and Ethan will satisfy. The other possibility is Max and Finlay which will not satisfy for correct answers in other rounds. Hence, Archie and Ethan are from LMN College and the rest are from PQR College.

The following table gives the college that each participant is from:

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 13
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Directions: Study the following information and answer the question given below.

Ten participants - Oliver, Archie, Ethan, Max, Joshua, Logan, Oscar, Finlay, David and Louie participated in three different rounds of a quiz competition - Round 1, Round 2 and Round 3. Each participant belongs to one of the four colleges among ABC College, XYZ College, LMN College and PQR College. The first table below presents the number of questions answered by each of the ten participants in each round and the second table provides, for each college, the number of questions answered by all the participants (from among the given ten participants) that belong to that college in each round.

Q. Which of the following pairs of participants belongs to the same college?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 13

Three participants are from LMN College.

The participants from XYZ College have given 8 correct answers in Round 3. Oscar and Archie could have given 8 correct answers, but their number of correct answers in the other rounds will not add up. Logan and one among Max, Finlay and David also will have 8 correct answers in Round 3. Among these participants. Logan and David will satisfy the number of questions answered by the participants from XYZ College. For no other combination of participants this is possible. Hence, Logan and David are from XYZ College.

The participants from ABC College have given 8 correct answers in Round 1. If either of Max and Finlay is from ABC College, then Oscar must also be from ABC College (for the total number of correct answers in Round 1 to become 8). However, for any of these cases, the number of correct answers in the other rounds will not satisfy. Another possibility is Joshua with Oliver or David. Joshua and Oliver can be from ABC College, but Joshua and David cannot be from ABC College. The other possibilities are also not possible. Hence, Joshua and Oliver are from ABC College.

Oscar cannot be from PQR College (since he has given 8 correct answers and no combination of participants with this participant will give the required number of correct answers). Hence, Oscar has to be from LMN College. The number of correct answers remaining for LMN College (removing Oscar) will be 9, 11 and 2 in the three rounds. To have 2 correct answers in Round 3, Archie and Ethan will satisfy. The other possibility is Max and Finlay which will not satisfy for correct answers in other rounds. Hence, Archie and Ethan are from LMN College and the rest are from PQR College.

The following table gives the college that each participant is from:

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 14
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Directions: Study the following information and answer the question given below.

Ten participants - Oliver, Archie, Ethan, Max, Joshua, Logan, Oscar, Finlay, David and Louie participated in three different rounds of a quiz competition - Round 1, Round 2 and Round 3. Each participant belongs to one of the four colleges among ABC College, XYZ College, LMN College and PQR College. The first table below presents the number of questions answered by each of the ten participants in each round and the second table provides, for each college, the number of questions answered by all the participants (from among the given ten participants) that belong to that college in each round.

Q. Name the participants of the college whose average correct answers of all rounds are 10.
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 14

Three participants are from LMN College.

The participants from XYZ College have given 8 correct answers in Round 3. Oscar and Archie could have given 8 correct answers, but their number of correct answers in the other rounds will not add up. Logan and one among Max, Finlay and David also will have 8 correct answers in Round 3. Among these participants. Logan and David will satisfy the number of questions answered by the participants from XYZ College. For no other combination of participants this is possible. Hence, Logan and David are from XYZ College.

The participants from ABC College have given 8 correct answers in Round 1. If either of Max and Finlay is from ABC College, then Oscar must also be from ABC College (for the total number of correct answers in Round 1 to become 8). However, for any of these cases, the number of correct answers in the other rounds will not satisfy. Another possibility is Joshua with Oliver or David. Joshua and Oliver can be from ABC College, but Joshua and David cannot be from ABC College. The other possibilities are also not possible. Hence, Joshua and Oliver are from ABC College.

Oscar cannot be from PQR College (since he has given 8 correct answers and no combination of participants with this participant will give the required number of correct answers). Hence, Oscar has to be from LMN College. The number of correct answers remaining for LMN College (removing Oscar) will be 9, 11 and 2 in the three rounds. To have 2 correct answers in Round 3, Archie and Ethan will satisfy. The other possibility is Max and Finlay which will not satisfy for correct answers in other rounds. Hence, Archie and Ethan are from LMN College and the rest are from PQR College.

The following table gives the college that each participant is from:

Oliver and Joshua are participants of the college ABC whose average correct answers of all rounds are 10.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 15
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Directions: Study the following information and answer the question given below.

Ten participants - Oliver, Archie, Ethan, Max, Joshua, Logan, Oscar, Finlay, David and Louie participated in three different rounds of a quiz competition - Round 1, Round 2 and Round 3. Each participant belongs to one of the four colleges among ABC College, XYZ College, LMN College and PQR College. The first table below presents the number of questions answered by each of the ten participants in each round and the second table provides, for each college, the number of questions answered by all the participants (from among the given ten participants) that belong to that college in each round.

Q. The participant who gave the 5th highest correct answers belongs to which college?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 15

Three participants are from LMN College.

The participants from XYZ College have given 8 correct answers in Round 3. Oscar and Archie could have given 8 correct answers, but their number of correct answers in the other rounds will not add up. Logan and one among Max, Finlay and David also will have 8 correct answers in Round 3. Among these participants. Logan and David will satisfy the number of questions answered by the participants from XYZ College. For no other combination of participants this is possible. Hence, Logan and David are from XYZ College.

The participants from ABC College have given 8 correct answers in Round 1. If either of Max and Finlay is from ABC College, then Oscar must also be from ABC College (for the total number of correct answers in Round 1 to become 8). However, for any of these cases, the number of correct answers in the other rounds will not satisfy. Another possibility is Joshua with Oliver or David. Joshua and Oliver can be from ABC College, but Joshua and David cannot be from ABC College. The other possibilities are also not possible. Hence, Joshua and Oliver are from ABC College.

Oscar cannot be from PQR College (since he has given 8 correct answers and no combination of participants with this participant will give the required number of correct answers). Hence, Oscar has to be from LMN College. The number of correct answers remaining for LMN College (removing Oscar) will be 9, 11 and 2 in the three rounds. To have 2 correct answers in Round 3, Archie and Ethan will satisfy. The other possibility is Max and Finlay which will not satisfy for correct answers in other rounds. Hence, Archie and Ethan are from LMN College and the rest are from PQR College.

The following table gives the college that each participant is from:

Max gave the 5th highest (14 correct answers) number of correct answers and he belongs to PQR College.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 16
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Directions: Read the given passage carefully and answer the question that follows.

Connor, Richard, Poppy, Mason and Sarah were playing a racing game which consisted of 4 levels. In each level, the persons who stood first, second and third were awarded 10, 7.5 and 5 points, respectively. The remaining two persons were awarded 2.5 points each.

It is also known that

(1) the total points earned by no two friends in the game were the same
(2) Connor earned 5 more points than Poppy and neither of them earned the highest total points in the game
(3) Richard, who was the last in one of the four levels, earned a total of 22.5 points in the game, but he was not the first in any level
(4) one of the five persons was the first in more than one levels and he did not win the highest points in the game
(5) Mason was not the third in any of the four levels, but he was the first in one of the four levels
(6) the points that Poppy earned in the game were more than the points that Sarah earned

Q. What are the highest points earned by any of the five persons in the game?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 16

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

The highest points earned by any person are 27.5 points.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 17
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Directions: Read the given passage carefully and answer the question that follows.

Connor, Richard, Poppy, Mason and Sarah were playing a racing game which consisted of 4 levels. In each level, the persons who stood first, second and third were awarded 10, 7.5 and 5 points, respectively. The remaining two persons were awarded 2.5 points each.

It is also known that

(1) the total points earned by no two friends in the game were the same
(2) Connor earned 5 more points than Poppy and neither of them earned the highest total points in the game
(3) Richard, who was the last in one of the four levels, earned a total of 22.5 points in the game, but he was not the first in any level
(4) one of the five persons was the first in more than one levels and he did not win the highest points in the game
(5) Mason was not the third in any of the four levels, but he was the first in one of the four levels
(6) the points that Poppy earned in the game were more than the points that Sarah earned

Q. How many of the following definitely earned higher points than Sarah in at least three of the four levels?
1. Connor
2. Richard
3. Poppy
4. Mason
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 17

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

Connor earned 2.5 points in two levels. In these two levels, Sarah could have got 2.5 points. Hence, we cannot say that Connor definitely earned more than Sarah in at least three levels.
Richard could have earned 2.5 points in the same level that Sarah earned 2.5 points. In the level that Richard earned 5 points, Sarah could have earned only 2.5 points (since two persons could not have earned 5 points). In the other two levels that Richard earned 7.5 points, Sarah would have got less points than Richard. Hence, Richard would have definitely earned higher points than Sarah in three levels. Poppy earned 2.5 points in two levels. In these two levels, Sarah could have earned 2.5 points. Hence, we cannot say that Poppy definitely earned more than Sarah in at least three levels. Mason earned 10 points in one level and 7.5 points in two levels. In all the three levels, Mason would have earned higher points than Sarah. Hence, the given condition is satisfied for two persons, Richard and Mason.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 18
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Directions: Read the given passage carefully and answer the question that follows.

Connor, Richard, Poppy, Mason and Sarah were playing a racing game which consisted of 4 levels. In each level, the persons who stood first, second and third were awarded 10, 7.5 and 5 points, respectively. The remaining two persons were awarded 2.5 points each.

It is also known that

(1) the total points earned by no two friends in the game were the same
(2) Connor earned 5 more points than Poppy and neither of them earned the highest total points in the game
(3) Richard, who was the last in one of the four levels, earned a total of 22.5 points in the game, but he was not the first in any level
(4) one of the five persons was the first in more than one levels and he did not win the highest points in the game
(5) Mason was not the third in any of the four levels, but he was the first in one of the four levels
(6) the points that Poppy earned in the game were more than the points that Sarah earned

Q. Which of the following statements is definitely true?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 18

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

The only persons who were second in any level were Richard and Mason. In the level that Mason was first, Richard must be second. Hence, the statement given in option (1) is definitely true. The other statements need not necessarily be true.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 19
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Directions: Read the given passage carefully and answer the question that follows.

Connor, Richard, Poppy, Mason and Sarah were playing a racing game which consisted of 4 levels. In each level, the persons who stood first, second and third were awarded 10, 7.5 and 5 points, respectively. The remaining two persons were awarded 2.5 points each.

It is also known that

(1) the total points earned by no two friends in the game were the same
(2) Connor earned 5 more points than Poppy and neither of them earned the highest total points in the game
(3) Richard, who was the last in one of the four levels, earned a total of 22.5 points in the game, but he was not the first in any level
(4) one of the five persons was the first in more than one levels and he did not win the highest points in the game
(5) Mason was not the third in any of the four levels, but he was the first in one of the four levels
(6) the points that Poppy earned in the game were more than the points that Sarah earned

Q. Who scored the first position more than one time in levels?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 19

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

Connor scored the first position in levels twice.

Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 20
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Directions: Read the given passage carefully and answer the question that follows.

Connor, Richard, Poppy, Mason and Sarah were playing a racing game which consisted of 4 levels. In each level, the persons who stood first, second and third were awarded 10, 7.5 and 5 points, respectively. The remaining two persons were awarded 2.5 points each.

It is also known that

(1) the total points earned by no two friends in the game were the same
(2) Connor earned 5 more points than Poppy and neither of them earned the highest total points in the game
(3) Richard, who was the last in one of the four levels, earned a total of 22.5 points in the game, but he was not the first in any level
(4) one of the five persons was the first in more than one levels and he did not win the highest points in the game
(5) Mason was not the third in any of the four levels, but he was the first in one of the four levels
(6) the points that Poppy earned in the game were more than the points that Sarah earned

Q. What is the sum of the points earned by Connor, Mason and Sarah?
Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 2 - Question 20

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

Sum of the points earned by Connor, Mason and Sarah = 25 + 27.5 + 15 = 67.5

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