There are two objects of masses 1 kg and 2 kg located at (1, 2) and (-1, 3) respectively. The coordinates of the centre of mass are
Body A has mass of 1kg and location (1,2)
Body B has mass of 2kg and location (-1,3)
mcxc = m1x1 + m2x2
(1+2) xc = (1 x 1) + (2 x -1)
xc = -1/3
mcyc = m1y1 + m2y2
(1 + 2) yc = (1 x 2) + (2 x 3)
Hence the co-ordinates of the center of mass are ( -1/3 , 8/3)
The motion of a potter’s wheel is an example of
Potter’s wheel is an example of rotary motion. Rotary motion is that kind of motion in which body of the mass moves along a circular path about an axis which remains fixed.
The general motion of a rigid body consists of
A rigid body is one
Rigid body is due to the presence of forces of attraction between the atoms or molecules and so they are tightly packed. Thus there positions are fixed. If the position is not fixed then it will not be a rigid body as the molecules will move , so because of this the state of the body will change.
If a shell at rest explodes then the centre of mass of the fragments
As a shell explosion is not governed by any external force, we get that no external force acts upon the shell, and hence it remains at rest.
A child sits stationary at one end of long trolley moving uniformly with speed v on a smooth horizontal floor. If the child gets up and runs about on the trolley in the forward direction with speed u. The centre of mass of the system (child + trolley) will move with speed
The child is running arbitrarily on a trolley moving with velocity v. However, the running of the child will produce no effect on the velocity of the centre of mass of the trolley. This is because the force due to the boy’s motion is purely internal. Internal forces produce no effect on the motion of the bodies on which they act. Since no external force is involved in the boy–trolley system, the boy’s motion will produce no change in the velocity of the centre of mass of the trolley.
There are some passengers inside a stationary railway compartment. The centre of masses of the compartment itself(without the passengers) is C1, while the centre of mass of the compartment plus passengers’ system is C2. if the passengers moves about inside the compartment
Given the track is frictionless, therefore as the people inside will move inside the compartment the compartment will itself move opposite to it.
Hence C1 will move but as their is no external force on the combined system and its initial velocity is also zero. Therefore C2 won't change.
If a man of mass M jumps to the ground from height h and his centre of mass moves a distance x in the time taken by him to hit the ground, the average force acting on him is (assuming his retardation to be constant during his impact with the ground)
As the centre of mass moves through a distance x, the averge force F acting on the man is calculate from :
Work done = Change in potential energy
⇒ Fx = Mgh
⇒ F = Mgh/x
The centre of mass of a body is located
When a shell was following a parabolic path in the air, it explodes somewhere in its flight. The centre of mass of fragments will continue to move in
The internal forces have no effect on the trajectory of centre of mass, and the forces due to explosion are the internal forces. So the centre of mass will follow the same parabolic path even after explosion.
A mass m is moving with a constant velocity along a line parallel to the x-axis, away from the origin. Its angular momentum with respect to the origin
Angular momentum = Mass of momentum
L = mv×h = constant
As the particle moves, m, v and h all remain unchanged.
Every point in a rotating rigid body has the same __________at any instant of time.
Every point in any rigid rotating object is rotating at the same angular velocity. However, I have seen a few cases where people have used the term "angular velocity" when they really meant tangential velocity, so you do have to be careful.
An isolated particle of mass m is moving in a horizontal plane (x,y) along the x axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragments is at y = +15 cm. The larger fragment at this instant is at
As the particle is exploded only due to its internal energy.
So net external force during this process is 0.
So the centre mass will not change.
Let the particle while explosion was above the origin of the co-ordinate system. i e just before explosion X=0 and Y=0
Centre of mass will be at X=0 and Y=0 after explosion Centre of mass will be at X=0 and Y=0
Y cm = [(m/4 * 15) + (3m/4 * y)]/m =0
Solving y = -5cm
The centre of mass of a system of particles does not depend on
If the net force acting on the system of particles is zero, then which of the following may vary
If three balls of same radius are placed touching each other on a horizontal surface such that they will form an equilateral triangle, when their centers are joined. What will be the position of the centre of mass of the system?
When external forces acting on a body are zero, then its centre of mass
When force acting upon the body results zero, the resulting acceleration due to net force applied is also zero and hence by the law of inertia the motion of the body either at rest or constant velocity wont change.
Two blocks of the masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block. The velocity of centre of mass is
The sum of moments of masses of all the particles in a system about the centre of mass is always:
In physics, the center of mass of a distribution of mass in space is the unique point where the weighted relative position of the distributed mass sums to zero, or the point where if a force is applied it moves in the direction of the force without rotating. The distribution of mass is balanced around the center of mass and the average of the weighted position coordinates of the distributed mass defines its coordinates. Calculations in mechanics are often simplified when formulated with respect to the center of mass.
In a CO molecule, the distance between carbon and oxygen atom is 0.12 nm. What is the distance of centre of mass from the carbon atom?