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AB is a chord of a circle with radius ‘r’. If P is any point on the circle such that ∠APB is a right angle , then AB is equal to
In the given figure, AC is a diameter of the given circle and ∠BCD = 75^{o}. Then, ∠EAF−∠ABC is equal to
P is a point on the diameter AB of a circle and CD is a chord perpendicular to AB. If AP = 4 cm and PB = 16 cm, the length of chord CD is
Arc ABC subtends an angle of 130^{o} at the centre O of the circle. AB is extended to P. Then ∠CBP equals :
Chords AB and CD intersect at right angles. If ∠BAC = 40^{o}, then ∠ABD is equal to
In the given figure, O is the centre of the circle. ∠OAB and ∠OCB are 40^{o} and 30^{o} respectively. Then, the measure of ∠AOC is
(Angle at the centre is double the angle at the circumference subtended by the same chord)
In the given, AB is side of regular five sided polygon and AC is a side of a regular six sided polygon inscribed in the circle with centre O. AO and CB intersect at P, then ∠APB is equal to
In the given figure, if ∠AOB = 80^{o} and ∠ABC = 30^{o} , then ∠CAO is equal to
2ACB=AOB
ACB=40
CAB+ACB+ABC=180
CAB=18070
CAB=110
since,OA=OB(radius)
OAB=OBA
AOB+OAB+OBA=180
2OBA=100
OBA=50
CAO=CABOBA=1105O
CAO=60^{o}
In the figure, O is the centre of eh circle and ∠AOB = 80^{o}. The value of x is :
In the given figure if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to
Chords AD and BC intersect each other at right angles at point P. ∠DAB = 35^{o}, then ∠ADC is equal to
In the given figure, AB is a diameter of the circle APBR. APQ and RBQ are straight lines. If ∠A = 35^{o} and , then the measure of ∠PBR is
In the figure, O is the center of the circle. If ∠OAB = 40^{o}, then ∠ACB is equal to :
X is a point on a circle with centre O. If X is equidistant from the two radii OP, OQ, then arc PX : arc PQ is equal to
BC is a diameter of the circle and ∠BAO = 60^{o} . Then ∠ADC is equal to
What fraction of the whole circle is minor arc RP in the given figure ?
In the given figure, AD is the diameter of the circle and AE = DE. If ∠ABC = 115^{o}, then the measure of ∠CAE is
In the figure, if ∠DAB = 60^{o}, ∠ABD = 50^{o}, then ∠ACB is equal to :
If ABCD is a cyclic trapezium in which AD ║ BC and ∠B = 60^{o}, then ∠BCD is equal to
In the given figure, O is the centre of the circle and ∠AOC = 130^{o}. Then ∠ABC is equal to
360^{o}  130^{o} =230^{o}
Therefore, angle ABC =1/2reflex angle AOC
Angle ABC =1/2 230^{o}
So, angle ABC =115^{o}
In the given circle, O is the centre and ∠BDC = 42^{o}. Then, ∠ACB is equal to
In ∆ BDC and ∆ BAC
Angle BAC = BDC
(angle made on same segment BC)
Since ABC is making right angle (90)
So,
In ∆ABC
ABC +BAC+ACB=180
(angle sum property of triangle)
90+42+ACB=180
ACB=180132
ACB=48^{o}
AOB is the diameter of the circle. If ∠AOE = 150^{o}, then the measure of ∠CBE is
In the given figure, a circle is centred at O. The value of x is :
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