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QUESTION: 1

The current flowing through the resistance of 10 Ω for the circuit shown below is

Solution:

The given circuit can be replaced by an equivalent circuit as shown below:

and

Hence,

QUESTION: 2

The Thevenin’s equivalent voltage source across the terminals X-Y shown below is

Solution:

For finding V_{oc'} the terminal X-Y is open circuited. Thus, current through voltage source (\/_{s}) becomes zero. i.e. I_{s} = 0 due to which 0.5I_{s} voltage source gets short circuited.

Thus, V_{oc} = 3 x 1 = 3 volt

QUESTION: 3

The Norton’s equivalent resistance across the diode in the given circuit is

Solution:

For finding R_{N} across diode, the independent voltage sources will be short circuited.

Hence, R_{N} = 5 + 5 = 10 Ω

QUESTION: 4

Assuming the op-amp to be ideal, the input admittance of the op-amp shown below is

Solution:

Since the op-amp is ideal, the inverting terminal will be virtually grounded.

Hence, V_{i} = I_{1 }R_{1}

or,

or,

QUESTION: 5

In the π-circuit shown below, the current through the 2 Ω, resistor is

Solution:

Here, we apply superposition theorem.

**Taking the 20 A current source only:
Taking the 10 A current source only:
**

Hence, the net current through the 2 Ω resistor

= I

QUESTION: 6

Match List-I (Elements) with List-ll (Type) and select the correct answer using the codes given below the lists:

**Codes:
**

Solution:

QUESTION: 7

The equivalent resistance of the given circuit is

Solution:

Given circuit can be reduced as shown below.

QUESTION: 8

The maximum power that a 12 V d.c. source with an interna! resistance of 2 Ω can supply toa resistive load is

Solution:

QUESTION: 9

The Norton’s equivalent circuit for the circuit shown below across the terminals X-Y can be represented as a current source (I_{N}) connected across a resistance (R_{N}). The value of I_{N} and R_{N} are respectively

Solution:

Here, V_{X-Y }= V_{OC} = 1 x I_{1} = I_{1}

Applying KVL in the loop, we have

I_{1} x 1 - 2 + 2 I_{1 }- 0.5 I_{1} = 0

or, I_{1} - 0.8 A

Hence, V_{OC} = 0.8 V

When the termical X-Y is short circuited then,

I_{1} = 0

∴

So,

QUESTION: 10

To effect maximum power transfer to the load, Z_{L} (W) for the circuit shown below should be

Solution:

For maximum power transfer,

Z_{L }= Z_{S}^{*}

or, Z_{L }= 6 - j4

or, Z_{L} = 7.211 ∠-33°.69Ω

QUESTION: 11

In order to apply superposition theorem, it is necessary that the network be only

Solution:

QUESTION: 12

A network N is to be connected to a load of 500 ohms. If the Thevenin’s equivalent voltage and Norton’s equivalent current of N are 5 volts and 10 mA respectively, the current through the load will be

Solution:

Given,

∴

= 500 Ω

Hence, the current through the load is

QUESTION: 13

If all the elements in a particular network are linear, then the superposition theorem would hold, when the excitation is

Solution:

QUESTION: 14

The maximum value of power transferred to the load Z_{L} shown in figure below is

Solution:

Also, V_{OC} across Z_{L} is

According to maximum power transfer theorem,

Hence,

QUESTION: 15

In the circuit shown below, the current through the inductive reactance is

Solution:

Let us apply superposition theorem.

Here,

and

∴

= 10 ∠- 90 ° + 0 = -j10 A

QUESTION: 16

Which of the following theorems is applicable for both linear and non-linear circuits?

Solution:

QUESTION: 17

While determining R_{Th} of a circuit

1. voltage and current sources should be left as they are.

2. all independent current and voltage sources are short-circuited.

3. all sources should be replaced by their source resistances.

4. all dependent sources remain as they are.

Q. Which of the statements is/are true in relation of R_{Th}?

Solution:

QUESTION: 18

For the circuit given in figure below, the Thevenin’s voltage and resistance as seen at “AB" are respectively

Solution:

(Using voltage divider rule)

R_{Th} across,

QUESTION: 19

Consider the following statements about Norton’s equivalent of a circuit across a given two load terminals:

1. Norton’s equivalent resistance is the same as Thevenin’s equivalent resistance R_{Th}.

2. Norton’s equivalent is the voltage equivalent of the network.

3. The load is connected in parallel to the Norton’s equivalent resistance.

Out of the above statements, which statements hold true?

Solution:

QUESTION: 20

When the power transferred to the load is maximum, the efficiency is

Solution:

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