Test: Class 9 Math: CBSE Sample Question Paper Term I - 2

# Test: Class 9 Math: CBSE Sample Question Paper Term I - 2

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## 50 Questions MCQ Test Mathematics (Maths) Class 9 | Test: Class 9 Math: CBSE Sample Question Paper Term I - 2

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 for Class 9 2022 is part of Mathematics (Maths) Class 9 preparation. The Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 questions and answers have been prepared according to the Class 9 exam syllabus.The Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 MCQs are made for Class 9 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 below.
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Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 1

### If x is a positive real number and x2 = 2, then x3 =

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 1

x2 = 2
⇒ x = √2
∴ x3 =  x2 . x
= 2√2

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 2

### The point (a, -a) does not lie on the graph of

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 2

Clearly a ≠ -a.
Hence, (a, -a) doesn't lie on y = x.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 3

### In the given figure, BO and CO are the bisectors of ∠B and ∠C respectively. If ∠A = 50°, then ∠BOC = ?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 3

In ΔABC
2x + 2y + ∠A = 180° (Angle sum property)
x + y + (∠A/2) = 90°
x + y = 90° – (A/2) ...1
In BOC, we have
x + y + ∠BOC = 180°
90° - (∠A/2) + ∠BOC = 180° [From (1)]
∠BOC = 180° - 90° + (∠A/2)
∠BOC = 90° + (∠A/2)
∠BOC = 90° + 25° = 115°

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 4

The area of an equilateral triangle with side 2√3 cm is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 4

Area of equilateral triangle =

= 3 x 1.732 = 5.196 sq. cm

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 5

when simplified is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 5

= 6+1-3
= 4
positive and rational

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 6

Which of the following is not a linear equation?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 6

x2 + 5 = 3x - 5, as it has power 2, then it is a quadratic equation.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 7

In the given figure, ∠BAC = 40°, ∠ACB = 90° and ∠BED = 100°, Then ∠BDE =?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 7

In ΔABC
∠ABC + ∠BAC + ∠ACB = 180°  (Angle sum property)
∠ABC = 180° - 90° - 40°
∠ABC = 50°
In ΔBED
∠BED + ∠EBD + ∠BDE = 180°  (Angle sum property)
∠BDE = 180° - 50° - 100°
∠BDE= 30°

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 8

In Figure, AB and CD are parallel lines and transversal EF intersects them at P and Q respectively. If ∠APR = 25°, ∠RQC = 30° and ∠CQF = 65°, then

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 8

∠OQP = 180° - ∠OQF
= 180° - (30° + 65°)
⇒ ∠OQP = 85° ...(i)
∠APQ = ∠CQF (Corresponding angles)
⇒ 25° + y° = 65°
⇒ y° = 65° - 25°
⇒ y° = 40°
Now in ΔOPQ
∠0 + ∠OPQ + ∠PQO = 180°
⇒ x° + 40° + 85° = 180°
⇒ x° = 180° - 85° -  40° = 55°
⇒ x = 55°, y = 40°

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 9

The value of , is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 9

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 10

In a grouped frequency distribution, the class intervals are 0-10, 10-20, 20-30, .., then the class width is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 10

The class width is the difference between the upper or lower class limits of consecutive classes. In this case, class width equals to the difference between the lower limits of the first two classes.
w = 10 - 0
So, the class width is 10

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 11

The number of angles formed by a transversal with a pair of parallel lines are

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 11

As we can see there are 4 angles formed at every point of intersection thus giving a total of 8 angles.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 12

If 4x - 4x-1 = 24, then (2x)x equals

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 12

4x - 4x-1 = 24
⇒
⇒
⇒
⇒
4x = 32
(22)x = (2)5
22x = 25
Comparing, we get

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 13

The value of , is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 13

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 14

In Fig. if l1 || l2, what is x + y in terms of w and z?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 14

Given that,
l1 ‖ l2
Let m and n be two transversal cutting them
∠w + ∠x = 180o (Consecutive interior angle)
x = 180o – w (i)
z = y (Alternate angles) (ii)
From (i) and (ii), we get
x + y = 180o – w + z

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 15

Write the linear equation such that each point on its graph has an ordinate 5 times its abscissa

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 15

y = 5x
at x = 1
y = 5.1 = 5
y = 5
(1,5)
at x = 2
y = 5.2 = 10
y = 10
(2,10)
at x = 3
y = 5.3 = 15
y = 15
(3,15)

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 16

The given cumulative frequency distribution shows the class intervals and their corresponding cumulative frequencies. Then the frequency of class interval 20-30 is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 16

A cumulative frequency distribution is the sum of the class and all classes below it in a frequency distribution.
Subtract the previous cumulative frequency (c.f) from the cumulative frequency of the current class.
So frequency of the class interval 20-30 is 14 - 5 = 9

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 17

The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 17

Area of Δ = 1/2 x Base x Height
The smallest side is 11 m
Area = 1/2 x 11 x Height.. (i)
Area by Heron's Formula =
s =
Area =
= 330 m2
From eq (i)
330 = 1/2 x 11 x height
Height = 2 x 330/11 = 60 m

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 18

In a histogram the area of each rectangle is proportional to

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 18

A histogram is a display of statistical information that uses rectangles to show the frequency of data items in successive numerical intervals of equal size. In the most common form of histogram, the independent variable is plotted along the horizontal axis and the dependent variable is plotted along the vertical axis.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 19

Which of the following is rational:

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 19

Since 0 is rational number  it is in the form of p/q , and where q ≠ 0 as 0/1

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 20

In the given figure, AB ║ CD ║ EF, EA ⊥ AB and BDE is the transversal such that ∠DEF = 55°, Then ∠AEB =?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 20

EA ⊥ AB
∠AEF = 90°
∠AEF = ∠BEF + ∠AEB
∠BEF + ∠AEB = 90°
∠BEF = 55°
55° + ∠AEB = 90°
∠AEB = 90° - 55°
∠AEB = 55°

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 21

The graph of the linear equation 3x – 2y = 6, cuts the x-axis at the point

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 21

the linear equation 3x – 2y = 6,   cuts the x-axis
when y co-ordinate is 0
so we put y = 0 in given equation 3x – 2y = 6
3x - 2.0 = 6
3x = 6
∴ x = 2
so the co-ordinates are (2,0)

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 22

An isosceles right triangle has area 8cm2. The length of its hypotenuse is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 22

Area of isosceles right triangle = 8 sq. cm
1/2 x Base  Base = 8    [Since in isosceles right triangle, base and perpendicular are same]
⇒ (Base)2 = 16
⇒ Base = 4 cm
Hypotenuse =

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 23

The graph of y = 5 is a line

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 23

As, the graph of y = 5 is a line parallel to x-axis i.e. y = 0.
⇒ The line represented by the equation y = 5 is parallel to x-axis and intersects y-axis at y = 5.
So, the graph of y = 5 is a line parallel to the x-axis at a distance of 5 units from the origin making an intercept 5 on the y-axis.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 24

A point of the form (0, b) lies on:

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 24

Let P be any point whose co-ordinate be P(0, b)
Then, if the value of x-coordinate or abscissa is zero then the point P lies in y-axis.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 25

is equal to

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 25

= 8/9

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 26

The sides of a triangle are in ratio 3 : 4 : 5. If the perimeter of the triangle is 84 cm, then area of the triangle is :

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 26

Let the sides be 3x, 4x and 5x.
Then according to quesiton, 3x + 4x + 5x = 84
⇒ 12x = 84
⇒ x = 7
Therefore, the sides are 3 x 7 = 21, cm, 4 x 7 = 28 cm and 5 x 7 = 35 cm
s =  = 42 cm
Area of triangle =

= 21  7  2 = 294 sq. cm

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 27

Which is true?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 27

True, you may have a triangle with two or more acute angles. If a triangle has three acute angles, the triangle is called an Acute Triangle. If a triangle has two acute angles and a single obtuse angle, the triangle is called an Obtuse Triangle.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 28

Which one of the following statements is true?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 28

The sum of two irrational numbers may be a rational number or an irrational number
Eg. a = √2 (which is irrational)
b  = 2√2(which is irrational)
a + b = √2 + 2√2 = 3√2 ( which is irrational)
and Let a = 1+√2  (which is  irrational)
and b= 1- √2 (which is irrational)
Now, a + b = 1+√2 +1- √2
= 2 (which is rational)

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 29

If x < 0 and y < 0, then the point (x, y) lies in

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 29

Here,x < 0 (i.e, -ve) and y < 0, (i.e, -ve)
And we know that,co-ordinate of the point in 3rd quadrant is (-,-)i.e, both negative,
So,the given point will lie in 3rd quadrant.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 30

The marks obtained by 17 students in a mathematics test (out of 100) are given below :
91, 82, 100, 100, 96, 65, 82, 76, 79, 90, 46, 64, 72, 68, 66, 48, 49.
Find the range of the data.

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 30

Highest Marks = 100
Lowest Marks = 46
Range of data = 100 - 46 = 54

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 31

The base of an isosceles triangle is 8 cm long and each of its equal sides measures 6 cm. The area of the triangle is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 31

Area of isosceles triangle =
Here, a = 6 cm and b = 8 cm
Thus, we have

= 8√5 cm2

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 32

Choose the wrong statement:

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 32

Every rational number is an integer.
Eg. 1/2 is a rational number but not an integer.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 33

In the adjoining figure, PQ > PR. If OQ and OR are bisectors of ∠Q and ∠R respectively, then

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 33

Since PQ > PR then R > Q and hence their bisectors follow the same i.e R/2 > Q/2 and hence OQ>OR

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 34

To compare this years result with last years result, teacher went to the class and collected this years number of distinctions from the students. For last years number of distinctions, she opened the result register & wrote the required number of distinctions. The data Collected by her from the students & register respectively, are examples of-

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 34

The data collected directly from the population is primary data, so the current number of distinctions as confirmed from students is primary data.
The data collected using the old records such as register is called secondary data. So, the data collected from the register is secondary data.

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 35

In the adjoining figure, if QP ║ RT, then x is equal to –

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 35

∠QPR = ∠PRT = 40° (Alternate interior angles)
In ∠QPR, ∠PQR + ∠QPR + ∠PRQ = 180° (Angle sum property)
65° + 40° + x° = 180°
x° = 180° - 40° - 65°
x° = 75

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 36

If (2, 0) is a solution of the linear equation 2x + 3y = k, then the value of k is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 36

(2, 0) is a solution of the linear equation 2x + 3y = k
⇒ 4 = k

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 37

In the adjoining figure, AB = AC and AD is median of ΔABC , then ∠ADC is equal to

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 37

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 38

The value of  is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 38

multiplying nu nominator and denominator by
√5 + √3 we get

= √5 + √3

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 39

What is the sum of the angles of a quadrilateral?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 39

Number of sides (n) = 4
Sum of interior angles = (n - 2) x 180°
p = (4 - 2) x 180°
p = 2  x 180°
p = 360°

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 40

Find the range of the following data: 25, 20 30, 18, 16, 15

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 40

The difference between the maximum and minimum value is called range.
Thus, 30 - 15 = 15

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 41

As shown In the village of Surya there was a big pole PC. This pole was tied with a strong wire of 10 m length.
Once there was a big spark on this pole, thus wires got damaged very badly. Any small fault was usually repaired with the help of a rope which normal board electricians were carrying on bicycles.
This time electricians need a staircase of 10 m so that it can reach at point P on the pole and this should make 60° with line AC.
In the ΔPAC and ΔPBC which side is common?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 41

PC

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 42

As shown In the village of Surya there was a big pole PC. This pole was tied with a strong wire of 10 m length.
Once there was a big spark on this pole, thus wires got damaged very badly. Any small fault was usually repaired with the help of a rope which normal board electricians were carrying on bicycles.
This time electricians need a staircase of 10 m so that it can reach at point P on the pole and this should make 60° with line AC.
In the ΔPAC and ΔPBC which angles are given to be equal?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 42

∠B = ∠x

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 43

As shown In the village of Surya there was a big pole PC. This pole was tied with a strong wire of 10 m length.
Once there was a big spark on this pole, thus wires got damaged very badly. Any small fault was usually repaired with the help of a rope which normal board electricians were carrying on bicycles.
This time electricians need a staircase of 10 m so that it can reach at point P on the pole and this should make 60° with line AC.
In the figure, ΔPAC and ΔPBC are congruent due to which criteria?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 43

RHS

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 44

As shown In the village of Surya there was a big pole PC. This pole was tied with a strong wire of 10 m length.
Once there was a big spark on this pole, thus wires got damaged very badly. Any small fault was usually repaired with the help of a rope which normal board electricians were carrying on bicycles.
This time electricians need a staircase of 10 m so that it can reach at point P on the pole and this should make 60° with line AC.
What is the value of ∠PBC?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 44

45°

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 45

As shown In the village of Surya there was a big pole PC. This pole was tied with a strong wire of 10 m length.
Once there was a big spark on this pole, thus wires got damaged very badly. Any small fault was usually repaired with the help of a rope which normal board electricians were carrying on bicycles.
This time electricians need a staircase of 10 m so that it can reach at point P on the pole and this should make 60° with line AC.
The value of ∠x is

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 45

30°

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 46

In the above picture, one small square is of size 1 km  1 km. From the starting point O(0,0)  Deepak started to drive towards his home. He first drives 3km in left then he turned to his left and drove 2 km, there he found a temple. He worshipped there and drove 6km in the left direction, there is a zoo and from the zoo, he drives 2km on the right side, then he reached his home.
From O Sanjay drove for his school, he drove 1km to his right then took a left turn and drives 2km then again took a right turn and drives 2 km. He found a hospital in the way. From Hospital he drove 3 km and finally reached his school.
What are the coordinates of the Hospital?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 46

(3, 2)

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 47

In the above picture, one small square is of size 1 km  1 km. From the starting point O(0,0)  Deepak started to drive towards his home. He first drives 3km in left then he turned to his left and drove 2 km, there he found a temple. He worshipped there and drove 6km in the left direction, there is a zoo and from the zoo, he drives 2km on the right side, then he reached his home.
From O Sanjay drove for his school, he drove 1km to his right then took a left turn and drives 2km then again took a right turn and drives 2 km. He found a hospital in the way. From Hospital he drove 3 km and finally reached his school.
What is common abscissa of school, Hospital, Zoo and Deepak's home?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 47

3

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 48

In the above picture, one small square is of size 1 km  1 km. From the starting point O(0,0)  Deepak started to drive towards his home. He first drives 3km in left then he turned to his left and drove 2 km, there he found a temple. He worshipped there and drove 6km in the left direction, there is a zoo and from the zoo, he drives 2km on the right side, then he reached his home.
From O Sanjay drove for his school, he drove 1km to his right then took a left turn and drives 2km then again took a right turn and drives 2 km. He found a hospital in the way. From Hospital he drove 3 km and finally reached his school.
What is the common ordinate of temple and Zoo?

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 48

-2

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 49

In the above picture, one small square is of size 1 km  1 km. From the starting point O(0,0)  Deepak started to drive towards his home. He first drives 3km in left then he turned to his left and drove 2 km, there he found a temple. He worshipped there and drove 6km in the left direction, there is a zoo and from the zoo, he drives 2km on the right side, then he reached his home.
From O Sanjay drove for his school, he drove 1km to his right then took a left turn and drives 2km then again took a right turn and drives 2 km. He found a hospital in the way. From Hospital he drove 3 km and finally reached his school.

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 49

III and IV

Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 50

In the above picture, one small square is of size 1 km  1 km. From the starting point O(0,0)  Deepak started to drive towards his home. He first drives 3km in left then he turned to his left and drove 2 km, there he found a temple. He worshipped there and drove 6km in the left direction, there is a zoo and from the zoo, he drives 2km on the right side, then he reached his home.
From O Sanjay drove for his school, he drove 1km to his right then took a left turn and drives 2km then again took a right turn and drives 2 km. He found a hospital in the way. From Hospital he drove 3 km and finally reached his school.

Detailed Solution for Test: Class 9 Math: CBSE Sample Question Paper Term I - 2 - Question 50

I only

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## Mathematics (Maths) Class 9

88 videos|397 docs|109 tests