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Test: Classification of Elements and Periodicity in Properties (May 12) - JEE MCQ


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15 Questions MCQ Test Daily Test for JEE Preparation - Test: Classification of Elements and Periodicity in Properties (May 12)

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Test: Classification of Elements and Periodicity in Properties (May 12) - Question 1

Which of the following statements is false?

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 1

Alkali metals always form ionic bonds.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 2

The order of Decreasing radius is

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 2

vanderwaal radius > Metallic radius > Covalent radius.

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Test: Classification of Elements and Periodicity in Properties (May 12) - Question 3

For alkali metals, which one of the following trends is INCORRECT?

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 3

Density: Li < Na < K < Rb.
The density of K is lower than that of Na. Thus, option D is incorrect. The correct trend is
Li < K < Na < Rb

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 4

Dmitri Mendeleev (1834-1907) and the German chemist, Lothar Meyer (1830-1895) proposed arranging elements in

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 4

Dmitri Mendeleev and Lothar Meyer proposed arranging elements in 1. increasing order of their atomic weights. This arrangement eventually led to the development of the periodic table of elements.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 5

According to the recommendation of International Union of Pure and Applied Chemistry (IUPAC), the groups in the modern periodic table are numbered from

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 5

they are numbered from 1 to 18 1 is alkali metal group and 18 is noble gases.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 6

Ionization enthalpy increases across a period because

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 6

as we move from left to right in a period atomic radii decreases and due to effective nuclear charge outermost electrons are held more closely to the nucleus.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 7

Choose one of the following in th increasing order of bond length

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 7

As the size increases bond length also increases.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 8

For the four successive transition elements (Cr, Mn, Fe and Co), the stability of + 2 oxidation state will be there in which of the following order? (At. nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 8

Mn has most stable +2 stable because Mn+2 had d5 configuration which is most stable.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 9

A transition metal ion exists in its highest oxidation state. It is expected to behave as

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 9

When a transition metal ion is in highest oxidation state it tends to lower its oxidation state by gaining electrons. thus it itself reduces and oxidizes the substance from which it accepts electron. So, it acts as oxidising agent. 

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 10

The sequence of ionic mobility in aqueous solution is 

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 10

Smaller the size of cation, higher will be the hydration and its effective size will increase and hence mobility in aqueous solution will decrease. Larger size ions have more ionic mobility due to less hydration. Thus the degree of hydration of M+ ions decreases from Li+ to Cs+. Consequently the radii of the hydrated ion decreases from Li+ to Cs+. Hence the ionic conductance of these hydrated ions increases from Li+ to Cs+ 

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 11

In the periodic table Electronegativity generally

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 11

electronegativity increases on moving from left to right while decreases as we move down the group.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 12

Al(3+)<Mg(2+)<Na+<F−<O(2−)<N(3−) The above can be aptly described as

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 12

They are isoelectronic species with same number of electrons. Higher is the atomic number, higher will be the effective nuclear charge, lower will be the size.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 13

Generally, the first ionization energy increases along a period. But there are some exceptions. One which is NOT an exception is ______.

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 13

Na and Mg are not an exception.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 14

Which of the following will have the most negative electron gain enthalpy and which one the least negative? P, S, Cl, F.

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 14

Cl just need one more electrons to get fully filled electronic configuration so it has most negative electron gain enthalpy while P has d3 configuration which is already stable so it cannot accept one electron extra easily so have large positive electron gain enthalpy.

Test: Classification of Elements and Periodicity in Properties (May 12) - Question 15

For Atomic numbers greater than 100 IUPAC has made recommendation that until a new element ‘s discovery is proved, and its name is officially recognized, a systematic nomenclature be derived directly from the atomic number of the element using the numerical roots for 0 and numbers 1-9. The name 'sept' in this scheme corresponds to the digit

Detailed Solution for Test: Classification of Elements and Periodicity in Properties (May 12) - Question 15

sept is for 7.

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