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Test: Combination of Capacitors (NCERT)


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Test: Combination of Capacitors (NCERT) - Question 1

Three capacitors each of capacity 4 μF are to be connected in such a way that the effective capacitance is 6 μF. This can be done by

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 1


To get equivalent capacitance 6 μF. Out of the 4 μF capacitance, two are connected in series and third one is connected in parallel.

Test: Combination of Capacitors (NCERT) - Question 2

The equivalent capacitance for the network shown in the figure is

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 2


Capacitance of C1 = C4 = 100pF
Capacitance of C2 = C3 = 400pF
Supply voltage , V = 400V
Capacitors C2 and C3 are connected is series,
Equivalent capacitance 
Capacitors C1 and C are in parallel
Their equivalent capacitance.
C = C + C1 = 200 + 100 = 300pF
Capacitors C'' and C4 are connected in series Equivalent capacitance

Test: Combination of Capacitors (NCERT) - Question 3

A network of four 20μF capacitors is connected to a 600V supply as shown in the figure.

The equivalent capacitance of the network is

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 3

image
Form the figure C1, C2, C3 are connected in series.


Now Cs is in parallel with C4
∴ equivalent capacitance Ceq = Cs + C4

Test: Combination of Capacitors (NCERT) - Question 4

The charge on capacitors C1 and C4 are

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 4

Charge on each capacitor C1, C2, C3 is same = q
Let charge on C4 be q.


Also qC4 = 600
or q = C4 × 600μC = 20 × 600μC = 12 × 10−3C

Test: Combination of Capacitors (NCERT) - Question 5

The charge on 3μF capacitor shown in the figure is

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 5

Since all the capacitors are connected in series,
∴ equivalent capacitance is

Charge on each capacitor is same  (∵ V = 10V)
q = CeqV = 1 × 10 = 10μC

Test: Combination of Capacitors (NCERT) - Question 6

Minimum number of capacitors each of 8μF and 250V used to make a composite capacitor of 16μF and 1000V are

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 6

Minimum number of capacitors in each row = 1000/250 = 4
Therefore, 4 capacitors connected in series.
If there are m such rows, that total capacity
= m × 2 = 16 ∴ m = 16/28
∴ minimum number of capacitors = 4 × 8 = 32

Test: Combination of Capacitors (NCERT) - Question 7

A capacitor of capacitance C1 is charged to a potential V and then connected in parallel to an uncharged capacitor of capacitance C2. The final potential difference across each capacitor will be

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 7

When a charged capacitor of capacitance C1  is connected in parallel to an uncharged capacitor of capacitance C2, the charge is shared between them till both attain the common potential which is given by, common Potential = q1 + q2/C1 + C2 = q1 + q2/C1 + C2 = C1V/C1 + C2

Test: Combination of Capacitors (NCERT) - Question 8

Two capacitors of 2 μF and 4 μF are connected in parallel. A third capacitor of 6 μF is connected in series. The combination is connected across a 12 V battery. The voltage across 2 μF capacitor is

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 8

Cp = 2 + 4 = 6μF

Total Q = CV = 3 × 12 = 36μF
Voltage across 6μF capacitor = 36μC/6μF = 6V
∴ Voltage across each of 2μF and 4μF capacitors = 12V - 6V
V = 6V

 

Test: Combination of Capacitors (NCERT) - Question 9

Two identical capacitors are joined in parallel, charged to a potential V, separated and then connected in series, the positive plate of one is connected to the negative of the other. Which of the following is true?

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 9

When the two capacitors charged to same potential are connected in series, then total potential difference V′ = V1 + V2 = V + V = 2V

Test: Combination of Capacitors (NCERT) - Question 10

In the given circuit, initially K1 ​is closed and K2 is open. Then K1 ​is opened and K2 ​is closed. If q1′ ​and q2′ ​are charges on C1 and C2 ​and V1 ​and V2 are the voltage respectively, then

Detailed Solution for Test: Combination of Capacitors (NCERT) - Question 10


From the figure, when K1 ​is closed and K2 is open, C1 ​is charged to potential V acquiring a total charge q = C1V When K1 is open and K2 ​ is closed, battery is cut off C1 ​and C2 ​are in parallel. The charge on C1 is shared between C1 ​and C2 ​such that V1 = V2
As there is no loss of charge q1′ ​+ q2′ ​= q

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