JEE Exam  >  JEE Tests  >  35 Years Chapter wise Previous Year Solved Papers for JEE  >  Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - JEE MCQ

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - JEE MCQ


Test Description

19 Questions MCQ Test 35 Years Chapter wise Previous Year Solved Papers for JEE - Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids for JEE 2024 is part of 35 Years Chapter wise Previous Year Solved Papers for JEE preparation. The Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids questions and answers have been prepared according to the JEE exam syllabus.The Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids below.
Solutions of Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids questions in English are available as part of our 35 Years Chapter wise Previous Year Solved Papers for JEE for JEE & Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids solutions in Hindi for 35 Years Chapter wise Previous Year Solved Papers for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids | 19 questions in 40 minutes | Mock test for JEE preparation | Free important questions MCQ to study 35 Years Chapter wise Previous Year Solved Papers for JEE for JEE Exam | Download free PDF with solutions
Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 1

PASSAGE -1

In the following reaction sequence, product I, J and L are formed.

K represents a reagent.

Q.The structure of the product I is –

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 1

Sodium borohydride reduces –CHO Selectively into –CH2O

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 2

In the following reaction sequence, product I, J and L are formed.

K represents a reagent.

Q. The structures of compound J and K, respectively, are

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 2

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 3

In the following reaction sequence, product I, J and L are formed.

K represents a reagent.

Q. The structure of product L is

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 3

It is Rosemmund reaction. Simultaneously the reagent H2-Pd also reduces carbon-carbon triple bond to double bond (syn -addition) giving cis product.

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 4

PASSAGE-2

A carbonyl compound P,  which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.

Q. The structure of the carbonyl compound P is

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 4

Iodoform test of compound P points out that P has – COCH3 group which shows that it may be either option (a) or (b) of Q. 16. Further since the dicarbonyl compound R has at least one a-H atom w.r.t to one of the carbonyl groups which is possible when R is produced from (b) of Q. 18; (a) option of Q. 16 will give dicarbonyl compound having two –CHO, none of which has a-H atom.




* Structure of R would be R' when P is (A)


Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 5

PASSAGE-2

A carbonyl compound P,  which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.

Q. The structures of the products Q and R, respectively, are

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 5

Iodoform test of compound P points out that P has – COCH3 group which shows that it may be either option (a) or (b) of Q. 16. Further since the dicarbonyl compound R has at least one a-H atom w.r.t to one of the carbonyl groups which is possible when R is produced from (b) of Q. 18; (a) option of Q. 16 will give dicarbonyl compound having two –CHO, none of which has a-H atom.




* Structure of R would be R' when P is (A)


Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 6

PASSAGE-2

A carbonyl compound P,  which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.

Q. The structure of the product S is

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 6

Iodoform test of compound P points out that P has – COCH3 group which shows that it may be either option (a) or (b) of Q. 16. Further since the dicarbonyl compound R has at least one a-H atom w.r.t to one of the carbonyl groups which is possible when R is produced from (b) of Q. 18; (a) option of Q. 16 will give dicarbonyl compound having two –CHO, none of which has a-H atom.




* Structure of R would be R' when P is (A)


Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 7

PASSAGE-3

Two aliphatic aldehydes P and Q react in the presence of aqueous K2CO3 to give compound R, which upon treatment with HCN provides compound S. On acidification and heating, S gives the product shown below

Q. The compounds P and Q respectively are :

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 7

Let us summarize the given facts of the problem.

                                 (P & Q)

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 8

PASSAGE-3

Two aliphatic aldehydes P and Q react in the presence of aqueous K2CO3 to give compound R, which upon treatment with HCN provides compound S. On acidification and heating, S gives the product shown below.

Q. The compound R is :

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 8

Let us summarize the given facts of the problem.


                        (P & Q)

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 9

PASSAGE-3

Two aliphatic aldehydes P and Q react in the presence of aqueous K2CO3 to give compound R, which upon treatment with HCN provides compound S. On acidification and heating, S gives the product shown below.

Q. The compound S is :

 

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 9

Let us summarize the given facts of the problem.


                        (P & Q)

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 10

PASSAGE-4

In the following reaction sequence, the compound J is an intermediate.

J (C9H8O2) gives effervescence on treatment with NaHCO3 and a positive Baeyer’s test.

Q. The compound I is

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 10

Reactions of compound J (C9H8O2) indicates that  it has C = C linkage and – COOH group. Thus, J can be written as C6H5CH = CH COOH. Since, J is unsaturated carboxylic acid and it is formed by the reactions of compound I with (CH3CO)2O and CH3COONa, compound I should be an aldehyde (recall Perkin reaction). Thus the whole series of reactions can be written as below.



Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 11

PASSAGE-4

In the following reaction sequence, the compound J is an intermediate.

J (C9H8O2) gives effervescence on treatment with NaHCO3 and a positive Baeyer’s test.

Q. The compound K is

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 11

Reactions of compound J (C9H8O2) indicates that  it has C = C linkage and – COOH group. Thus, J can be written as C6H5CH = CH COOH. Since, J is unsaturated carboxylic acid and it is formed by the reactions of compound I with (CH3CO)2O and CH3COONa, compound I should be an aldehyde (recall Perkin reaction). Thus the whole series of reactions can be written as below.



Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 12

PASSAGE-5

P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 12


Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 13

PASSAGE-5

P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.

Q. In the following reaction sequences V and W are respectively

  

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 13


Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 14

PASSAGE-6

In the following reactions


Q. Compound X is

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 14

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 15

PASSAGE-6

In the following reactions


Q. The major compound Y is

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 15

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 16

Each of  this question contains STATEMENT-1 (Assertion/ Statement ) and STATEMENT-2 (Reason/Explanation) and has 4 choices (a), (b), (c) and (d) out of which ONLY ONE is correct.

Q. 

Statement-1 : Acetate ion is more basic than the methoxide ion.

Statement-2 : The acetate ion is resonance stabilized

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 16

TIPS/Formulae :

Acetate ion is reasonance stabilized while methoxide ion is not.

Hence, acetate ion is less basic than methoxide ion.

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 17

Statement-1 : Acetic acid does not undergo haloform reaction.

Statement-2 : Acetic acid has no alpha hydrogens.

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 17

Haloform reaction is undergone only by ketones, CH3COOH has 3 α-hydrogens.

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 18

Statement-1 : Dimethyl sulphide is commonly used for the reduction of an ozonide of an alkene to get the carbonyl compounds.

Statement-2 : It reduces the ozonide giving water soluble dimethyl sulphoxide and excess of it evaporates.

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 18

TIPS/Formulae : Ozonide can be reduced by (CH3)2S to give carbonyl compounds and dimethyl sulphoxide.

Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 19

Statement-1 : p-Hydroxybenzoic acid has a lower boiling point than o-hydroxybenzoic acid.

Statement-2 : o-Hydroxybenzoic acid has intramolecular hydrogen bonding.

Detailed Solution for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids - Question 19

p-Hydroxybenzoic acid has higher boiling point than o-hydroxybenzoic acid due to intermolecular hydrogen bonding. Thus, statement-1 is false. o-Hydroxybezoic acid shows intramolecular H-bonding thus, statement2 is true.

327 docs|185 tests
Information about Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids Page
In this test you can find the Exam questions for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Comprehension Based Questions: Aldehydes, Ketones & Carboxylic Acids, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE