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QUESTION: 1

B is a hinge support and C is roller support. A and D are free ends. A load of 60 KN acts in downward direction at point D. Sign conventions are as usual.

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What will be the reaction force at support C?

Solution:

Answer: c

Explanation: Balance moment about point B.

QUESTION: 2

B is a hinge support and C is roller support. A and D are free ends. A load of 60 KN acts in downward direction at point D. Sign conventions are as usual.

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What will be the shape of SFD in this case?

Solution:

Answer: c

Explanation: Since loads are not uniform, SFD will be linear and support at point C and B will lead to discontinuity.

QUESTION: 3

B is a hinge support and C is roller support. A and D are free ends. A load of 60 KN acts in downward direction at point D. Sign conventions are as usual.

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What is the shape of BMD for this diagram?

Solution:

Answer: b

Explanation: It will be 0 till point B, and then will increase till C and then again decrease till D (every time linearly), thus making it triangular

QUESTION: 4

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What will be the peak value of SFD?

Solution:

Answer: c

Explanation: It will decrease to 20 at point B and then increase by 80 at point C and then will remain constant. So, peak value will be 80-20 i.e. 60KN.

QUESTION: 5

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** Where would peak value of BMD lie?

Solution:

Answer: c

Explanation: It will be 0 till point B, and then will increase till C and then again decrease till D (every time linearly), thus making it triangular.

QUESTION: 6

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** Which type of joint would replace point A in its conjugate beam?

Solution:

Answer: d

Explanation: Since point A is a free end, a fixed joint would replace it in the conjugate beam.

QUESTION: 7

How many fixed joint will be there in conjugate beam?

Solution:

Answer: b

Explanation: Since there are 2 fixed ends in initial beam, there will be two fixed joints.

QUESTION: 8

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What will be the shear developed at hinge B in conjugate beam?

Solution:

Answer: a

Explanation: Balance moment about point C in the beam BC.

QUESTION: 9

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What will be the shear developed at hinge C in conjugate beam?

Solution:

Answer: c

Explanation: Balance moment about point B in the beam BC.

QUESTION: 10

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What will be the modulus of slope at point A?

Solution:

Answer: c

Explanation: Just balance shear forces in the conjugate beam AB.

QUESTION: 11

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What will be the modulus of slope at point D?

Solution:

Answer: a

Explanation: Just balance shear forces in the conjugate beam CD after balancing moment.

QUESTION: 12

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What will be the modulus of deflection of point A?

Solution:

Answer: b

Explanation: Balance moment about point B in beam AB.

QUESTION: 13

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

**Q. ** What will be the modulus of deflection of point D?

Solution:

Answer: c

Explanation: Balance moment about point C in beam CD.

QUESTION: 14

AB = CD = 1m and BC = 3m

All force options are in kN.

All moment options are in KNM.

All deformation options are in M.

E and I are given.

There won’t be any hinge in the conjugate beam.

State whether the above statement is true or false.

Solution:

Answer: b

Explanation: Initial beam comprises of one internal pin and one internal roller, so conjugate beam would contain two hinges.

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