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In triangle ABC, altitude BE = altitude CF. Then triangle ABC is
To construct a ΔABC in which BC = 10 cm and ∠B= 60 degrees and AB + AC = 14 cm, then the length of BD used for construction.
Which of these triangles are possible to construct by knowing only its altitude?
The construction of a triangle ABC, given that BC = 6 cm, B = ∠45° is not possible when difference of AB and AC is equal to :
Given, BC = 6 cm and ∠B= 45°
We know that, the construction of a triangle is not possible, if sum of two sides is less than or equal to the third side of the triangle.
i.e., AB + BC < AC
⇒ BC < AC – AB
⇒ 6 < ACAB
So, if AC – AB= 6.9 cm, then construction of ΔABC with given conditions is not possible.
The point of concurrence of the three angle bisectors of a triangle, is called
In triangle ABC, side AB is produced to D so that BD = BC. If angle B = 60° and angle A = 70°, then
The point of intersection of the perpendicular bisectors of the sides of a triangle is called
To construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. We draw line segment AB of 12 cm. Draw a ray AX making 90° with AB. The next step is:
The below given steps will be followed to construct the required triangle.
Step I:
Draw line segment AB of 12 cm. Draw a ray AX making 90deg with AB.
Step II:
Cut a line segment AD of 18 cm (as the sum of the other two sides is 18) from ray AX.
Step III:
Join DB and make an angle DBY equal to ADB.
Step IV:
Let BY intersect AX at C. Join AC, BC.
ΔABC is the required triangle.
The lengths of the sides of some triangles are given, which of them is not a right angled triangle?
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