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Q.
We divided the plane of the paper into four equal parts. by drawing two mutually perpendicular lines, X'OX and YOY'. These lines are called the axes. Here X'OX is called xaxis and YOY' is called yaxis. There axes divide the plane of the paper into four parts, called quadrants.
The position of a point in a plane is denoted by an ordered pair (a,b), where a is called the x coordinate and y is called y coordinate.
In which quadrant does the point(4, 7) lie?
The point (4, 7) lies in 3rd quadrant.
The point (1, 5) lies in 1st quadrant.
The point (9, 2) lies in 4th quadrant.
The point (7, 6) lies in 2nd quadrant.
The point (0, 9) lies in yaxis.
The point (9, 0) lies in xaxis.
Find the coordinates of the point equidistant from the points A(1, 2), B(3, –4) and C(5, –6).
Given three points A(1,2) B(3,4) and C(5,6).
To find the perpendicular bisectors of AB:
To find the perpendicular bisectors of AC:
Now, solve the above two equations:
⇒ 1 / 3(x  2)  1 = 1 / 2(x  3)  2
⇒ 2(x  2)  6 = 3(x  3)  12
⇒ x = 11
⇒ y = 1 / 2(x  3)  2 = 1 / 2(11  3)  2 = 2
The coordinates of the points equidistant from the point A(1, 2), B(3, 4) and C(5, 6) are (11, 2)
Find the distance of the point A(3, 3) from the origin.
OA = √3^{2}+(3)^{2} = √9+9 = √18 = 3√2
P is a point on xaxis at a distance of 4 units from yaxis to its right. The coordinates of P are:
The coordinates of P are A(4, 0)
A is a point on yaxis at a distance of 5 units from xaxis lying below xaxis. The coordinates of A are:
The coordinates of A are A(0, 5)
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