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NEET Exam  >  NEET Test  >  Chemistry Class 12  >  Test: Coordination Compounds - 2 - NEET MCQ

Coordination Compounds - 2 - Free MCQ Practice Test with solutions, NEET


MCQ Practice Test & Solutions: Test: Coordination Compounds - 2 (30 Questions)

You can prepare effectively for NEET Chemistry Class 12 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Coordination Compounds - 2". These 30 questions have been designed by the experts with the latest curriculum of NEET 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 45 minutes
  • - Number of Questions: 30

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Test: Coordination Compounds - 2 - Question 1
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The correct IUPAC name of [Fe(C5H5)2] is

Detailed Solution: Question 1

The correct answer is option B.

The I.U.P.A.C. name for Fe(C5H5)2 is bis(η5 -cyclopentadienyl) iron(II) 
The oxidation state of iron is +2 and is written in parenthesis in roman numerals. Two cyclopentadienyl ligands are coordinated to Fe. The prefix bis indicates 2. η5 indicates that the cyclopentadienyl ligands are penta coordinates.

Test: Coordination Compounds - 2 - Question 2
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Type of isomerism exhibited by [Cr(NCS)(NH3)5] [ZnCl4] :

Detailed Solution: Question 2


Since both cation & anion constitute coordination sphere so it exhibit coordination isomerism and contains ambident ligand so, it shows linkage isomerism

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Test: Coordination Compounds - 2 - Question 3
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A complex compound in which the oxidation number of a metal is zero is

Detailed Solution: Question 3

A complex compound in which the oxidation number of metal is zero is [Ni(CO)4​]. In this complex, the oxidation number of both metal and ligand is zero.

The oxidation number of metal in the complexes K4​[Fe(CN)6​], K3​[Fe(CN)6​] and [Pt(NH3)4]Cl2 are +2, +3 and +2 respectively.

Test: Coordination Compounds - 2 - Question 4
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Trioxalato aluminate (III) and tetrafluorido-borate (III) ions are respectively :

Detailed Solution: Question 4

O. N. of Al = +3
O. N. of B = + 3
[BF4]-
[Al(C2O3)3]3-

Test: Coordination Compounds - 2 - Question 5
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Which of the ligand can show linkage isomerism and acts as flexidentate ligand:

Detailed Solution: Question 5

The correct answer is B: CNS⁻.

Explanation:

  • Linkage isomerism occurs when a ligand can coordinate to the central metal ion through two different atoms, leading to different isomers.

  • Flexidentate ligands are ligands that can form multiple bonds to the metal centre via different donor atoms.

CNS⁻ (Thiocyanate) is an example of a ligand that can exhibit linkage isomerism. The thiocyanate ion (CNS⁻) can bind to the metal through the nitrogen atom (N) or the sulfur atom (S), leading to two different isomers:

  1. N-bonded thiocyanate (also called isothiocyanate),

  2. S-bonded thiocyanate.

This makes CNS⁻ a flexidentate ligand, as it can coordinate through two different donor atoms (N or S), showing linkage isomerism.

Thus, the correct answer is B: CNS⁻.

Test: Coordination Compounds - 2 - Question 6
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Consider the following statements, "According the Werner's theory. :

(1) Ligands are connected to the metal ions by covalent bonds.

(2) Secondary valencies have directional properties.

(3) Secondary valencies are non-ionisable.

(4) Secondary valencies are satisfied by either neutral or negative legands.

Of these statements.

Detailed Solution: Question 6

Werner’s coordination theory describes primary and secondary valencies in coordination compounds:

  • Ligands are connected to the metal ions by covalent bonds: Incorrect. Werner proposed that ligands are bound by coordinate (dative) bonds, not covalent bonds (Statement 1 is false).

  • Secondary valencies have directional properties: Correct. Secondary valencies (coordination number) determine the geometry of the complex (e.g., octahedral, tetrahedral), which is directional (Statement 2 is true).

  • Secondary valencies are non-ionizable: Correct. Secondary valencies involve ligands bound to the metal within the coordination sphere, which do not ionize in solution (Statement 3 is true).

  • Secondary valencies are satisfied by either neutral or negative ligands: Correct. Secondary valencies are satisfied by ligands like NH₃ (neutral) or Cl⁻ (negative) (Statement 4 is true).

Thus, statements 2, 3, and 4 are correct.

Answer: A

Test: Coordination Compounds - 2 - Question 7
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From the stability constant (hypothetical values), given below, predict which is the strongest ligand:

Detailed Solution: Question 7

Higher the value of K higher will be strength of ligand & more will be thermodynamic stability of complex produced.

Test: Coordination Compounds - 2 - Question 8
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The complexes given below show:

and

Detailed Solution: Question 8


Test: Coordination Compounds - 2 - Question 9
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In which of the following complexes the nickel metal is in highest oxidation state.

Detailed Solution: Question 9

[Ni0(CO)4]
[Cr3+(NH3)2][Ni4+F6]3
[Ni2+(NH3)2][B+3F4]2
K4[Ni+2(CN)6]

Test: Coordination Compounds - 2 - Question 10
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An ion M2+, forms the complexes [M(H2O)6]2+, [M(en)3]2+ and [MBr6]4-, match the complex with the appropriate colour.

Detailed Solution: Question 10

Δo value is directly proportional to energy and inversely related to the wavelength. Also, more the ligand is a strong field ligand More will be the value of Δo and lower will be its wavelength. Among the given complexes the strength of ligands are Br− < H2O < en.

Since the emitted colours are red, green, blue the absorbed colours must be green,red,orange. Hence the  compound [M(H2O)6]2+, [M(en)3]2+, [M(Br)6]4− are blue red and green respectively. Hence option B is correct.

Test: Coordination Compounds - 2 - Question 11
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For the complex ion dichlorido bis (ethylene diamine) cobalt (III), select the correct statement.

Detailed Solution: Question 11

Test: Coordination Compounds - 2 - Question 12
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Co(CO)4 follows EAN rule by :

Detailed Solution: Question 12

[Co(CO)4]
EAN = 27 –(0)+ 4 × 2 = 35
2[Co(CO)4] → Co2(CO)8

EAN = 27 + 1 + 4 ×2 = 36

Test: Coordination Compounds - 2 - Question 13
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Type of isomerism exhibited by [Ir(OCN)2(H2O)3]

Detailed Solution: Question 13

–OCN is ambident ligand & it shows linkage isomerism.

Test: Coordination Compounds - 2 - Question 14
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Which of the following complex exhibits geometrical isomerism:

Detailed Solution: Question 14

[PtBrCl NH3 Py] Pt2+ is dsp2 hybridised & hence geometry is square planner & sq. planner complex with four different ligands shows geometrical isomerism.

Test: Coordination Compounds - 2 - Question 15
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A complex of platinum, ammonia and chloride produces four ions per molecule in the solution. The structure consistent with the observation is :

Detailed Solution: Question 15


[Pt(NH3)4]Cl4 → 5 ions
[Pt(NH3)2Cl4] → 0 ions
[Pt(NH3)4Cl2]Cl2 → 3 ions

Test: Coordination Compounds - 2 - Question 16
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The total number of possible isomers of the compound [Cu||(NH3)4] [Pt||Cl4] are :

Detailed Solution: Question 16

Test: Coordination Compounds - 2 - Question 17
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In the complex Fe(CO)x, the value of x is :

Detailed Solution: Question 17

[Fe(CO)x]0
EAN = 26 + 2x = 36
x = 5

Test: Coordination Compounds - 2 - Question 18
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The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:

Detailed Solution: Question 18


Test: Coordination Compounds - 2 - Question 19
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The oxidation state of Mo in its oxo-complex species [Mo2O4(C2H4 )2(H2O)2]2- is :

Detailed Solution: Question 19

Let the O. N. of Mo in the complex is x
 2x + (–2) × 2 + 0 × 2 + 0 × 2  = – 2

Test: Coordination Compounds - 2 - Question 20
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The hybridisation and unpaired electrons in [Fe(H2O)6]2+ ion are :

Detailed Solution: Question 20

H2O is weak field ligand

Test: Coordination Compounds - 2 - Question 21
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In which complex is the transition metal in zero oxidation state:

Detailed Solution: Question 21

K4[Ni(CN)4] Let O.S of Ni = x
4 + x – 4 = 0
x = 0
(A) Co3+  (B)  Fe2+  (C) Co–1

Test: Coordination Compounds - 2 - Question 22
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Formula of ferrocene is :

Detailed Solution: Question 22

Test: Coordination Compounds - 2 - Question 23
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The hybrisation of Co in [Co(H2O)6]3+ is :

Detailed Solution: Question 23

In this complex compound the total charge is +3 as H2O is a neutral compound so the oxidation state of cobalt is +3 and the electronic configuration of Co is 3d7 4s2. So, Co(+3)=4d6 and H2O is a weak ligand so there is no pairing of electron. So,4s 4p3 and 4d2 orbital make hybrid orbital to have a hybridization of d2sp3.

Test: Coordination Compounds - 2 - Question 24
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Which of the following is π complex :

Detailed Solution: Question 24

Al(C2H5)3 σ - complex
Fe(C5H5)2 π - complex
Zn(C2H5)2 σ - complex
[Ni(CO)4] σ - complex

Test: Coordination Compounds - 2 - Question 25
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Which complex is likely to show optical activity

Detailed Solution: Question 25

Cis [Co(NH3)2(en)2]3+

No POS optically active rest compound has POS.

Test: Coordination Compounds - 2 - Question 26
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Which one is the most likely structure of CrCl3·6H2O if 1/3 of total chlorine of the compound is precipitated by adding AgNO3 to its aqueous solution :

Detailed Solution: Question 26

Coordination no. of Cr = 6
1/3 × 3 = 1 Chloride ion is outside the coordination sphere.

Test: Coordination Compounds - 2 - Question 27
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The two compounds [Co(SO4)(NH3)5]Br and [Co(SO4)(NH3)5]Cl represent :

Detailed Solution: Question 27

Different molecular mass, so no isomerism

Test: Coordination Compounds - 2 - Question 28
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The structure of iron pentacarbonyl is :

Detailed Solution: Question 28

[Fe(CO)5] TBP
CO is strong field ligand
Fe - 3d64s2

Test: Coordination Compounds - 2 - Question 29
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The EAN of platinum in potassium hexachloroplatinate (IV) is :

Detailed Solution: Question 29

K2+4[PtCl6]
At No. Pt = 78
EAN = 78 – 4 + 6 × 2 = 86

Test: Coordination Compounds - 2 - Question 30
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Diethylene triamine is :

Detailed Solution: Question 30

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This test contains 30 MCQs on Coordination Compounds - 2 with detailed solutions for each question. It is part of the Chemistry Class 12 course on EduRev, designed to align with the current NEET syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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