Test: Coulomb's Law (NCERT)
10 Questions MCQ Test Physics Class 12 | Test: Coulomb's Law (NCERT)
| 1 Crore+ students have signed up on EduRev. Have you? |
The value of k = (1/4πε0) = 8.854 x 10-12 C2 N-1 m-2 where ε0 is permittivity of free space.
Which of the following statement is not a similarity between electrostatic and gravitational forces?
Electrostatic forces are both attractive and repulsive depending upon the type of charge, but gravitational forces is always attractive.
The force between two small charged spheres having charges of 1 x 10-7 C and 2 x 10-7 C placed 20 cm apart in air is
Here, q1 = 1 x 10-7 C, q2 = 2 x 10-7 C, r = 20cm = 20 x 10-2 m
The nucleus of helium atom contains two proton that are separated by distance 3.0 x 10-15 m. The magnitude of the electrostatic force that each proton exerts on the other is
Charge of proton is qP = 1.6 x 10-19 C
Distance between the protons is, r = 3 x 10-15m
The magnitude of electrostatic force between protons is
Two insulated charged metallic spheres P and Q have their centres separated by a distance of 60 cm. The radii of P and Q are negligible compared to the distance of separation. The mutual force of electrostatic repulsion if the charge on each is 3.2 x 10-7 C is
Here, q1 = q2 = 3.2 x 10-7 C, r = 60cm = 0.6 m
Electrostatic force,
Two point charges of +3 μC and +4 μC repel each other with a force of 10 N. If each is given an additional charge of -6 μC, the new force is
Here, q1 = +3 μC, q2 = +4 μC, F = 10N
q1 = +3 - 6 = -3 μC, q2 = +4 - 6 = -2 μC
The ratio of magnitude of electrostatic force and gravitational force for an electron and proton is
Here, for an electron and a proton
The electrostatic attracting force on a small sphere of charge 0.2μC due to another small sphere of charge -0.4μC in air is 0.4N. The distance between the two spheres is
Here, q1 = 0.2 μC = 0.2 x 10-6 C
q2 = 0.4 μC = -0.4 x 10-6 C, F = -0.4 N
As F = 
= 1.8 x 10-3
∴ r = (1.8 x 10-3)1/2 = 0.0424 m = 42.4 x 10-3 m
Under the action of a given coulombic force the acceleration of an electron is 2.5 x 1022 ms-2. Then the magnitude of the acceleration of a proton under the action of same force is nearly
The acceleration due to given coulombic force F is
a = (F/m) or a ∝ (1/m) ...(1)
∴ 
where mc and mp are masses of electron and proton respectively
|
157 videos|452 docs|213 tests
|
|
Use Code STAYHOME200 and get INR 200 additional OFF
|
Use Coupon Code |
|
157 videos|452 docs|213 tests
|
How to Prepare for NEET
Download free EduRev App
Related content with Test: Coulomb's Law (NCERT)
|
|
|
|
Related tests with Test: Coulomb's Law (NCERT)
|
|
|
|
|
|
© EduRev
|
Education Revolution
|
Follow Us
|
