Test: Deflection & Theories of Failure - 3

Test: Deflection & Theories of Failure - 3

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20 Questions MCQ Test Topicwise Question Bank for Mechanical Engineering | Test: Deflection & Theories of Failure - 3

Test: Deflection & Theories of Failure - 3 for Mechanical Engineering 2022 is part of Topicwise Question Bank for Mechanical Engineering preparation. The Test: Deflection & Theories of Failure - 3 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Deflection & Theories of Failure - 3 MCQs are made for Mechanical Engineering 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Deflection & Theories of Failure - 3 below.
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Test: Deflection & Theories of Failure - 3 - Question 1

What is the vertical displacement under the point of application of the force P?

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 1

M= PR - P(R - R cosθ)
M = PR cosθ

Test: Deflection & Theories of Failure - 3 - Question 2

A thin semicircular ring is hinged at each end and loaded by a central concentrated force, P as shown in figure. What is the horizontal reaction at each hinge?

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 2

Test: Deflection & Theories of Failure - 3 - Question 3

Who enunciated the following theorem: Deflection of the point of application-of an external force acting on a beam is equal to the partial derivative of the work of deformation with respect to this force

Test: Deflection & Theories of Failure - 3 - Question 4

Who enunciated the following theorem:
If unit loads rest upon a beam at the two points R and S, the deflection at R due to unit load at S equals the deflection at S due to the load at R

Test: Deflection & Theories of Failure - 3 - Question 5

When a number of loads rest upon a beam the deflection at any point is equal to the sum of the deflections at this point due to each of the loads taken separately. This is according to

Test: Deflection & Theories of Failure - 3 - Question 6

Total strain energy stored in a simply supported beam of span ‘L’ and flexural rigidity 'El' subjected to a concentrated load ‘W‘ at the center is equal to

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 6

∴

Test: Deflection & Theories of Failure - 3 - Question 7

The strain energy stored in a shaft due to torsion is given by
Where V is the volume, G is modulus of rigidity and τs is the maximum shear stress on the surface of the shaft.

Test: Deflection & Theories of Failure - 3 - Question 8

Which one of the following graphs represent Von Mises yield criterion?

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 8

As per Von Mises yield criterion, the equation in the 2-D system is .This equation represents an ellipse.

Test: Deflection & Theories of Failure - 3 - Question 9

Match the List-I with List-ll:
List-I
A. Maximum normal stress theory
B. Maximum principal strain theory
C. Maximum shear stress theory
List-ll
1. Mise's and Henkey’s theory
2. Rankine’s theory
3. St Venant’s theory
4. Guest’s Tresca’s theory
Codes:
A  B  C
(a) 4  1  2
(b) 2  3  4
(c) 3  2  4
(d) 2  3  1

Test: Deflection & Theories of Failure - 3 - Question 10

Which of the following theories of failure is represented by square shape elastic boundary?

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 10

Maximum principal stress theory

Test: Deflection & Theories of Failure - 3 - Question 11

Principal stresses at a point in an elastic material are 100 MPa tensile 5 and 50 MPa tensile. What is the factor of safety against failure based on maximum shear strain energy theory? The elastic limit in simple tension is 173.2 MPa and Poisson’s ratio 0.3.

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 11

1 - σ2)2 + (σ2 - σ3)2 + (σ3 - σ1)2 =  262
Here, σ1 = 100 MPa, σ2 = 50 MPa, σ3 = 0
∴ (100 - 50)2 + 502 + 1002 = 262
∴ σ2 = 7500 or σ = 86.6 MPa
Factor of safety,

Test: Deflection & Theories of Failure - 3 - Question 12

A uniform rod made of ductile material is subjected to tension. The value of octahedral shearing stress developed will be
where σy is the yield stress of ductile material.

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 12

∴

Test: Deflection & Theories of Failure - 3 - Question 13

The value of octahedral shearing stress for a material subjected to hydrostatic pressure will be

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 13

For hydrostatic pressure,

Test: Deflection & Theories of Failure - 3 - Question 14

Which theory of failure is widely used in machine design dealing with ductile materials?

Test: Deflection & Theories of Failure - 3 - Question 15

The ratio of the area under the bending moment diagram to the flexural rigidity between any two points along a beam gives the change in

Test: Deflection & Theories of Failure - 3 - Question 16

A cantilever beam rectangular in cross-section is subjected to an isolated load at its free end. If the width of the beam is doubled, the deflection of the free end will be changed in the ratio of

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 16

initial width, b1 = b
final width, b2 = 2b
Deflection,

But

Test: Deflection & Theories of Failure - 3 - Question 17

For a simply supported beam of length ‘L' subjected to downward load of uniform intensity w, Match List-I with List-II and select the correct answer using the codes given below the lists:
List-l
A. Slope of shear force diagram
B. Maximum shear force
C. Maximum deflection
D. Magnitude of maximum bending moment
List-II
1.
2. w
3.
4.
Codes:
A  B  C  D
(a) 1  2  3   4
(b) 3  1  2   4
(c) 3  2  1   4
(d) 2  4  1   3

Test: Deflection & Theories of Failure - 3 - Question 18

The Mohr’s circle of plane stress for a point in a body is shown. The design is to be done on the basis of the maximum shear stress theory for yielding. Then, yielding will just begin if the designer chooses a ductile material whose yield strength is

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 18

From maximum shear stress theory

σyp = -90 MPa

Test: Deflection & Theories of Failure - 3 - Question 19

As per the elastic theory of design, the factor of safety is the ratio of

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 19

Usually ratio of ultimate stress to working stress is called factor of safety. In elastic theory of design the material factor of safety is only considered and the ratio of yield stress to working stress is called factor of safety.

Test: Deflection & Theories of Failure - 3 - Question 20

All the failure theories give nearly the same result

Detailed Solution for Test: Deflection & Theories of Failure - 3 - Question 20

When one of the principal stresses at a point is large in comparison to the other, the situation resembles uniaxial tension test. Therefore all theories give nearly same result.

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