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Test: EMT - Magnetostatics


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20 Questions MCQ Test GATE Physics Mock Test Series | Test: EMT - Magnetostatics

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Test: EMT - Magnetostatics - Question 1

Which one of the following can represent the magnetic field outside the wire of radius a earning an arbitrary current distribution in its volume:

Detailed Solution for Test: EMT - Magnetostatics - Question 1

Any vector will represent the magnetic field if the divergence of the vector field is zero. The curl of magnetic field outside the wire must be zero, i.e.,
Only option (d) satisfies tins conditions.

Test: EMT - Magnetostatics - Question 2

Suppose four infinitely long wires passing through the corners of a square of side 2a centre at origin in x-y plane as shown in figure. The magnetic tield at origin is

Detailed Solution for Test: EMT - Magnetostatics - Question 2

The magnetic field at the origin due to wire (I) is








Therefore, the resultant magnetic field at origin

Test: EMT - Magnetostatics - Question 3

A long wire of radius R carries a current I with a volume current density (where α is a constant and s is the perpendicular distance from the axis). The value of α is

Detailed Solution for Test: EMT - Magnetostatics - Question 3

Given: Current density 
Tlierefore, the total current passing through the wire is

Test: EMT - Magnetostatics - Question 4

A long hollow coaxial wire lias inner radius a and outer radius b. Uniform current I flows along its inner surface and return through the outer surface as shown in figure. The magnitude vector potential in different regions are

Detailed Solution for Test: EMT - Magnetostatics - Question 4

According to Ampere's law.


Test: EMT - Magnetostatics - Question 5

A conducting wire carrying current I0 is bent in the shape of a loop, as shown in figure. The magnetic field at Unseen point O is given by

Detailed Solution for Test: EMT - Magnetostatics - Question 5

The magnetic field at O is due to curve portion + straight portion.
The magnetic field due to curve portion is


The magnetic field due to straight portion is



Therefore, the resultant magnetic field at O is

Test: EMT - Magnetostatics - Question 6

A vector potntial at a point is given by  The current density corresponding to the vector potential is

Detailed Solution for Test: EMT - Magnetostatics - Question 6

Given magnetic vector potential 
Therefore, the magnetic field. 


Therefore, the current density

Test: EMT - Magnetostatics - Question 7

Three infinitely-long conductors carrying currents I1, I2, and I3 lie perpendicular to the plane of the paper as shown below. If the value of integral for the loops C1, C2, and C3 are 2μ0, 4μ0 and μ0 in the units of N/A, respectively, then

Detailed Solution for Test: EMT - Magnetostatics - Question 7

According to Ampere’s law,

Solving the above three equation, we can write 
I= 5, I= -3, I= -1

Test: EMT - Magnetostatics - Question 8

If a point dipole of the dipole moment is kept in external magnetic field  The force acting on the dipole is given by 

Detailed Solution for Test: EMT - Magnetostatics - Question 8

We have magnetic dipole, 
And magnetic field, 
Therefore, the magnetostatics energy, 
Therefore, the force acting on the dipole. 

*Answer can only contain numeric values
Test: EMT - Magnetostatics - Question 9

Consider two infinitely Ions wires parallel to the z-axis passing through the point and One is carrying current I0 along positive z-direction of other one is carrying current 3I0, along negative z-direetion. The value of  on closed curve (x - 1)2 + y2 = 16 along clockwise direction is _____ μ0I0.
(Answer should be integer).


Detailed Solution for Test: EMT - Magnetostatics - Question 9


According to Ampere’s law,

*Answer can only contain numeric values
Test: EMT - Magnetostatics - Question 10

An election is revolving around the nucleus in circular orbit of radius a0 in a hydrogen atom. If electron is revolving with speed v0 , the magnetic field at nucleus due to orbital motion of electron is . (Round off to two decimal places)


Detailed Solution for Test: EMT - Magnetostatics - Question 10

Current flow due motion of electron in circular orbit is

Therefore, the magnetic field at the centre of circular loop is

Test: EMT - Magnetostatics - Question 11

Two infintely long current carrying wire are placed along x and y axis and crossing through the origin as shown in figure. The magnetic field at (2, 3,4) will be

Detailed Solution for Test: EMT - Magnetostatics - Question 11

The magnetic field at (2,3,4) due to wire (I) is

The magnetic field at (2,3,4) due to wire (II) is 

Therefore, the resultant magnetic field at (2,3,4) is


Test: EMT - Magnetostatics - Question 12

Two large parallel plates move with a constant speed v in the positive y direction as shown in figure. If both the plates have surface charge density σ, the magnetic force per unit area on the lower plate is

Detailed Solution for Test: EMT - Magnetostatics - Question 12

The current density on the moving plate is given by 
Therefore, the magnetic field on the lower plate is

Therefore, the magnetic force on the lower plate per unit area is

Test: EMT - Magnetostatics - Question 13

All infinitely long wire carrying current I0 is placed (crossing through the origin) along x-axis and another wire of length L carrying current I0 is placed mx-y plane, as shown in figure below. Thex-component of magnetic force acting on the wire is given by

Detailed Solution for Test: EMT - Magnetostatics - Question 13

Consider an arbitrary points on the finite wire (x, y).
The magnetic field at (x, y) is 
Therefore, the magnetic force on the elementary length, 


Therefore, the x component of magnetic force is

Test: EMT - Magnetostatics - Question 14

The regions of space z < 0 and z > 0 are filled with free space and material having permeability 2μ0 respectively. The magnetic field m the region  and the magnitude of magnetic field in region z > 0 is 6T. The angle between magnetic field and normal to the mterface in region z < 0 is given by

Detailed Solution for Test: EMT - Magnetostatics - Question 14

According to boundary condition, Bln = B2n
⇒ B2n = 2


∴ The angle between magnetic field and normal to the interface in region z < 0 is

Test: EMT - Magnetostatics - Question 15

Two magnetic dipoles of magnitude m, one is placed at origin and the otherone is displaced from P to Q keeping the direction fixed (Assume that P and Q both are in x-y plane). The required work done to displaced the magnetic dipole from P to Q is

Detailed Solution for Test: EMT - Magnetostatics - Question 15

The mutual magnetostatics energy when magnetic dipole at P is 


Tlie mutual magnetostatics energy when magnetic dipole at Q is 

Therefore. the required work done is
W = change of magnetostatic energy

*Answer can only contain numeric values
Test: EMT - Magnetostatics - Question 16

A ring of radius R carries a linear charge density λ. It is rotating about an axis crossing through its centre and perpendicular to its plane with an angular speed ω. The magnetic field on its axis at a distance  from the centre is ________ μ0λω. (Round off to two decimal places)


Detailed Solution for Test: EMT - Magnetostatics - Question 16

Current due to rotation of charge carrying ring is given by I = ωλR.
The magnetic field on the axis of a loop is

*Answer can only contain numeric values
Test: EMT - Magnetostatics - Question 17

A rigid square loop ABCD of side L is situated at a distance L from an infinite straight wire, with the side AB parallel to the infinite wire, as shown in the figure below. The infinite wire, which is in the plane of the loop, carries a current I from right to left. The value of  through the square loop is _____________ (Round off to two decimal places)


Detailed Solution for Test: EMT - Magnetostatics - Question 17


*Answer can only contain numeric values
Test: EMT - Magnetostatics - Question 18

The volume current density through a long cylindrical conductor is given to be  where, R is radius of cylinder and r is tlie distance of some point from tlie axis of cylinder and J0 is a constant. The value of r at which magnetic field maximum is ___________________ R. (Round off to two decimal places)


Detailed Solution for Test: EMT - Magnetostatics - Question 18


According to Ampere's law, 

For extrema value of B

Now, B will be maximum for

*Answer can only contain numeric values
Test: EMT - Magnetostatics - Question 19

A long hollow cylinder of radius R carrying uniform surface charge density σ. It is rotating about its axis with angular speed ω. A ring of radius (r = R/2) is placed eo-axially with cylinder. The value of ton the ring is    ______ πμ0ωσR3 (Round off to two decimal places)


Detailed Solution for Test: EMT - Magnetostatics - Question 19

Given: The surface current density σ. Now, when it will rotate about its axis there will be current flow along and we can treat it as solenoid.
Therefore, the magnetic field inside the cylinder

*Answer can only contain numeric values
Test: EMT - Magnetostatics - Question 20

A long solid conducting cylinder of radius R carrying volume current along its axis. The magnetic field inside the cylinder is given by (where J0 is a constant and r is the distance from the it axis). The magnetic field at a distance r = 2R from it axis is______ 
(Upto two decimal places)


Detailed Solution for Test: EMT - Magnetostatics - Question 20

We have magnetic field, 
Therefore, the current density corresponding to the magnetic field, 

Therefore, the magnetic field at outside the cylinder

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