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# Test: Electric Field Intensity

## 10 Questions MCQ Test Electromagnetic Theory | Test: Electric Field Intensity

Description
This mock test of Test: Electric Field Intensity for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Electric Field Intensity (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Electric Field Intensity quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Electric Field Intensity exercise for a better result in the exam. You can find other Test: Electric Field Intensity extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

### The electric field intensity is defined as

Solution:

Explanation: The electric field intensity is the force per unit charge on a test charge, i.e, q1 = 1C. E = F/Q = Q/(4∏εr2).

QUESTION: 2

### Find the force on a charge 2C in a field 1V/m.

Solution:

Explanation: Force is the product of charge and electric field.
F = q X E = 2 X 1 = 2 N.

QUESTION: 3

### Find the electric field intensity of two charges 2C and -1C separated by a distance 1m in air.

Solution:

Explanation: F = q1q2/(4∏εor2) = -2 X 9/(10-9 X 12) = -18 X 109
E = F/q = 18 X 109/2 = 9 X 109.

QUESTION: 4

What is the electric field intensity at a distance of 20cm from a charge 2 X 10-6 C in vacuum?

Solution:

Explanation: E = Q/ (4∏εor2)
= (2 X 10-6)/(4∏ X εo X 0.22) = 450,000 V/m

QUESTION: 5

Determine the charge that produces an electric field strength of 40 V/cm at a distance of 30cm in vacuum(in 10-8C)

Solution:

Explanation: E = Q/ (4∏εor2)
Q = (4000 X 0.32)/ (9 X 109) = 4 X 10-8 C.

QUESTION: 6

The field intensity of a charge defines the impact of the charge on a test charge placed at a distance. It is maximum at d = 0cm and minimises as d increases. State True/False

Solution:

Explanation: If a test charge +q is situated at a distance r from Q, the test charge will experience a repulsive force directed radially outward from Q. Since electric field is inversely proportional to distance, thus the statement is true.

QUESTION: 7

Electric field of an infinitely long conductor of charge density λ, is given by E = λ/(2πεh).aN. State True/False.

Solution:

Explanation: The electric field intensity of an infinitely long conductor is given by, E = λ/(4πεh).(sin α2 – sin α1)i + (cos α2 + cos α1)j
For an infinitely long conductor, α = 0. E = λ/(4πεh).(cos 0 + cos 0) = λ/(2πεh).aN.

QUESTION: 8

Electric field intensity due to infinite sheet of charge σ is

Solution:

Explanation: E = σ/2ε.(1- cos α), where α = h/(√(h2+a2))
Here, h is the distance of the sheet from point P and a is the radius of the sheet. For infinite sheet, α = 90. Thus E = σ/2ε.

QUESTION: 9

For a test charge placed at infinity, the electric field will be

Solution:

Explanation: E = Q/ (4∏εor2)
When distance d is infinity, the electric field will be zero, E= 0.

QUESTION: 10

In electromagnetic waves, the electric field will be perpendicular to which of the following?

Solution: