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# Test: Electrostatic Energy And Its Properties

## 20 Questions MCQ Test Electromagnetic Theory | Test: Electrostatic Energy And Its Properties

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This mock test of Test: Electrostatic Energy And Its Properties for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 20 Multiple Choice Questions for Electrical Engineering (EE) Test: Electrostatic Energy And Its Properties (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Electrostatic Energy And Its Properties quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Electrostatic Energy And Its Properties exercise for a better result in the exam. You can find other Test: Electrostatic Energy And Its Properties extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

### The electrostatic energy in an electric field does not depend on which of the following?

Solution:

Explanation: The energy in an electric field directly magnitude of charges. Thus electric field and flux density are also dependent. But the applied field affects only the polarisation and it is independent of the energy in the field.

QUESTION: 2

### Calculate the energy in an electric field with flux density 6 units and field intensity of 4 units.

Solution:

Explanation: The energy in an electric field is given by, W = 0.5 x D x E, where D = 6 and E = 4. We get W = 0.5 x 6 x 4 = 12 units.

QUESTION: 3

### Calculate the energy in an electric field with permittivity of 56 and field intensity of 36π(in μJ)

Solution:

Explanation: The energy in an electric field is given by, W = 0.5 x D x E. Since D = εE, we get W = 0.5 x ε x E2. On substituting the data, we get 3.16 microjoule.

QUESTION: 4

Equipotential surface is a

Solution:

Explanation: Equipotential surface is an imaginary surface in an electric field of a given charge distribution in which all the points on the surface are at the same electric potential.

QUESTION: 5

The work done in moving a test charge from one point to another in an equipotential surface is zero. State True/False.

Solution:

Explanation: Since the electric potential in the equipotential surface is the same, the work done will be zero.

QUESTION: 6

When curl of a path is zero, the field is said to be conservative. State True/False.

Solution:

Explanation: By Stoke’s theorem, when curl of a path becomes zero, then
∫ E.dl = 0. In other words the work done in a closed path will always be zero. Fields having this property is called conservative or lamellar fields.

QUESTION: 7

If the electric potential is given, which of the following cannot be calculated?

Solution:

Explanation: Using potential, we can calculate electric field directly by gradient operation. From E, the flux density D can also be calculated. Thus it is not possible to calculate energy directly from potential.

QUESTION: 8

Superconductors exhibit which of the following properties?

Solution:

Explanation: Since superconductors have very good conductivity at low temperatures (σ->∞), they have nearly zero resistivity and exhibit perfect diamagnetism.

QUESTION: 9

Debye is the unit used to measure

Solution:

Explanation: Debye is the standard unit for measurement of electric dipole moment. 1 Debye = 3.336 x 10-30 Coulomb-meter.

QUESTION: 10

Ceramic materials possess which of the following properties?

Solution:

Explanation: Ceramic materials are generally brittle. Since these materials are used in capacitors, they have higher dielectric constant than polymer. With respect to energy, they possess high electrostatic energy due to very high dielectric constant (W α ε).

QUESTION: 11

The permittivity is also called

Solution:

Explanation: The term permittivity or dielectric constant is the measurement of electrostatic energy stored within it and therefore depends on the material.

QUESTION: 12

Dielectric constant will be high in

Solution:

Explanation: Materials that have very less conductivity like ceramics, plastics have higher dielectric constants. Due to their low conductivity, the dielectric materials are said to be good insulators.

QUESTION: 13

Under the influence of electric field, the dielectric materials will get charged instantaneously. State True/False.

Solution:

Explanation: The dielectrics have the ability of storing energy easily when an electric field is applied as their permittivity is relatively higher than any other materials.

QUESTION: 14

Insulators perform which of the following functions?

Solution:

Explanation: Insulators is a non-conducting material which prevents the leakage of electric current in unwanted directions. Thus it is used to provide electrical insulation.

QUESTION: 15

Which of the following properties distinguish a material as conductor, insulator and semiconductor?

Solution:

Explanation: The only parameter that classifies the material as conductor or insulator or semiconductor is the band gap energy. It is the energy required to make the electrons conduct. This is low of conductors, average for semiconductors and very high for insulators. This means it requires very high energy to make an insulator conduct.

QUESTION: 16

Semiconductors possess which type of bonding?

Solution:

Explanation: Conductors exhibit metallic bonding. Insulators exhibit ionic bonding and semiconductors exhibit covalent bonding due to sharing of atoms.

QUESTION: 17

Find the susceptibility of a material whose dielectric constant is 2.26.

Solution:

Explanation: Electric susceptibility is the measure of ability of the material to get polarised. It is given by, χe = εr – 1.Thus we get 1.26.

QUESTION: 18

The bound charge density and free charge density are 12 and 6 units respectively. Calculate the susceptibility.

Solution:

Explanation: The electric susceptibility is given by, χe = Bound free density/Free charge density. χe = 12/6 = 2. It has no unit.

QUESTION: 19

The susceptibility of free space is

Solution:

Explanation: For free space/air, the relative permittivity is unity i.e, εr = 1. Thus χe = εr – 1 = 0. The susceptibility will become zero in air.

QUESTION: 20

When the electric field becomes zero, which of the following relations hold good?

Solution: