Test: Electrostatics

# Test: Electrostatics

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## 10 Questions MCQ Test Topicwise Question Bank for Electrical Engineering | Test: Electrostatics

Test: Electrostatics for Electrical Engineering (EE) 2022 is part of Topicwise Question Bank for Electrical Engineering preparation. The Test: Electrostatics questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Electrostatics MCQs are made for Electrical Engineering (EE) 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Electrostatics below.
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Test: Electrostatics - Question 1

### What is the ratio of electrostatic repulsion and gravitational attraction between two electrons? Given: Q = Charge on an electron = 1.6 x 10-19C G = Gravitation constant = 6.67 x 10-11 Nm2/kg2 m = Mass of an electron = 9.1 x 10-31 kg

Detailed Solution for Test: Electrostatics - Question 1

By columb’s law,

Also, by Newton's law of gravitation,

Test: Electrostatics - Question 2

### What is the electric field strength at a distance of 200 mm from a charge of 2 x 10-6 Coulomb, in vacuum?

Detailed Solution for Test: Electrostatics - Question 2

Test: Electrostatics - Question 3

### Two point charges of 3 x 10-9 C and -2 x 10-9C are spaced two meters apart. What is the electric field at a point which is one meter from each of the two point charges?

Detailed Solution for Test: Electrostatics - Question 3

Test: Electrostatics - Question 4

Five equal point charges of Q = 20 x 10-9C, are placed at x = 2,3,4,5 and 6 cm. The electric potential at origin will be

Detailed Solution for Test: Electrostatics - Question 4

Electric potential at origin is given as

Test: Electrostatics - Question 5

What is the equivalent capacitance of a parallel plate capacitor having two dielectrics, ∈r1 = 1.5 and ∈r2 = 3.5, each comprising one-half the volume as shown in figure below with A = 2 m2 and d = 1 mm?

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Test: Electrostatics - Question 6

Four point charges 1, - 2, -3 and 4 μC are located on the x-axis at x = 1, 2, 3 and 4 metre respectively. The energy stored in the field is

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Test: Electrostatics - Question 7

The electric field strength at a point in front of an infinite sheet of charge is

Detailed Solution for Test: Electrostatics - Question 7

The electric field strength at a point in front of an infinite sheet of charge is given by

where, ρs = charge density and
= unit vector normal to the sheet and directed away from the sheet.
Here, is independent of the distance of the point from the sheet.

Test: Electrostatics - Question 8

Assertion (A): If all the points in space which have the same potential are jointed, then equipotential surfaces are obtained.
Reason (R): The field and the equipotential surfaces are orthogonal to each other.

Detailed Solution for Test: Electrostatics - Question 8

Both assertion and reason are individually true. However, the correct reason for assertion is that equipotential surfaces are those on which the potential is everywhere the same. Thus, if all the points in space which have the same potential are joined, then equipotential surfaces are obtained.

Test: Electrostatics - Question 9

Consider the following statements associated with various medias encountered in electostatics:
1. An isotropic media is one whose properties are independent of direction
2. A homogeneous media is one whose physical characteristics vary from point-to- point.
3. A non-homogenous media is one whose physical characteristics do not vary from point-to-point:
4. A linear media is a one in which the electric flux density is proportional to the electric field intensity.

Which of the above statements are correct?

Detailed Solution for Test: Electrostatics - Question 9

Statements 2 and 3 are not correct because a homogenous media is one whose physical characteristics do not vary from point-to-point while a non-homogeneous media is one whose physical characteristics vary from point-to-point.

Test: Electrostatics - Question 10

Assertion (A): Continuity of current equation is derived from law of conservation of charge.
Reason (R): Continuity of current equation states that there can be no accumulation of charge at any point.

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