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Year 11 Exam  >  Year 11 Tests  >  Physics for GCSE/IGCSE  >  Test: Energy, Work & Power - Year 11 MCQ

Test: Energy, Work & Power - Year 11 MCQ


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10 Questions MCQ Test Physics for GCSE/IGCSE - Test: Energy, Work & Power

Test: Energy, Work & Power for Year 11 2024 is part of Physics for GCSE/IGCSE preparation. The Test: Energy, Work & Power questions and answers have been prepared according to the Year 11 exam syllabus.The Test: Energy, Work & Power MCQs are made for Year 11 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Energy, Work & Power below.
Solutions of Test: Energy, Work & Power questions in English are available as part of our Physics for GCSE/IGCSE for Year 11 & Test: Energy, Work & Power solutions in Hindi for Physics for GCSE/IGCSE course. Download more important topics, notes, lectures and mock test series for Year 11 Exam by signing up for free. Attempt Test: Energy, Work & Power | 10 questions in 20 minutes | Mock test for Year 11 preparation | Free important questions MCQ to study Physics for GCSE/IGCSE for Year 11 Exam | Download free PDF with solutions
Test: Energy, Work & Power - Question 1
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What is the efficiency of a solar cell if 1000 J of solar energy hits the cell and 200 J are converted into electrical energy?

Detailed Solution for Test: Energy, Work & Power - Question 1
200 divided by 1000 then multiplied by 100 to convert into a percentage
Test: Energy, Work & Power - Question 2
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What is electrical energy converted into when a drill is used?

Detailed Solution for Test: Energy, Work & Power - Question 2
It is the kinetic energy that is useful
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Test: Energy, Work & Power - Question 3
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An old boiler system is replaced with a solar heating system. The old boiler cost £250 per year to run. The new solar heating system costs £0 to run but cost £2,000 to install. How long will it take to start saving money?

Detailed Solution for Test: Energy, Work & Power - Question 3
The solar water heating system saves £250 per year so dividing the cost of installation by the savings each year leads you to the correct answer
Test: Energy, Work & Power - Question 4
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Electrical energy in a kettle changes to what type(s) of energy?
Detailed Solution for Test: Energy, Work & Power - Question 4
Whilst heat is the predominant output of energy transfer, sound and light are given off as wasted energy. It could be argued that the light is actually useful as it lets you see that the electricity to the kettle is switched on but it is generally regarded as wasted since it isn't involved directly in boiling the water
Test: Energy, Work & Power - Question 5
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Electrical energy in a TV changes to what type(s) of energy?
Detailed Solution for Test: Energy, Work & Power - Question 5
The TV also emits the same types of energy transfers, however they are in a different proportion with light and sound being the dominant transfers
Test: Energy, Work & Power - Question 6
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An energy saving bulb replaces a 60 W lamp which cost £4.65 each year to run and 20p to buy. The new low energy bulb costs just £2 per year to run and 65p to buy. How long will it take to start saving money on the running costs due to the change?
Detailed Solution for Test: Energy, Work & Power - Question 6
The 60 W lamp costs just under 39p per month to run, the energy saving bulb costs just under 17p per month to run. By the end of 3 months, the 60W bulb will have cost about £1.37 to buy and run but the energy saving bulb has cost £1.26 to buy and run so from late on in the third month, money is saved. The closest answer to this is 4 months, therefore that is the correct choice
Test: Energy, Work & Power - Question 7
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What would be a good idea to save energy and money?
Detailed Solution for Test: Energy, Work & Power - Question 7
Performing all of the steps above may cost a lot in the short term, however the long term benefits of implementing such a plan would help to reduce your yearly bills and help the environment too!
Test: Energy, Work & Power - Question 8
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A car engine produces 5000 W of power while traveling at a constant speed of 20 m/s. What is the driving force exerted by the engine?
Detailed Solution for Test: Energy, Work & Power - Question 8

Power (P) = Force × Velocity
Given: Power (P) = 5000 W
Velocity (v) = 20 m/s

To find the force (F): P = F × v 5000 W = F × 20 m/s

F = 5000 W / 20 m/s
 F = 250 N

Test: Energy, Work & Power - Question 9
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A pulley system lifts a load of 500 N to a height of 10 meters in 20 seconds. Calculate the power input to the pulley system.
Detailed Solution for Test: Energy, Work & Power - Question 9

Power (P) = Work done / Time taken

First, calculate the work done by the pulley system:
Work done = Force × Distance = 500 N × 10 m = 5000 J

Now, calculate power:
Power (P) = Work done / Time taken
P = 5000 J / 20 s = 250 W

Test: Energy, Work & Power - Question 10
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A wind turbine converts 3000 J of wind energy into 1500 J of electrical energy. What is the efficiency of the wind turbine?
Detailed Solution for Test: Energy, Work & Power - Question 10

Efficiency = (Useful output energy / Input energy) × 100

Given: Useful output energy (electrical energy) = 1500 J
Input energy (wind energy) = 3000 J

Efficiency = (1500 J / 3000 J) × 100 = 50%

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