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# Test: Engineering Mathematics- 4

## 10 Questions MCQ Test RRB JE for Computer Science Engineering | Test: Engineering Mathematics- 4

Description
This mock test of Test: Engineering Mathematics- 4 for Computer Science Engineering (CSE) helps you for every Computer Science Engineering (CSE) entrance exam. This contains 10 Multiple Choice Questions for Computer Science Engineering (CSE) Test: Engineering Mathematics- 4 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Engineering Mathematics- 4 quiz give you a good mix of easy questions and tough questions. Computer Science Engineering (CSE) students definitely take this Test: Engineering Mathematics- 4 exercise for a better result in the exam. You can find other Test: Engineering Mathematics- 4 extra questions, long questions & short questions for Computer Science Engineering (CSE) on EduRev as well by searching above.
QUESTION: 1

### Find

Solution:

Since the limit from the left does not equal to the limit from the right. So limit does not exist.

QUESTION: 2

### If f(x) is continuous at x = 0 where then what is the value of k?

Solution:

Since given function is continuous at x = 0

Alternate method:

0/0 form using L Hospital’s

QUESTION: 3

### If f(x) is continuous at x = 0 where then what is the value of k?

Solution:

f(x) is continuous at x = 0

By definition of logarithm

k ≠ -4

∴ k = 4

Alternate method using L Hospital's

2logk = log (16)

2logk = 2log (4)

∴ k = 4

*Answer can only contain numeric values
QUESTION: 4

The value of   will be ______

Solution:

= 1

QUESTION: 5

The value of

Solution:

QUESTION: 6

The value of

Solution:

Applying L-Hospital Rule

Since the limit is of the form 0/0

Therefore,

*Answer can only contain numeric values
QUESTION: 7

If  Find ln p

Solution:

Concept:

QUESTION: 8

Find the value for

Solution:

Alternate method: Using L Hospital’s

QUESTION: 9

What is the value of f(x) =

Solution:

QUESTION: 10

Find the value of

Solution:

Substituting x = ∞

It is of the form 1