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= x – 2 tan –1 (x/2)+ C
If x = 1 and x = 2 are extreme points of f(x) = a log x + βx^{2} + x then
(f'(x)) = 0
a/x + 2bx +1= 0
at x=1, a  2b + 1 = 0
a + 2b = 1 ..........(1)
At x=2, a/2 + 4b + 1 = 0
a + 8b = 2 ..........(2)
subtracting (1) & (2), b=1/2
=> a=2
= 0  1 =  1
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149 docs215 tests









