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= x – 2 tan –1 (x/2)+ C
If x = -1 and x = 2 are extreme points of f(x) = a log |x| + βx2 + x then
(f'(x)) = 0
a/x + 2bx +1= 0
at x=-1, -a - 2b + 1 = 0
a + 2b = 1 ..........(1)
At x=2, a/2 + 4b + 1 = 0
a + 8b = -2 ..........(2)
subtracting (1) & (2), b=-1/2
=> a=2
= 0 - 1 = - 1
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149 docs|215 tests
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