Test: Enginering Mathematics - 1


15 Questions MCQ Test GATE ECE (Electronics) 2022 Mock Test Series | Test: Enginering Mathematics - 1


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This mock test of Test: Enginering Mathematics - 1 for Electronics and Communication Engineering (ECE) helps you for every Electronics and Communication Engineering (ECE) entrance exam. This contains 15 Multiple Choice Questions for Electronics and Communication Engineering (ECE) Test: Enginering Mathematics - 1 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Enginering Mathematics - 1 quiz give you a good mix of easy questions and tough questions. Electronics and Communication Engineering (ECE) students definitely take this Test: Enginering Mathematics - 1 exercise for a better result in the exam. You can find other Test: Enginering Mathematics - 1 extra questions, long questions & short questions for Electronics and Communication Engineering (ECE) on EduRev as well by searching above.
QUESTION: 1

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QUESTION: 2

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QUESTION: 3

The order of differential equation 

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QUESTION: 4

The order of differential equation  

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QUESTION: 5

Find the rank of matrix 

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QUESTION: 6

The rank of Diag matrix  [− 1 0 1 0 0 4] is ________

Solution:
QUESTION: 7

  the third row of R-1 is 

Solution:
QUESTION: 8

For what value of k will the matrix given below become singular 

is ___________

Solution:

Correct Answer :- B

Explanation:- If the matrix is singular, its determinant has to be zero.

[8(0-12) -4(4k-24) +0(24-0)] = 0

-96 -16k +96 = 0

-16k = 0

k = 0

 

 

QUESTION: 9

The Eigen values of the matrix 

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QUESTION: 10

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QUESTION: 11

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QUESTION: 12

   then find 

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QUESTION: 13

 Given system of linear equations

3x + 2y + z = 0, x + 4y + z = 0, 2x + y + 4z = 0, has 

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QUESTION: 14

Suppose that the probability of event A is 0.2 and the probability of event B is 0.4. Also, suppose that the two events are independent. Then P(A|B) is:

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QUESTION: 15

The Newton-Raphson method formula for finding the square root of a real number R from the equation x2 − R = 0 is

Solution:

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