Which of the following statements is correct?
Find the number of multiples of 5.
How many prime numbers are there "between 1 to 100"?
Prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 = 25
Which of the following is a perfect square?
25 is the perfect square of 5. rest all options are not perfect squares of any natural number.
What is the HCF of two prime numbers?
What is the LCM of 36, 75 and 80?
LCM = 2×3×5×2×3×5×4 = 3600
Product of two numbers = ___________
The sum of the factors of 25 is
Factors of = 25 = 52 are 1, 5, 25 which can also be represented as: 52 = (2+1) = 3 (i.e.3 factors)
A number is divisible by 24 if ___________
It is divisible by 8 & 3 because 8 and 3are co-prime
Prime factorization of 512 × 343
512×343 =
2×2×2×2×2×2×2×2×2×7×7×7=29 x 73
Determine the number nearest to 100000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21?
Reminder= 40 84040=800 100000+800=100800
182/195 when reduced to the lowest term is
Which of the following pair is co-prime?
HCF of 81 and 135 = 27 HCF of 87 and 116 = 29 HCF of 43 and 73 = 1 HCF of 26 and 65 = 13 Hence, 43 and 73 are co-prime
Find the number of factors of 1024
1024=210=2n
⇒ (n+1) = (10+1) = 11.
Where (n+1) = no. of factors. Here factors will be 1, 2, 4, 8, 16?????.1024.
If the 8-digit number 136y5785 is divisible by 15, then find the least possible value of
136Y5785
For 15, No. should be divisible by 5, 3
No. is already divisible by 5 1 + 3 + 6 + 5 + 7 + 8 + 5 + y = 35 + y
∴y=1
Find the smallest number which when divided by 25, 40 and 60 leaves remainder 7 in each case?
5×4×5×2×3=600
Required numbers is 600+7=607
x, y, z, w are four odd natural numbers. Let u=x2+y2+z2+w2. Consider following statements
I. U is always divisible by 4
II. U is never divisible by 8
Q. Which of the above statements) is /are true?
2211/5025 , which reduced to its simplest form. By dividing the numerator and denominator
A boy saves Rs. 4.65 daily. Find the least number of days in which he will be to save an exact number (whole number) of rupees.
Rs. 4.65 = 465 paise
The exact number of rupees will be a multiple of 100
So, we have to fine the L.C.M. of 465 and 100
100 = 2*2*5*5
465 = 3*5*31
L.C.M. of 465 and 100 = 2*2*3*5*5*31
= 9300
So, the boy saves 9300 paise
Hence, least number of days required to save 9300 paise = 9300/465
= 20 days
H.C.F of two numbers is 16, then their LCM is
H.C.F is always a factor of L.C.M. In this case 16 Divides 192 only.
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