Test: Factors and Multiples- 2
10 Questions MCQ Test Mathematics for Class 4 | Test: Factors and Multiples- 2
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You are thinking of a number that is a multiple of 7 and 12. What is the smallest number that you can think of?
Multiples of 7: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91.......
Multiples of 12: 12, 24, 36, 48, 60, 72, 84, 96.....
Smallest number is 84 because 84 is minimum common multiple of 7 and 12.
What is the greatest length that is used to measure 8 m, 6 m and 14 m exactly?
8 = 2 × 2 × 2
6 = 2 × 3
14 = 2 × 7
Maximum length be 2m.
Which of the following numbers has the least number of factors?
The factors of 106 are 1, 2, 53 and 106.
The factors of 78 are 1, 2, 3, 6, 13, 26, 39 and 78.
The factors of 110 are 1, 2, 5, 10, 11, 22, 55, and 110.
The factors of 66 are 1, 2, 3, 6, 11, 22, 33 and 66.
Read the statement carefully and choose the correct option with true/false.
A. 6 is multiple of 18.
B. 24 is a multiple of 3
C. 5 is factor of 20.
D. 88 is factor of 4.
6 is a factor of 18 and 88 is multiple of 4.
From the list given below find how many numbers are factors of 125?
2, 3, 5, 7, 25, 50, 100
5 and 25 are factors of 125.
Hence, only two numbers are factors of 125 from the given list.
From the list given below find how many of the numbers are multiples of 20?
12, 25, 40, 36, 80, 100, 110, 150
40, 80 and 100 are multiples of 20.
Hence, we have only three numbers are multiples of 20 from the given list.
Three alarm clocks ring the alarm at 3, 6 and 9 minutes respectively. In 60 minutes how many times will the clocks ring together?
Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27.....
Multiples of 6: 6, 12, 18, 24, 30.....
Multiples of 9: 9, 18, 27.....
The clocks ring in every 18 minutes together.
1st time the clock will ring in 18 minutes, then at 36 minutes and then at 54 minutes.
So in 60 minutes the clocks will ring 3 times.
I am multiple of 23. I am odd number and have 3 digits. I am also a multiple of 7. Who am I?
23 × 7 = 161.
The teacher gave 12 books a group of children and asked them to arrange them in different groups under some conditions like
(A) Each group should have the same number of books.
(B) No of books should be left over.
(C) Each grouping should be different from the other.
This activity will help the children to understand the concept of
Given activity is helpful to understand multiples and factors because 12 books can be arranged in groups having 1, 2, 3, A, 6 and 12 books in each group.
All the multiples of 3, except 3, all the multiples of 5, except 5 and all the multiples of 7, except 7 are
Composite numbers: Numbers having three or more than 3 factors are called composite numbers.
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