Test: Fluid Pressure - Mechanical Engineering MCQ

The Pascal law states that the liquid at rest applies pressure at a point is same in all directions. This means that the pressure is there in spite of the direction. And it is present in the same direction and is having same magnitude.

The Pascal law states that the liquid at rest applies pressure at a point is same in all directions. This means that the pressure is there in spite of the direction. And it is present in the same direction and is having same magnitude.

The Pascal law states that the liquid at rest applies pressure at a point is same in all directions. This means that the pressure is there in spite of the direction. And it is present in the same direction and is having same magnitude.

The liquid must be incompressible. The Pascal law states that the liquid at rest applies pressure at a point is same in all directions. This means that the pressure is there in spite of the direction.

The liquid must be incompressible. The Pascal law states that the liquid at rest applies pressure at a point is same in all directions. This means that the pressure is there in spite of the direction. But the gases are compressive that’s why it is not used in the gas form.

The pressure is always acted normal to the surface of the body. Thus the pressure plays a role as a vector in this case. So mainly the pressure must be considered as normal to the surface of the body.

The body used in the determination of the fluid pressure equations is immersed in the liquid. It is completely immersed in the liquid. So as to make the calculations of the pressure beneath the liquid.

The force system having all the forces emerging from a point is called the collinear system of force. This is a type of system of the force, which is easy in the simplification. This is because as the forces are the vector quantity, the vector math is applied and the simplification is done.

The simplification is easy. The simplified force system gives us a net force and the parallel force system gives us a simplified force, and then we add it vectorially. Thus the vector addition at the last can be easily done and thus both can be simplified.

For the equilibrium in the three dimensional system of axis we have all the conditions true as, ∑Fx=0, ∑Fy=0 and ∑Fz=0. Also we have the summation of the forces equal to zero. Which is not a non-zero value.

The answer is obviously yes. If we are having any difficulty in making the vector components, then we can go in 2D. As if the particle is in equilibrium, the net force will be zero. No matter where you see first. Net force is zero.

Yes, we equate all the components of the three axis equal to zero. That is the resultant of the forces along the three axis are being equated to zero. This brings in that there is no net force along any direction. Hence equilibrium.

We first make the free body diagram and then we make the equilibrium equations to satisfy the given conditions. This helps us to solve the question easily. As this reduces the part of imagination and increases accuracy too.

The answer is false as the equations asked are scalars. As we make the net sum of the forces along the axis equal to zero. Of course this equation comes from the solving the vector forms, but still the result is a scalar, hence the equations are scalar.

The Pascal law states that the liquid at rest applies pressure at a point is same in all directions. This means that the pressure is there in spite of the direction. And it is present in the same direction and is having same magnitude.